In the coordinate plane, three vertices of rectangle MNOP are M(0, 0), N(0, c), and P(d, 0). What are the coordinates of point O?. a.(d, c). b.(2d, 2c). c.(c/2, d/2). d.(c, d)

Answers

Answer 1
Answer: MNOP is a rectangle.
In the coordinate plane, three vertices are: M ( 0, 0 ), N ( 0, c ) and P ( d, 0 ).
The coordinates of point O is:
A ) ( d, c )
Answer 2
Answer:

Answer:

The coordinates of O is (d,c) .

Option (a) is correct .

Step-by-step explanation:

As given

In the coordinate plane, three vertices of rectangle MNOP are M(0, 0), N(0, c), and P(d, 0).

As MNOP is a rectangle .

Thus opposite sides of the rectangles are equal .

Formula

Distance\ formula = \sqrt{(x_(2)-x_(1))^(2)+(y_(2)-y_(1))^(2) }

NM = \sqrt{(0-0)^(2)+(c-0)^(2)}

NM = \sqrt{c^(2)}

NM = c units

MP = \sqrt{(d-0)^(2)+(0-0)^(2)}

MP = \sqrt{d^(2)}

MP = d units

Thus the coordinate of the O (d,c) .

(This is because opposit sides of the rectangle are equal thus distance of point O from point P must be d and distance of point O from point N must be c .)

Therefore the coordinates of O is (d,c) .

Option (a) is correct .





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Answer:

D area

Step-by-step explanation:

1. The length of a swimming pool is 8m longer than its width and the area is 105m2.

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In the diagram, lines l and m are parallel lines cut by transversal line p. (5x-20) 85 what is the value of x ?

Answers

Answer:

The value of x is 23.

Step-by-step explanation:

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Answers

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Find the area and perimeter of an isosceles trapezoid with a 60° base angles and bases 9 and 13.

Answers

The area and perimeter of an isosceles trapezoid with a 60° base angles and bases 9 and 13 is 38.105 squared units and 24 units respectively.

What is area and perimeter of the isosceles trapezoid?

The area of the isosceles trapezoid is the space occupied by it. It can be find out using the following formula,

A=(a+b)/(2)* h

Permiter of the isosceles trapezoid is the total length of the boundary by which it is enclosed. It can given as,

P=a+b+2c

Here (a,b) are the base side (c) is the side of leg and (h) is the height.

The image of the given isosceles trapezoid is attached below. Let the value of leg is x units. Thus using right angle property the cos theta is,

\cos60=(2)/(x)\nx=1

And the height of this trapezoid is,

\tan60(h)/(2)\nh=3.46

Thus the area of the solid is,

A=(9+13)/(2)* 3.46\nA=38.105\rm\; units^2

The perimeter of the solid is,

P=9+13+2*1\nP=24\rm\; units

Thus, the area and perimeter of an isosceles trapezoid with a 60° base angles and bases 9 and 13 is 38.105 squared units and 24 units respectively.

Learn more about the area of the isosceles trapezoid here;

brainly.com/question/436117

The trapezoid has two right triangles each with one side of length (13-9)2 = 4/2 = 2.

The other side of each right triangle is such that tan 60° = Heigth / 2

Then height = 2*tan60°.

The area of the trapezoid is height * (base 1 + base 2)/2

Then area = 2*tan (60°) * (13+9)/2 = 38.11