List the following in smallest to largest:-Glucose
-Carbonic Acid
-Hydrogen Gas
-Atom
-Proton
-Sodium Chloride
-Triglyceride
-Electron
-Protein
-Amino Acid

Answers

Answer 1
Answer: Here you are! The correct sequence is being shown below : 

- Electron
 - Proton
 - Atom
 - Hydrogen Gas
- Amino Acid
 - Glucose
 -Triglyceride
 - Sodium Chloride
 - Carbonic Acid
 - Protein

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In a laboratory investigation, magnesium reacts with hydrochloric acid to produce hydrogen gas and magnesium chloride. This reaction is represented by the unbalanced equation below.Mg(s) + HCl(aq) ==>H2(g) + MgCl2(aq)State, in terms of the relative activity of elements, why this reaction is spontaneous.
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What is the result of adding KF to an equilibrium mixture of the weak acid HF?HF(aq)⇔H+(aq)+F-(aq).

a. F- concentration decreases
b.the dissociation constant, K, increases
c. HF concentration decreases
d. H+ concentration decreases

Answers

When gaseous hydrogen chloride is passed through a sodium chloride solution, precipitation of the sodium chloride occurs as a result of an excess of chloride ions in the solution (caused by the dissociation of HCl). Here the concentration of H⁺ decreases. The correct option is D.

What is common-ion effect?

When another electrolyte (which includes an ion that is also present in the first electrolyte, i.e., a common ion) is added, the common ion effect suppresses the ionisation of the first electrolyte. It is thought to be a result of Le Chatlier's principle, often known as the equilibrium law.

An increase in the concentration of one of the ions dissociated in the solution by the addition of another species containing the same ion will result in an increase in the degree of association of ions in a solution where there are several species associating with each other via a chemical equilibrium process.

Here the common ion 'F' in KF supresses the dissociation of HF.

Thus the correct option is D.

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Answer D. Follow Le Chatelier's principle.

Yesterday we combined Hydrochloric Acid HCl with Sodium Hydroxide NaOH in a violent reaction that resulted in water H2O and common table salt NaCl. How many grams of hydrochloric acid should we use so we have exactly enough to react with 40g of sodium hydroxide? You'll need to write a chemical reaction, balance it, and then perform your calculation. 

also how many grams of salt NaCl will be produced and how many grams of water H2O be produced? 

Answers

HCl + NaOH ---> NaCl + H2O                  

                                                        1 mol HCl = 1 mol NaOH 

mole HCl = 36.5 g // mole HaOH = 40 g


36.5 HCl is the answer.



mole NaCl = 58,5 g // mole H2O = 18g 


HCl (36,5 g) ⇒ NaCl (58,5 g)
HCl (36,5 g) ⇒ H2O (18 g)

So, 58,5 g NaCl and 18 g H2O are the answer.
Reaction:
HCl + NaOH ---> NaCl + H2O

1 mole of HCl = 36,5 g
1 mole of NaOH = 40g

so, according to the reaction:
1 mol HCl = 1 mol NaOH
so, we need > 36,5 g HCl (hydrochloric acid)

answer: 36,5 g HCl (hydrochloric acid)
 ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~
next question.

1 mole of NaCl = 58,5 g
1 mole of H2O = 18g

so, according to the reaction:
1 mole of HCl (36,5 g) ----------------- - 1 mole of NaCl (58,5 g)
(the same for NaOH)
i
1 mole of HCl (36,5 g) ------------------ 1 mole of H2O (18 g)
(the same for NaOH)

so, this reaction is stechiometric

answer: 58,5 g NaCl i 18g H2O

A real gas behaves least like an ideal gas under the conditions of(1) low temperature and low pressure
(2) low temperature and high pressure
(3) high temperature and low pressure
(4) high temperature and high pressure

Answers

The correct answer is option 3. A real gas behaves least like an ideal gas under the conditions of high temperature and low pressure. At this temperature and pressure, the molecules are close to each other and collisions or interactions are very likely to happen which is not an ideal gas.

What is the empirical formula for Hg2(NO3)2

Answers

I think it's HgNO3 because the subscripts on Hg and No3 are divisible by 2  :)

For a given chemical reaction, the addition of a catalyst provides a different pathway that(1) decreases the reaction rate and has a higher activation energy(2) decreases the reaction rate and has a lower activation energy
(3) increases the reaction rate and has a higher activation energy
(4) increases the reaction rate and has a lower activation energy

Answers

Answer: Option (4) is the correct answer.

Explanation:

Activation energy is the minimum amount of energy required by the reactants to participate in the chemical reaction.

Therefore, reactant molecules whose energy is less than the activation energy are not able to participate in the reaction. Hence, a catalyst lowers the activation energy so that molecules with less energy can also participate in the reaction.

Thus, a catalyst is a specie that increases the reaction rate and has a lower activation energy.

For a given chemical reaction, the addition of a catalyst provides a different pathway that "(4) increases the reaction rate and has a lower activation energy"

What is the pressure in atm exerted by 2.48 moles of a gas in a 250.0 ml container at 58c?

Answers

Explanation:

The given data is as follows.

     V = 250.0 ml,                  T = 58^{o}C = 58 + 273 = 331 K

      n = 2.48 moles,              P = ?    ,             R = 0.082 atm L /K mol

Therefore, calculate the pressure using ideal gas equation as follows.

                       PV = nRT

                        P = (nRT)/(V)

                            = (2.48 mol * 0.082 atm L/K mol * 331 K)/(250.0 ml)

                            = 0.269 atm

Thus, we can conclude that pressure of the given gas is 0.269 atm.

T = 58 + 273.15 = 331.15

R = 0.082 atm

V = 250.0 mL / 1000 = 0.25 L

P =  n x R x T / V

P = 2.48 x 0.082 x 331.15 / 0.25

P = 67.342 / 0.25

P = 269.368 atm

hope this helps!