A family is having a pool built in their backyard. If their yard is rectangular and measures 7x by 6x and the pool is circular with a radius of 2x how much of the yard will be left over after the pool is built?a. 38x2
b. 42x2 – 4x2
c. 42x2 – 2x2
d. 38x2

Answers

Answer 1

Answer: Area of a rectangular yard:
A 1 = L x W = 7 x * 6 x = 42 x²
Area of a pool:
A 2 = r² π = ( 2 x )² π = 4 x² π
A = A 1 - A 2
A = 42 x² - 4 x² π
Answer: B ) 42 x² - 4 x² π

Related Questions

Widget Wonders produces widgets. They have found that the cost, c(x), of making x widgets is a quadratic function in terms of x. The company also discovered that it costs $16 to produce 2 widgets, $18 to produce 4 widgets, and $48 to produce 10 widgets. Find the total cost of producing 8 widgets. Write your answer in quadratic equation.
Find the length x in the triangle. Express your answer in simplified radical form. Side 1=10. Side 2=8. Side 3=x
19/20-3/20 in simplest form
Which number line represents the solution set for this inequality?−9x −12 ≤ 42
At a hot dog stand, they serve regular and footlong hot dogs at a ratio of 3 to 2. Based on this ratio,how many footlong hot dogs will be served if there are a total of 80 hot dogs served

Given the following scenario, decide if it is a permutation or combination. Then calculate the number of possibilities. (Please write Permutation/Combination ; answer)A committee must choose 4 finalists from 15 candidates. How many ways can the committee choose the four finalists.

Answers

The right answer for the question that is being asked and shown above is that:

There are...
15 * 14 * 13 * 12 ways in order to know the four finalists.
This is equal to 32,760 ways i n order to know the four finalists.

in sound and harmonics, the frequency of a vibrating string varies inversely to its length. A guitar string 20 inches long vibrates at a frequency of 400 cycles per second. Find the frequency of a 35- inch string.

Answers

20 inches is 400
10 inches is 200
5 iches is 100

So 20+10+5=35
Which means 400+200+100= 700

So the frequency of a 35 inch string is 700 cycles per second

A distribution is positively skewed if which of these statements is true about the density curve that represents it?A. The left side is a mirror reflection of the right side.
B. The left tail is equal in length to the right tail.
C. The left tail is longer than the right.
D. The right tail is longer than the left.

Answers

The right answer for the question that is being asked and shown above is that: "D. The right tail is longer than the left." Positively skewed distribution is asymmetrical and points in the positive direction. So, the tail on the right is longer than that of the left.

Which property justifies the following statement if a=b then a/d=b/d?

Answers

Division property of equality.

Mark wants to use a grid to model the percent equivalent of the fraction 2/3. How many grid squares should be shade? What percent would his model show?

Answers

Answer:

66 + 1 ( not fully shaded ) squares will be shaded.

66.67% region will be shaded

Step-by-step explanation:

It is given that Marks uses a grid to model percent equivalent of $(2)/(3)$ .

Let us assume that Mark uses a model containing 100 grids.

Now, as the grids are divided into region equivalent to $(2)/(3)$ i.e. it is divided into 3 parts.

Moreover, 2 out of those 3 parts will be shaded.

As, $(2)/(3) =0.6667$

i.e. $(2)/(3)$ =66.67%

So, it gives us that 66 squares in the grid will be fully shaded and one will not be fully shaded.

Hence, 66 + 1 ( not fully shaded ) squares will be shaded and in percent, 66.67% of the region will be shaded.

Final answer:

To represent the fraction 2/3 on a grid, approximately 67% of the squares on the grid should be shaded. This means such a fraction corresponds to 67 out of 100 squares on a 100-square grid or equivalently 67% shaded.

Explanation:

To determine how many grid squares Mark should shade to model the percent equivalent of the fraction 2/3, we need to understand the relationship between fractions, decimals, and percents. When we convert the fraction 2/3 into a decimal, we get approximately 0.67. To represent this as a percent, we multiply by 100, which gives us 67%. So, about 67 out of 100 squares should be shaded.

Let's say Mark's grid has 100 squares (10 rows by 10 columns). In that case, he would shade about 67 squares to represent 2/3 as a percent. If the grid contains fewer than 100 squares, he would need to adjust accordingly.

In summary, the model would show about 67% shaded.