F(x) = 4x - 7 find the range value for a domain value of { -3 }

Answers

Answer 1

Answer: $f(-3)=4\cdot(-3)-7=-12-7=-19$

Related Questions

Maria is selling toys an flowers.The toys cost $12 an the flowers cost $10. She needs to make at least $300.

Answers

Maria needs to sell at last 14 flowers and 14 toys to get $308

I will show you how it works:
x(12+10) = 300 you add 12 and 10 together
x(22) = 300 than 22 times x
22x = 300 now you divide 300 by 22, you will get 13.64, round it, 14
x = 14

Flowers : 10 times 14 = $ 140
Toys : 12 times 14 = $168 Now add them together.
Flowers and Toys = $308

So this is how you get the answer

1,574/18 Long Division Please And Thank You

Answers

87.4
______
18 | 15740
144
--------
134
126
----------
80
72
--------
8
this is gonna just keep repeating....so ur answer is 87.444.....or 87 4/9

Hello there.

1,574/18 Long Division Please And Thank You

87.444

The graph of which function has an axis of symmetry at x =-1/4 ?f(x) = 2x2 + x – 1

f(x) = 2x2 – x + 1

f(x) = x2 + 2x – 1

f(x) = x2 – 2x + 1

Answers

we know that

The equation of the vertical parabola in vertex form is equal to

$y=a(x-h)^(2)+k$

where

(h,k) is the vertex

The axis of symmetry is equal to the x-coordinate of the vertex

$x=h$ ------> axis of symmetry of a vertical parabola

we will determine in each case the axis of symmetry to determine the solution

case A) $f(x)=2x^(2)+x-1$

Convert to vertex form

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$f(x)+1=2x^(2)+x$

Factor the leading coefficient

$f(x)+1=2(x^(2)+0.5x)$

Complete the square. Remember to balance the equation by adding the same constants to each side

$f(x)+1+0.125=2(x^(2)+0.5x+0.0625)$

$f(x)+1.125=2(x^(2)+0.5x+0.0625)$

Rewrite as perfect squares

$f(x)+1.125=2(x+0.25)^(2)$

$f(x)=2(x+0.25)^(2)-1.125$

the vertex is the point $(-0.25,-1.125)$

the axis of symmetry is

$x=-0.25=-(1)/(4)$

therefore

the function $f(x)=2x^(2)+x-1$ has an axis of symmetry at $x=-(1)/(4)$

case B) $f(x)=2x^(2)-x+1$

Convert to vertex form

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$f(x)-1=2x^(2)-x$

Factor the leading coefficient

$f(x)-1=2(x^(2)-0.5x)$

Complete the square. Remember to balance the equation by adding the same constants to each side

$f(x)-1+0.125=2(x^(2)-0.5x+0.0625)$

$f(x)-0.875=2(x^(2)-0.5x+0.0625)$

Rewrite as perfect squares

$f(x)-0.875=2(x-0.25)^(2)$

$f(x)=2(x-0.25)^(2)+0.875$

the vertex is the point $(0.25,0.875)$

the axis of symmetry is

$x=0.25=(1)/(4)$

therefore

the function $f(x)=2x^(2)-x+1$ does not have a symmetry axis in $x=-(1)/(4)$

case C) $f(x)=x^(2)+2x-1$

Convert to vertex form

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$f(x)+1=x^(2)+2x$

Complete the square. Remember to balance the equation by adding the same constants to each side

$f(x)+1+1=x^(2)+2x+1$

$f(x)+2=x^(2)+2x+1$

Rewrite as perfect squares

$f(x)+2=(x+1)^(2)$

$f(x)=(x+1)^(2)-2$

the vertex is the point $(-1,-2)$

the axis of symmetry is

$x=-1$

therefore

the function $f(x)=x^(2)+2x-1$ does not have a symmetry axis in $x=-(1)/(4)$

case D) $f(x)=x^(2)-2x+1$

Convert to vertex form

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$f(x)-1=x^(2)-2x$

Complete the square. Remember to balance the equation by adding the same constants to each side

$f(x)-1+1=x^(2)-2x+1$

$f(x)=x^(2)-2x+1$

Rewrite as perfect squares

$f(x)=(x-1)^(2)$

the vertex is the point $(1,0)$

the axis of symmetry is

$x=1$

therefore

the function $f(x)=x^(2)-2x+1$ does not have a symmetry axis in $x=-(1)/(4)$

the answer is

$f(x)=2x^(2)+x-1$

axis of symmetry is the x value of the vertex

for
y=ax^2+bx+c
x value of vertex=-b/2a

first one
-1/2(2)=-1/4
wow, that is right

answer is first one
f(x)=2x^2+x-1

What is d slope intercept of 11x-8y=-48

Answers

$General\ equation\ for\ line\ in\ slope\ intercept\ form:\n\ny=ax+b\n a-slope\n b-intercept\n\n 11x-8y=-48\ \ \ | subtract\ 11x\n-8y=-11x-48\ \ \ | divide\ by\ -8\n\boxed{y=(11)/(8)x+6}$

Which strategies can be used to solve this problem?The candle factory made 1,200 candles per month in June and July and 1,345 candles per month in August and September. What is the total number of candles they made in four months?
Choose all answers that are correct.

A.Use logical reasoning.
Multiply 1,200 by 2 to figure out how many candles were made in June and July. Multiply 1,345 by 2 to figure out how many candles were made in August and September. Add the two numbers together to find the total number of candles made in four months.
B.Draw a diagram.
Draw two circles. In one circle write 1,200 and in the other circle write 1,345. Add the numbers in the circles together.
C.Work backward.
Divide 1,200 by 2 (for the 2 months, June and July). Then divide 1,345 by 2 (for the 2 months August and September). Add these two numbers.
D.Translate into an equation.
1,200 × 2 + 1,345 × 2 = c

Answers

you want total number made in 4 m onths, so adding all numbers is correct, but it is per 1 month, so multiply by 2

A because you need brain for most problems
D works

pick A and D

Evaluate the related series,of each sequence

-9,-16,-23,-30,-37,-44

Answers

I think its just that the series decreases by 7 from n-1 to n

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