Cathy volunteered to collect cans for a school project. cathy collected 125 cans in 5 days. there were 6 volunteers including cathy who each collected about the same number of cans. about how many cans did they collect ?

Answers

Answer 1

Answer: Everyone got 4 cans a day but one person got 5 cans everyday. How? 125/5, cans collect/number of day equals 25 cans a day if you divide by 6 you get 4.1 and they can't collect a fraction of a can so then you do 6*4=24 but you need 25 a day so one of the people got an extra can.

Answer 2

Answer:

Answer: They collected 750 cans.

Step-by-step explanation:

Hi, to answer this question we have to analyze the information given:

Number of cans collected by Cathy: 125
Number of volunteers (including Cathy) : 6

So, calculate the total number of can that all the volunteers collected we have to simply multiply the number of cans that Cathy collected (125 ,Since each volunteer collected about the same number of cans) by the number of volunteers (6 including Cathy).

125 x 6 = 750 cans.

Feel free to ask for more if needed or if you did not understand something.

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Write an equation in slope-intercept form of the line that passes through the given point and is parallel to the graph of the given equation.(-3,-3);y=-3x-2 y=−3x+2
Write an equation for the line in slope-intercept form.

Answers

Answer:

y = –3x – 6

Step-by-step explanation:

We'll begin by obtaining the slope of the equation y = –3x – 2.

This can be obtained by comparing

y = –3x – 2 with y = mx + c

Thus, the slope (m) of the equation

y = –3x – 2 is –3.

Next, we shall determine the slope of the equation parallel to line with equation y = –3x – 2.

This is illustrated below:

For parallel lines, the slope are related as follow:

m1 = m2

m1 = –3

m2 = m1 = –3.

Finally, we shall determine the equation as follow:

Coordinate = (–3, –3)

x1 coordinate = –3

y1 coordinate = –3

Slope (m) = –3

y –y1 = m(x – x1)

y – (–3) = –3 (x – (–3))

y + 3 = –3 (x + 3)

y + 3 = –3x – 3

Rearrange

y = –3x – 3 – 3

y = –3x – 6

Thus, the equation parallel to the line is y = –3x – 6

What is the average of the integers of 25 to 41

Answers

$a_v=(25+26+27+....+41)/(17)=(561)/(17)=33$

Factor completely. n ^4 - 1

Answers

Answer: Hello there!

here we have the equation n^4 - 1

using the relation: $(a^(2) - b^(2)) = (a+b)*(a-b)$

we can write our equation as:

$(n^(4) - 1) = ((n^(2) )^(2) -1^(2) ) = (n^(2) + 1)(n^(2) - 1) = (n^(2) + 1)(n + 1)(n-1)$

and (n^2 + 1) has only complex roots, i and - i, then we can factorize this as (n -i)(n + i) = n*n + ni - ni (+i)*(-i) = (n^2 + 1)

then our equation is: $(n^(2) + 1)(n + 1)(n-1) = (n + i)(n - i)(n + 1)(n-1)$

(n^4 - 1) = (n^2 - 1) (n^2 +1) = (n - 1) (n + 1) (n^2 + 1)

An investment of $2000 in a bank account doubles every five years. The function that models the growth of this investment is f(x)=2000•2^x, where x is the number of doubling periods, or 10 years?

Answers

x=1 after the first 5 years;
x=2 after the another 5 years (or better said after the first 10 years in the bank);
x=3 after another 5 years ( or better said after the first 15 years in the bank)
and so on...

x is the number of 5 years intervals which have passed up to a moment in time :)

Answer:

4150

Step-by-step explanation:

A machinist can produce 114 parts in 6 mins.At this rate,how many parts can the machinist produce in 15 mins

Answers

$114\ parts\ in\ 6\ min\n\nx\ parts\ in\ 15\ min\n\nmaking\ proportion:\n114-6\nx-15\n\ncross\ multiplication\n\n114*15=6x\n\n1710=6x\ \ \ \ | divide\ by\ 6\n\nx=285\n\n285\ parts\ can\ be\ produced\ in\ 15min$

Answer:

thx for points

Step-by-step explanation:

hehe

(2×² -×³-18×²-7÷(×+2)
i need solution and explanation

Answers

$▪▪▪▪▪▪▪▪▪▪▪▪▪ {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪$

The quotient is equal to :

$- {x}^(2) - 14x + 28$

remainder :

$- 63$

Solution is in attachment ~

Answer:

${ \rm{( {2x}^(2) - {x}^(3) - 18 {x}^(2) - 7) / (x + 2) }}$

• now, (x + 2) is the factor.

• let's find the value of xfrom the factor:

${ \rm{x + 2 = 0}} \n { \underline{ \rm{ \: \: x = - 2 \: \: }}}$

• let's substitute for xinto the quotient:

${ \rm{f(x) = {2x}^(2) - {x}^(3) - {18x}^(2) - 7 }} \n \n { \rm{f( - 2) = 2 {( - 2)}^(2) - {( - 2)}^(3) - 18 {( - 2)}^(2) - 7 }} \n \n { \rm{f( - 2) = 8 +8 - 72 - 7}} \n \n { \boxed{ \boxed{ \pmb{answer \: \dashrightarrow \: \: {}^( - ) 63 \: \: }}}}$

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