HELP. I don't know if I'm supposed to put in theorems or?? It's a fill in the blank for a,b,c,d, and e.
Pretty sure A and B are "Given" but not 100%.

Answers

Answer 1

Answer: I hope this helps you

Related Questions

Simplify (3(3n-10) - 2n + 5). The solution for (n) is: a) 2n - 25 b) 5n - 35 c) 7n - 25 d) 7n - 25
Is 5 - (-3) equal to 8 or -2. And if one or the other, please state why one is correct and the other isn't.
If f(c) = 0, which of the following statements must be true?A. The point (c,0) lies on the graph of f(x) B. x - c is a factor of f(x). C. c is a 0 for f(x). D. All three statements are true.
A six-sided number cube is rolled 12 times. An even number is rolled 7 times. what is the experimental probability that even number is rolled?
Using the ratio of perfect squares method, what is square root of 41 rounded to the nearest hundredth?Do not use your calculator to answer this question. Use the ratio of perfect squares method.

Determine if triangle XYZ with coordinates X(1, 1), Y(5, 6), and Z(6, 2) is a right triangle.

Answers

Answer:

Yes.

Step-by-step explanation:

If you graph it you can see that they all the points match up to the perfect right triangle. You may have to rotate it to see it though. Point Z is the angle of the triangle that is the corner of the 90 degree triangle.

Simplify the product using the distributive property. (-4h +2)(3h +7)

Answers

Answer: $-12h^2-22h+14$

Step-by-step explanation:

According to distributive property under multiplication over addition

We can write a.(b+c)=a.b+a.c

Since, The given expression, (-4h+2)(3h+7)

By applying distribution in first bracket.

we can write, (-4h+2)(3h+7)= -4h(3h+7)+2(3h+7)

Again on applying distribution property,

we get, (-4h+2)(3h+7)= -4h×3h+(-4h)×7+2×3h+2×7

⇒ $(-4h+2)(3h+7)= -12h^2-28h+6h+14$ = $-12h^2-22h+14$

-2(2h - 1)(3h + 7)
(-2(2h) - 2(-1))(3h + 7)
(-4h + 2)(3h + 7)
-4h(3h + 7) + 2(3h + 7)
-4h(3h) - 4h(7) + 2(3h) + 2(7)
-12h² - 28h + 6h + 14
-12h² - 22h + 14

Evaluate the limit as x approaches 0 of (1 - x^(sin(x)))/(x*log(x))aka: $(1-x^(sin(x)))/(x*log(x))$

Please include steps/explanation.

Answers

$sin~ x \approx x ~ ~\sf{as}~~ x \rightarrow 0$

We can replace sin x with x anywhere in the limit as long as x approaches 0.

Also,

$\large \lim_( x \to 0 ) ~ x^x = 1$

I will make the assumption that log(x)=ln(x).

The limit result can be proven if the base of log(x) is 10.

$\large \lim_(x \to 0^(+)) (1- x^(\sin x) )/(x \log x ) \n~\n \large = \lim_(x \to 0^(+)) (1- x^(\sin x) )/( \log( x^x) ) \n~\n \large = \lim_(x \to 0^(+)) (1- x^(x) )/( \log( x^x) ) ~~ \normalsize{\text{ substituting x for sin x } } \n~\n \large = (\lim_(x \to 0^(+)) (1) - \lim_(x \to 0^(+)) \left( x^(x)\right) )/( \log( \lim_(x \to 0^(+))x^x) ) = (1-1)/(\log(1)) = (0)/(0)$

We get the indeterminate form 0/0, so we have to use Lhopitals rule

$\large \lim_(x \to 0^(+)) (1- x^(x) )/( \log( x^x) ) =_(LH) \lim_(x \to 0^(+)) (0 -x^x( 1 + \log (x)) )/(1 + \log (x) ) \n = \large \lim_(x \to 0^(+)) (-x^x) = \large - \lim_(x \to 0^(+)) (x^x) = -1$

Therefore,

$\large \lim_(x \to 0^(+)) (1- x^(\sin x) )/(x \log x ) =\boxed{ -1}$

Emilio keeps 92% of his trading cards in a binder. What fraction of trading cards does he keep in his binder?

Answers

92/100 which simplifies to 24/25

"Percent" means "over 100." So 92% is:

$(92)/(100)$

This can be reduced by dividing both the numerator and denominator by 4 to get:

$(23)/(25)$

This is the fraction of trading cards he keeps in his binder.

Use the card collection box-and-whisker plot to solve. In which quarter are the data least concentrated?

A.first quarter

B.second quarter

C.third quarter

D.fourth quarter

Answers

The right answer for the question that is being asked and shown above is that: "B.second quarter." Use the card collection box-and-whisker plot to solve. In the second quarter that the data are at least concentrated.

What is the arithmetic mean of the following numbers?
9, 10, 6, 5, 6