MATHEMATICS HIGH SCHOOL

Distance between -5.4 and -3.8

Answers

Answer 1
Answer:

Answer:

1.6

Step-by-step explanation:

In order to find the distance all you need to do is subtract the two numbers

so you would:

-5.4-(-3.8)=-1.6 or 1.6 since distance is not negative number.

A interesting fact to note is when you are subtracting negatives you can also just add the number as a positive

Ex.

5 - (-2) =7

5+2=7

Answer 2
Answer:

Final answer:

The distance between -5.4 and -3.8 is found by taking the absolute difference of these two numbers, which results in 1.6.

Explanation:

To find the distance between two numbers on a number line, we subtract the smaller number from the larger one and take the absolute value. Here, the smaller number is -5.4, and the larger number is -3.8. Therefore the absolute difference or distance between these two numbers would be |-5.4 - (-3.8)| which equals to |-5.4 + 3.8| = |-1.6|= 1.6. Hence, the distance between -5.4 and -3.8 is 1.6.

Learn more about distance between numbers here:

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If y= -7 when x= -28, find y when x=20​
A map has a scale of 1 cm : 20 km. Two cities are 2.5 cm apart on the map. To the nearest tenth of a kilometer, what is the actual distance corresponding to the map distance?A. 70 km B. 52.5 km C. 50 km D. 150 km
Markus scored 85, 92, 82, and 94 on the first four tests of the semester. His teacher has not yet told him his score on his fifth test, but did tell him that his score on the fifth test is five points lower than the average (arithmetic mean) of all five tests. Which equation could Markus use to determine the score of the fifth test, x?
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Flying against the wind a jet travels 7740 miles in 9 hours. Flying with the wind the same jet travels 4000 80 miles in 3 hours. What is the rate of the jet in still air and what is the rate of the wind?

Answers

j\ \rightarrow\ the\ rate\ of\ the\ jet\ in\ still\ air \nw\ \rightarrow\ the\ rate\ of\ the\ wind\n\nj-w= \frac{\big{7740\ miles}}{\big{9\ hours}}\ \ \ \Rightarrow\ \ \ j-w=860\ (miles)/( hour)\n\n j+w= \frac{\big{4080\ miles}}{\big{3\ hours}}\ \ \ \Rightarrow\ \ \ j+w=1360\ (miles)/( hour)\n----------\n\n2j=(860+1360)\ (miles)/( hour)\ \ \ \Rightarrow\ \ \ 2j=2220\ (miles)/( hour)\ \ \ \Rightarrow\ \ \ j=1110\ (miles)/( hour)

j+w=1360\ (miles)/( hour)\ \ \ \Rightarrow\ \ \ w=(1360}-1110)\ (miles)/( hour)=250\ (miles)/( hour)\n\n\nAns.\ the\ rate\ of\ the\ jet\ in\ still\ air\ is\ 1110\ (mi)/(hr) \ \ \ \n\n.\ \ \ \ \ \ and\ \ \ the\ rate\ of\ wind\ is\ 250\ (mi)/(hr)

Evaluate......6!2!=?

Answers

Answer:  The required value of the given expression is 1440.

Step-by-step explanation:  We are given to evaluate the following expression involving factorials:

E=6!2!.

We know that

for any non-negative integer n, the factorial of n is defined as:

n!=n*(n-1)*(n-2)*~.~.~.~*2*1.

Therefore, the value of the given expression E will be

E\n\n=6!2!\n\n=6*5*4*3*2*1*2*1\n\n=1440.

Thus, the required value of the given expression is 1440.

Note that the required value of the given expression 6! 2! is 1440.

How is this so?

We are given to evaluate the following expression involving factorials -

E = 6! 2!

n! = x x (n-1) x (n-2 ) x .... x 2 x 1

Hence, , the value of the given expression E will be

= 6! 2!

= 6 x 5 x 4 x 3 x 2 x 1 x 2 x 1

= 1440

Recall that factorials are mathematical operations denoted by an exclamation mark (!) that represent the product of a positive integer and all positive integers less than it.

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Find the domain and range of the relation. A. domain: {-3, -1.5, 1.5, 3}; range: {4, 3, 1.5} B. domain: {-3, -1.5, 0, 1.5, 3}; range: {4, 3, 1.5} C. domain: {4, 3, 1.5}; range: {-3, -1.5, 1.5, 3} D. domain: {4, 3, 1.5}; range: {-3, -1.5, 0, 1.5, 3}

Answers

the domain is the x values and the range is the y values

domain : { - 3, -1.5,0,1.5,3 }
range : { 4, 3, 1.5 }

5 over 9 - 1 over 3 x 1 over 6

Answers

The answer is 1/2 or 0.5; 1/3 * 1/6 = 1/18; 5/9 - 1/18 (find common denominator) = 10/18 - 1/18 = 9/18; 9/18 cancels to 1/2!

Mario invested $6,000 in an account that pays 5% annual interest compounded annually. Using the formula A = P(1 + r)t, what is the approximate value of the account after 2.5 years?a. $6,075
b. $6,118
c. $6,456
d. $6,778

Answers

The approximate value of the account after 2.5 years is $6778.

Compound interest

The compound interest is given by:

A = P(1 + r)^t

where P is the initial amount, r is the interest rate, t is the period and A is the final amount.

Given that:

r = 5% = 0.05, P = $6000, t = 2.5 years, hence:

A = 6000(1 + 0.05) ^ 2.5 = $6778

The approximate value of the account after 2.5 years is $6778.

Find out more on Compound interest at: brainly.com/question/24924853
Given:
Principal = 6,000
interest rate = 5%
term = 2.5 years

A = P (1+r)^t
A = 6,000 (1 + 0.05)².⁵
A = 6,000 (1.05)².⁵
A = 6,000 (1.1297)
A = 6,778.20 Choice D.

A proposed null hypothesis states that there is no difference in the population mean heights of two neighboring districts. The difference of the sample means is 10 cm, and the standard deviation of the difference of sample means is 6 cm. Which conclusion can we draw at the 68% confidence level?

Answers

Answer:

Explained

Step-by-step explanation:

Null hypothesis is something that states that there is no difference between the population means, while the alternative hypothesis states that there is difference between the two.

So, If the difference of the sample means is 10cm, and the standard deviation of the difference of sample means is 6 cm. Then  the population means of the two districts will be different according to the manual solution.

Answer:

The population means of the two districts are different.

Step-by-step explanation:
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