MATHEMATICS HIGH SCHOOL

Susie is solving the quadratic

Answers

Answer 1

Answer:

Answer:

Option (D)

Step-by-step explanation:

Standard equation of a quadratic function is,

ax² + bx + c

Comparing this function with the given quadratic function,

f(x) = 2x² - 4x - 3

a = 2, b = -4 and c = -3

By using quadratic formula to get the value of x,

x = $(-b\pm √(b^2-4ac) )/(2a)$

= $(-(-4)\pm √((-4)^2-4(2)(-3)) )/(2(2))$

= $(4\pm√(16+24))/(4)$

= $(-4\pm √(40))/(4)$

= $(-2\pm √(10))/(2)$

Therefore, Susie made a mistake in step IV.

Option (D) is the answer.

Related Questions

How can you evaluate this expression using the distributive property?5×(7+6)
How to solve -5/7-11/7x=-y 2y=7+5x
Which of the following points are on the line given by the equation y=2x?A.(16,8)B.(1,3)C.(4,6)D.(3,6)E.(4,2)F.(5,10
The minimum value of 2x + 1 is 13
A system of equations is shown below:y = 5x + 3 y = 4x + 6 What is the solution to the system of equations? (−3, 18) (−3, −18) (3, −18) (3, 18)

Two lines are parallel. The equation for the first line is y=-3x+5. Which of the following can't be the equation of the second line?A. y=-3x+2
B. x-3y=-3
C. 3x+y=-6
D. 6x+2y=2 Two lines are parallel. The equation for the first line is y=-3x+5. Which of the following can't be the equation of the second line?
A. y=-3x+2
B. x-3y=-3
C. 3x+y=-6
D. 6x+2y=2 @Mathematics

Answers

Parallel lines can be distinguished by looking at the value of their slopes. These equations should have the same value of the slope. We are given the equation,

y=-3x+5

From the choices, we see that A, C and D have the same slope with the equation. Therefore, the correct answer is B, it is the equation that can't be parallel with the given equation.

Find the surface area of this cylinder using pie.

Answers

Answer:

the surface area of a cylinder:

$A=750\pi$ ft²

$A\approx 2356.19$ ft²

Step-by-step explanation:

Given

r = 10 ft

h = 15 ft

Using the formula to determine the surface area of a cylinder:

$A=2\pi rh+2\pi r^2$

$A=2\cdot \pi \cdot 15\cdot 10+2\cdot \pi \cdot 15^2$

$A=750\pi$ ft²

$A\approx 2356.19$ ft²

Thus, the surface area of a cylinder:

$A=750\pi$ ft²

$A\approx 2356.19$ ft²

An amusement park charges a $3 rental fee $1.50 per hour to rent a stroller. Write an equation that represents the total cost, starting what your variables represent.

Answers

Answer:the equation is

y = 3x + 1.5

Step-by-step explanation:

Let x represent the number of hours for which the stroller was rented.

Let y represent the total cost of renting the stroller for x hours.

The amusement park charges a $3 rental fee $1.50 per hour to rent a stroller. It means that $1.50 is constant and the total cost vary with number of hours for which it was rented. Therefore, for x hours,

y = 3x + 1.5

Which relationships hold true for the sum of the magnitudes of vectors u and v, which are perpendicular? a. ||u+v||=||u||+||v|| b. ||u+v||=sq rt(||u||^2+||v||^2) c. ||u+v||

Answers

The perpendicular are B) ||u+v|| = sqrt ||u||^2 + ||v||^2 and D) ||u+v|| less than ||u||+||v||

We have given that,

The relationships hold true for the sum of the magnitudes of vectors u and v,

We have determined which are perpendicular.

What is the magnitude of the vector?

The magnitude of a vector formula is used to calculate the length for a given vector (say v) and is denoted as |v|. So basically, this quantity is the length between the initial point and endpoint of the vector.

B) ||u+v|| = sqrt ||u||^2 + ||v||^2

AND

D) ||u+v|| less than ||u||+||v||

To learn more about the vector visit:

brainly.com/question/25705666

#SPJ2

it is

B) ||u+v|| = sqrt ||u||2 + ||v||2

AND

D) ||u+v|| less than ||u||+||v||

Simplify. (Polynomials) 1. (2cd^3)(-2c)(3c^d) =

2. (2x^2)(3x^6) - (4x^4)(2x^4) =

3. (6x^2)(3x^6) + (4x^4)(2x^4) =

4. (2ab^2)^2(-3a^2b^2) =

5. -6a^3(a^2-2a+1) =

6. -2xy(x^2-3xy+y^2) =

7. (a+b) (2a^2-ab+3b^2) =

(Please help asap!)

Answers

1. $(2cd^(3))(-2c)(3c^(d))=\n-12c^(d+2)d^(3)$

2. $(2x^(2))(3x^(6))-(4x^(4))(2x^(4))=\n6x^(8)-8x^(8)=\n-2x^(8)$

3. $(6x^(2))(3x^(6))+(4x^(4))(2x^(4))=\n18^(8)+8x^(8)=\n26x^(8)$

4. $(2ab^(2))^(2)(-3a^{2b^(2)})=\n4a^(2)b^(4)(-3a^{2b^(2)})=\n-12a^{2b^(2)+2}b^(4)$

5. $-6a^(3)(a^(2)-2a+1)=\n-6a^(5)+12a^(4)-6a^(3)$

6. $-2xy(x^(2)-3xy+y^(2))=\n-2x^(3)y+6x^(2)y^(2)-2xy^(3)$

7. $(a+b)(2a^(2)-ab+3b^(2))=\n2a^(3)-a^(2)b+3ab^(2)+2a^(2)b-ab^(2)+3b^(3)=\n2a^(3)+3b^(3)+a^(2)b+2ab^(2)$

1. $(2cd^(3))(-2c)(3cd)$
   $-12c^(3)d^(4)$

2. $(2x^(2))(3x^(6)) - (4x^(4))(2x^(4))$
   $6x^(8) - 8x^(8)$
   $-2x^(8)$

3. $(6x^(2))(3x^(6)) + (4x^(4))(2x^(4))$
   $18x^(8) + 8x^(8)$
   $26x^(8)$

4. $(2ab^(2))^(2)(-3a^(2)b^(2))$
   $((2ab^(2))(2ab^(2)))(-3a^(2)b^(2))$
   $(4a^(2)b^(4))(-3a^(2)b^(2))$
   $-12a^(4)b^(6)$

5. $-6a^(3)(a^(2) - 2a + 1)$
   $-6a^(3)(a^(2)) + 6a^(3)(2a) - 6a^(3)(1)$
   $-6a^(5) + 12a^(4) - 6a^(3)$

6. $-2xy(x^(2) - 3xy + y^(2))$
   $-2xy(x^(2)) + 2xy(3xy) - 2xy(y^(2))$
   $-2x^(3)y + 6x^(2)y^(2) - 2xy^(3)$

7. $(a + b)(2a^(2) - ab + 3b^(2))$
   $(2a^(3) - a^(2)b + 3ab^(2) + 2a^(2)b - ab^(2) + 3b^(3))$
   $(2a^(3) - a^(2)b + 2a^(2)b + 3ab^(2) - ab^(2) + 3b^(3))$
   $2a^(3) + a^(2)b + 2ab^(2) + 3b^(3)$

The main tank at an aquarium is a cylinder with diameter 203 ft and height 25 ft. Using 3.14 for pi, find the volume of the tank to the nearest cubic foot.

Answers

If the main tank at an aquarium is a cylinder getting the volume of the tank we have to follow the equation V = πr^2h. So we basically following the equation we should have V = (3.14)(101.5)2(25). We have to get the full equivalent values for each parameter so this would show as V = (3.14)(10302.25)(25) = 808726.625 or 808727 cubic feet.

Other Questions

The elevation of lake sam rayburn is 164 above mean sea level during the summer if it does not rain the elevation of the lake decreases by 0.5 feet each week

Which of the following does not represent a function?graph of a negative parabola oriented about the y axis with y intercept at positive 6 graph of an absolute value function oriented about the y axis graph of an ellipse with x intercepts negative 8 and positive 8 graph of a line with a positive slope and y intercept of negative 6

What is 191x21=?????

Classify triangle ABC by its sides if side AB = 6x, side AC = 4x + 6 and side BC = 8x + 3. The perimeter of triangle ABC is 63. Show all your work.

Susie is solving the quadratic​

Answers

Related Questions

Answers

Answers

Answers

Answers

What is the magnitude of the vector?

Answers

Answers

Susie is solving the quadratic