MATHEMATICS HIGH SCHOOL

Solve
tan x + 1 = 0
for x.

Answers

Answer 1
Answer: tan x  + 1 = 0
tan x + 1 - 1 = 0 - 1
tan x = - 1
We will use the unit circle:
tan ( - 45° ) = - 1
tan ( - π / 4 ) = - 1
Answer:
x = - π / 4 + n π,   n ∈ Z

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Simplify 24pn/18p^2 please and thank you

Answers

2np/27 is the simplified version of this question.

Good luck!

24pn/18p²

= 24np/18p²

= 24n/18p

= 4n/3p


I hope that's help;0

8 ( x+ 7 ) = - 24 solve for x

Answers

Answer:

21

Step-by-step explanation:

Nells mortgage is 50,150 at 10 percent for 30 years. What is her monthly payment if she must pay 8.78 points per 1,000?A.) 440.32
B.) 439
C.) 422.95
D.) 385.89

Answers

I think it the answer is A.) 440.32

50,150 / 1,000 = 50.15 
50.15 x 8.78 = 440.317 or 440.32

Help merrereeeeeeeerreer

Answers

Answer: -216

Step-by-step explanation:

Of 10 students surveyed in a school , 7 picked Summer as their favorite season. If the school has 350 students. How many can be expected to perfer summer?

Answers

Answer:

The expected number of students to prefer summer=245

Step-by-step explanation:

Step 1

Determine the number of students that prefer summer as their favorite season, and the sample size

number that prefer summer=7

sample size=10

Step 2

Determine the probability of a student picking summer as their favorite season as shown;

Probability=number that prefer summer/sample size

Probability=7/10=0.7

Step 3

Determine the total number of students out of the total population that can be expected to prefer summer as follows;

Expected number of students=probability×total number of students

where;

probability=0.7

total number of students=350

replacing;

Expected number of students=(0.7×350)=245

The expected number of students to prefer summer=245

Which of the solution sets is all real numbers?
|x| < -1
|x| = -1
|x| > -1

Answers

Answer:

The solution sets is all real numbers in case of:

                        |x| > -1

Step-by-step explanation:

We know that modulus is a function with the property such that:

                      if a<0 then |a|= -a

that is the modulus of a negative number is positive and if a≥0

                                then |a| =a

and modulus of a positive value is also positive.

i.e. modulus function always gives positive value.

Hence,

1)

|x|<-1

This is not possible as modulus function always gives a value ≥0 for all real numbers.

2)

|x|= -1

This is also not possible as modulus of any number can't be negative.

3)

|x| > -1

The modulus of any number will definitely be greater than or equal to zero.

    Hence, the solution set contain all the real numbers.
The last one is all real number
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