MATHEMATICS COLLEGE

What is 62 divided by 17 plus 29

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Answers

Answer 1

Answer: 62/17=3.647059+29= 32.64059 but if you round just say 33!

Answer 2

Answer:

Answer:

32.647

Step-by-step explanation:

Related Questions

A hot air balloon rose from ground level to 1000 feet in order to pass over a mountain. The balloon then descended 800 feet to a cruising height.A number line going from negative 1000 to positive 1000 in increments of 100. The line has points negative 1000, blank, A, blank, blank, negative 500, blank, blank, B, blank, 0, blank, C, blank, blank, 500, blank, blank, D, blank, 1000.Which point is a representation of cruising height in feet?Point APoint BPoint CPoint D
A meteorologist is studying the speed at which thunderstorms travel. A sample of 10 storms are observed. The mean of the sample was 12.2 MPH and the standard deviation of the sample was 2.4. What is the 95% confidence interval for the true mean speed of thunderstorms?
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Determine the equivalent system for the given system of equations.4x − 5y = 2 3x − y = 8 4x − 5y = 2 13x − 8y = 4 4x − 5y = 2 10x + 3y = 15 4x − 5y = 2 13x − 8y = 26 4x − 5y = 2 7x + 6y = 10
Jacob walks 1.250 meters to school every day. How many kilometers does Jacob walk in one week?HELP ASAP

While on vacation, Rosa stopped at a souvenir shop to buykeychains and refrigerator magnets for family members and
friends. Keychains cost $2 each, and refrigerator magnets cost $1
each. Let x represent the number of keychains that Rosa bought,
and let y represent the number of refrigerator magnets.
Rosa bought 12 items and paid $18 more for the keychains than
for the refrigerator magnets.

Answers

9514 1404 393

Answer:

10 keychains
2 magnets

Step-by-step explanation:

We assume you want to know how many of each item Rosa bought.

The problem information lets us write two equations:

x + y = 12

2x - y = 18

Adding the two equations, we get ...

3x = 30

x = 10 . . . . . divide by 3

y = 12 -x = 2 . . . find y

Rosa bought 10 keychains and 2 magnets.

Sanjay attempts a 49-yard field goal in a football game. For his attempt to be a success, the football needs to pass through the uprights and over the crossbar that is 10 feet above the ground.Sanjay kicks the ball from the ground with an initial velocity of 73 feet per second, at an angle of 34° with the horizontal.

What is true of Sanjay's attempt?

Responses

The kick is not successful. The ball is approximately 5 feet too low.

The kick is not successful. The ball is approximately 8 feet too low.

The kick is not successful. The ball is approximately 2 feet too low

The kick is good! The football clears the crossbar by approximately 5 feet.

Answers

In the above prompt involving a trajectory calculation, the correct option is: "The kick is not successful. The ball is approximately 5 feet too low." (Option A)

What is the rationale for the above response?

x component of trajectory = 73 cos 34 f/s

Now how long will it take to travel 49 yards (= 147 feet) ?

147 / (73 cos 34) = 2.43 seconds

Initial y component of trajectory = 73 sin 34 f/s = 40.82 f/s

but this velocity is acted upon by gravity

y = y0 + vot - 1/2 a t^2

y0 = 0

Now we need to know the y value at 2.43 seconds to see if it will clear the uprights.

y = 40.82 (2.43) - 1/2 (32.174)(2.43)2

= 4.2 Feet
Thus, it is correct to state that the "The kick is not successful. The ball is approximately 5 feet too low."

Learn more about Trajectory:
brainly.com/question/28164318
#SPJ1

The measure of the exterior angle of the triangle is?

Answers

Formula:

Interior + Interior=exterior

Step 1:

75 + 64 =x

139=x

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2. In an industrial training program, students have been averaging about 64 points on a standardized test. The lecture system was replaced by teaching machines with a lab instructor. There was some doubt as to whether the scores would decrease, increase, or stay the same. A sample of n = 60 students using the teaching machines was tested, resulting in a mean of 68 and a standard deviation of 12. Perform a hypothesis test to see if scores would decrease, increase, or stay the same. Use α = 0.05. Be sure to:1. State your hypotheses.
2. Find the value of the Test Statistic.
3. Find the p-value
4. State your decision (Reject or not)
5. State your conclusion.

Answers

Answer:

Case I

Null hypothesis: $\mu = 64$

Alternative hypothesis: $\mu \neq 64$

$t=(68-64)/((12)/(√(60)))=2.582$

$df=n-1=60-1=59$

Since is a two sided test the p value would given by:

$p_v =2*P(t_((59))>2.582)=0.012$

If we compare the p value and the significance level given $\alpha=0.05$ we see that $p_v<\alpha$ so we can conclude that we have enough evidence to reject the null hypothesis.

We can say that at 5% of significance the true mean is different from 64.

Case II

Null hypothesis: $\mu \leq 64$

Alternative hypothesis: $\mu > 64$

The statistic not changes but the p value does and we have:

$p_v =P(t_((59))>2.582)=0.006$

And we reject the null hypothesis on this case.

So we can conclude that the true mean is significantly higher than 64 at 5% of singnificance

Step-by-step explanation:

Data given and notation

$\bar X=68$ represent the sample mean

$s=12$ represent the sample standard deviation

$n=60$ sample size

$\mu_o =64$ represent the value that we want to test

$\alpha=0.05$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the population mean is different from 64 the system of hypothesis are :

Null hypothesis: $\mu = 64$

Alternative hypothesis: $\mu \neq 64$

Since we don't know the population deviation, is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=(\bar X-\mu_o)/((s)/(√(n)))$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=(68-64)/((12)/(√(60)))=2.582$

P-value

We need to calculate the degrees of freedom first given by:

$df=n-1=60-1=59$

Since is a two sided test the p value would given by:

$p_v =2*P(t_((59))>2.582)=0.012$

Conclusion

If we compare the p value and the significance level given $\alpha=0.05$ we see that $p_v<\alpha$ so we can conclude that we have enough evidence to reject the null hypothesis.

We can say that at 5% of significance the true mean is different from 64.

Now let's assume that we want to see if the mean is significantly higher than 64

Null hypothesis: $\mu \leq 64$

Alternative hypothesis: $\mu > 64$

The statistic not changes but the p value does and we have:

$p_v =P(t_((59))>2.582)=0.006$

And we reject the null hypothesis on this case.

So we can conclude that the true mean is significantly higher than 64 at 5% of singnificance

-5(4x + 7) <25
Answer here

Answers

Answer:

X>-3

Step-by-step explanation:

Hope I helped

Do u want the steps ?

Answer: x > -3

Step-by-step explanation: -5(4x + 7) <25

-20x - 35 < 25

-20x -35 + 35 < 25 + 35

-20x/20 < 60/20

x > -3

An insurance company writes policies for a large number of newly-licensed drivers each year. Suppose 40% of these are low-risk drivers, 40% are moderate risk, and 20% are high risk. The company has no way to know which group any individual driver falls in when it writes the policies. None of the low-risk drivers will have an at-fault accident in the next year, but 10% of the moderate-risk and 20% of the high-risk drivers will have such an accident. If a driver has an at-fault accident in the next year, what is the probability that he or she is high-risk

Answers

Answer:

The probability that he or she is high-risk is 0.50

Step-by-step explanation:

P(Low risk) = 40% = 0.40

P( Moderate risk) = 40% = 0.40

P(High risk) = 20% = 0.20

P(At - fault accident | Low risk) = 0% = 0

P(At-fault accident | Moderate risk) = 10% = 0.10

P(At-fault accident | High risk) = 20% = 0.20

If a driver has an at-fault accident in the next year, what is the probability that he or she is high-risk. Hence, We need to calculate P( High risk | at-fault accident) = ?

Using Bayes' conditional probability theorem

P( High risk | at-fault accident) = ( P( High risk) * P(At-fault accident | High risk) ) / { P( Low risk) * P(At-fault accident | Low risk) +P( Moderate risk) * P(At-fault accident | Moderate risk) + P( High risk) * P(At-fault accident | High risk) }

P( High risk | at-fault accident)= (0.20 * 0.20) / ( 0.40 * 0 + 0.40 * 0.10 + 0.20 * 0.20 )

P( High risk | at-fault accident) = 0.04 / 0 + 0.04 + 0.04

P( High risk | at-fault accident) = 0.04 / 0.08

P( High risk | at-fault accident) = 0.50.

Final answer:

The probability that a driver is high-risk given that they had an at-fault accident can be found using Bayes' theorem. Given the probabilities provided in the question, the probability is approximately 0.3333 or 33.33%.

Explanation:

To find the probability that a driver is high-risk given that they had an at-fault accident, we can use Bayes' theorem. Let's define the events:

A: Driver is high-risk
B: Driver has an at-fault accident

We are given the following probabilities:

P(A) = 0.20 (probability of a driver being high-risk)
P(B|A) = 0.20 (probability of an at-fault accident given that they are high-risk)
P(~A) = 0.80 (probability of a driver not being high-risk)
P(B|~A) = 0.10 (probability of an at-fault accident given that they are not high-risk)

Using Bayes' theorem, the probability of a driver being high-risk given that they had an at-fault accident is:

P(A|B) = (P(A) * P(B|A)) / (P(A) * P(B|A) + P(~A) * P(B|~A))

Substituting the given probabilities:

P(A|B) = (0.20 * 0.20) / (0.20 * 0.20 + 0.80 * 0.10) = 0.04 / (0.04 + 0.08) = 0.04 / 0.12 = 0.3333.

Therefore, the probability that a driver is high-risk given that they had an at-fault accident in the next year is approximately 0.3333 or 33.33%.