One mole of an ideal gas is held at standard conditions. At what Kelvin temperature would the pressure be doubled?

Answers

Answer 1

Answer:

The pressure of the gas will become double when its Kelvin temperature becomes $\boxed{{\text{twice}}}$ its initial value.

Further Explanation:

Ideal gas equation:

Ideal gas is just a theoretical concept and practically no gas can act as ideal. It can be considered as group of random moving particles having perfectly elastic collisions between them.

Ideal gas equation for one mole of gas is mentioned below.

PV = RT …… (1)

Here,

P is the gas pressure.

V is the gas volume.

T is the absolute temperature of gas.

R is the universal gas constant.

Standard conditions refer to state when pressure of gas is 1 atm and its temperature is 273 K.

Consider P’ and T’ to be new pressure and temperature respectively while all other terms in ideal gas equation remains constant. Equation (1) then modifies as follows:

P’V = RT’ …… (2)

Since new pressure is doubled, P’ becomes 2P. Equation (2) becomes,

(2P)V = RT’ …… (3)

Dividing equation (3) by equation (1), we get:

$\frac{{\left( {{\text{2P}}} \right){\text{V}}}}{{{\text{PV}}}} = \frac{{{\text{RT'}}}}{{{\text{RT}}}}$ …… (4)

Solving for T’,

${\text{T'}} = {\text{2T}}$

Therefore pressure is doubled when temperature becomes twice its initial value.

Learn more:

Which statement is true for Boyle’s law? brainly.com/question/1158880
Calculation of volume of gas: brainly.com/question/3636135

Answer details:

Grade: Senior School

Subject: Chemistry

Chapter: Ideal gas equation

Keywords: ideal gas equation, R, T, P, V, 2P, 2T, pressure, volume, universal gas constant, P’, T’, standard conditions.

Answer 2

Answer: The volume should be kept in constant condition.
Then we go $PV=nRT P/T = constant P1/T2 =P2/T1 T2=P1 T1 /P2$
and if P2 is equal to 2P1, we have $T2=P1T1/2P1=1/2 T1$
which means that needed temperature is half of the initial temperature

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B) neutralization
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Answers

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Express in scientific notation. Make sure your answer has the same number of significant figures as the starting value. 0.01325 = _____

Answers

0.01325 = 1.325x10^-2 or 13.25 x 10^-3 or 132.5 x 10^ - 4 or 1325 x 10^-5. Scientific notation is the standardized way to represent any number as the product of a real number and a power of ten.

Final answer:

The number 0.01325 is expressed in scientific notation as 1.325 x 10^-2. The number of significant figures remains the same.

Explanation:

The starting value 0.01325 can be converted to scientificnotation by first moving the decimal place. In this case, the decimal moved to the right by 2 places, making the number 1.325. So the number in scientific notation becomes 1.325 x 10^-2. Notice that there are still the same 4 significant figures (1, 3, 2, 5) in the number 1.325 as in the original number 0.01325.

Learn more about Scientific Notation here:

brainly.com/question/2005529

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Answers

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Explanation :

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Answers

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