Find the differential of this function. y=tan*sqrt(t)

Answers

Answer 1
Answer: y = tan (√ t )
We will use chain rule.
( tan x ) ` = sec² x
( √ t ) ` = 1 / 2√t
y ` = sec² (√ t ) · 1 / 2√t
y` = 1/cos² ( √ t ) · 1 / 2√t

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What is 39 squared? A. 39 B. 1,482 C. 1,521 D. 78

Answers

Hey There!

The answer to you're question is C, because squared means to the power of two. So, 39 * 39 is 1,521.

Have A Brainly Day!

Squaring 39 means multiplying it by itself which amounts to  C. 1,521

What is required when asked to square?

Squaring a number means multiplying it by itself. So, 39 squared is 39 multiplied by 39. This is equal to 1,521.

Here is the calculation:

39 × 39 = 1,521

Quite often, people confuse squaring with finding the square root of a number.

Taking the square root of a number means finding a number that, when multiplied by itself, equals the original number. For example, the square root of 25 is 5 because 5 × 5 = 25.

Find more exercises on squaring;

brainly.com/question/14198272

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What is the median of this data set? 23,37,49,15,82

Answers

Answer:37

Step-by-step explanation:

Answer:37

Step-by-step explanation: rearrange so it becomes 15, 23,37, 49,82 middle is then 37

Are the two right triangles TRS and WUV congruent? If so, name the congruence postulate that applies.A. Might not be congruent
B. Congruent - SSS
C. Congruent - SAS
D. Congruent - ASA

Answers

Two figures are said to be congruent when they have the same shape and size or if one object is a mirror image of the other object. The right triangles trs and wuv are congruent when they have equal lengths of the sides and having equal sides, angles should as well be equal with the two triangles. The correct answer would be B, congruent - SSS.

Answer:Is D Congruent-ASA

Step-by-step explanation:

If names a major arc of a circle, then must be a minor arc. True or false?

Answers

Answer: The answer is true.


Step-by-step explanation:  We are to check whether a major arc of a circle is also minor arc or not.

In the attached figure, A major arc AB is drawn on a circle with centre 'O'. The, we can easily see from there that the major arc AB corresponds to another arc AB which is smaller in length than the major arc AB.

This smaller arc is called the minor arc AB. This explains the existence of a minor arc whenever there is a major arc on a circle.

Thus, the given statement is true.


A major arc of a circle is an arc of a circle having a measure greater than nor equal to it s minor arc. So in your statement that states that the minor arc is a major arc and that would be True. I hope you are satisfied with my answer and feel free to ask for more 

A rectangular bedroom floor has an area of 100 square feet and a length of 10 feet. What is the perimeter on the floor?

Answers

I'm guessing the the length is 10?So it would be a square, 4 sides of equal lengthSo 10 x 4 = 40It would be 40 feet

There is a school with 1,000 students and 1,000 lockers. On the first day of term the headteacher asks the first student to go along and open every single locker, he asks the second to go to every second locker and close it, the third to go to every third locker and close it if it is open or open it if it is closed, the fourth to go to the fourth locker and so on. The process is completed with the thousandth student. How many lockers are open at the end?

Answers

As many were opened during the time period. Jk, I don't know. This is a hard one
Hello,

answer: 31

I have make a programm in Qbasic

CONST Faux = 0
CONST Vrai = NOT (Faux)
CONST nb = 1000
DIM SHARED locker(nb) AS INTEGER
DIM i AS INTEGER, j AS INTEGER, answer AS INTEGER
'1 first student
FOR i = 1 TO nb: locker(i) = Vrai: NEXT i: ' CALL See
'2 2nd student
FOR i = 2 TO nb STEP 2: locker(i) = Faux: NEXT i: 'CALL See
FOR j = 3 TO nb
    FOR i = j TO nb STEP j
        locker(i) = NOT (locker(i))
    NEXT i
    'CALL See
NEXT j
answer = 0
FOR i = 1 TO nb
    IF locker(i) THEN answer = answer + 1
NEXT i
PRINT "answer="; answer
END

SUB See

SHARED locker() AS INTEGER
DIM i AS INTEGER
locker(0) = 0
FOR i = 1 TO nb
    PRINT locker(i);
    IF locker(i) THEN locker(0) = locker(0) + 1
NEXT i
PRINT locker(0)

END SUB