MATHEMATICS COLLEGE

If f(x) = 2 - x and g(x) = x^2+ x, find each value.. g(3)

. F(m)

. F (1)+g(2)

. F(11)

Answers

Answer 1

Answer:

Answer:

Step-by-step explanation:

3x + 5y = 7

Since that is our original form, let's convert it so that we can find the slope:

5y = -3x + 7

y = -3/5 x + y

To get a perpendicular line, we need the negative reciprocal of the slope. This means that the sign switches and numerator and denominator flip:

m = 5/3

From here, we use the point-slope equation and then convert that into slope-intercept form:

y - y1 = m(x - x1)

y - 6 = 5/3(x - 0)

y - 6 = 5/3x

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8/3+7/5aSimplify your answer as much as possible.

Are they equal or diffrent angles

Answers

equal because the parallel lines :)

Records show that the average number of phone calls received per day is 9.2. Find the probability of between 2 and 4 phone calls received (endpoints included) in a given day.

Answers

Answer:

4.76% probability of between 2 and 4 phone calls received (endpoints included) in a given day.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = (e^(-\mu)*\mu^(x))/((x)!)$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given interval.

Records show that the average number of phone calls received per day is 9.2.

This means that $\mu = 9.2$ .

Find the probability of between 2 and 4 phone calls received (endpoints included) in a given day.

$(2 \leq X \leq 4) = P(X = 2) + P(X = 3) + P(X = 4)$

$P(X = x) = (e^(-\mu)*\mu^(x))/((x)!)$

$P(X = 2) = (e^(-9.2)*(9.2)^(2))/((2)!) = 0.0043$

$P(X = 3) = (e^(-9.2)*(9.2)^(3))/((3)!) = 0.0131$

$P(X = 4) = (e^(-9.2)*(9.2)^(4))/((4)!) = 0.0302$

$(2 \leq X \leq 4) = P(X = 2) + P(X = 3) + P(X = 4) = 0.0043 + 0.0131 + 0.0302 = 0.0476$

4.76% probability of between 2 and 4 phone calls received (endpoints included) in a given day.

Find the first derivative for y = f(x). fox ) 3x² -5x-1 at a Pocat where a = 4

Answers

Answer:

Step-by-step explanation:

f(x) = 3x² -5x - 1

f'(x) =2*3x - 5*1 +0

= 6x - 5

f'(4) = 6*4 - 5

= 24 - 5

= 19

Someone help pls!!! Thanks

Answers

Answer:

The answers are A and C

Step-by-step explanation:

A is correct because -16 is on the left of the number line.

Pleeease open the image and hellllp me

Answers

1. Rewrite the expression in terms of logarithms:

$y=x^x=e^(\ln x^x)=e^(x\ln x)$

Then differentiate with the chain rule (I'll use prime notation to save space; that is, the derivative of y is denoted y' )

$y'=e^(x\ln x)(x\ln x)'=x^x(x\ln x)'$

$y'=x^x(x'\ln x+x(\ln x)')$

$y'=x^x\left(\ln x+\frac xx\right)$

$y'=x^x(\ln x+1)$

2. Chain rule:

$y=\ln(\csc(3x))$

$y'=\frac1{\csc(3x)}(\csc(3x))'$

$y'=\sin(3x)\left(-\cot^2(3x)(3x)'\right)$

$y'=-3\sin(3x)\cot^2(3x)$

Since $\cot x=(\cos x)/(\sin x)$ , we can cancel one factor of sine:

$y'=-3(\cos^2(3x))/(\sin(3x))=-3\cos(3x)\cot(3x)$

3. Chain rule:

$y=e^{e^(\sin x)}$

$y'=e^{e^(\sin x)}\left(e^(\sin x)\right)'$

$y'=e^{e^(\sin x)}e^(\sin x)(\sin x)'$

$y'=e^{e^(\sin x)+\sin x}\cos x$

4. If you're like me and don't remember the rule for differentiating logarithms of bases not equal to e, you can use the change-of-base formula first:

$\log_2x=(\ln x)/(\ln2)$