Martha has $180. she needs a total of $20000 to start an account. she earns $60 per day working, of which she saves $50. which equation can she use to determine the number days,d, she needs to work to reach her goal of $20000.

Answers

Answer 1
Answer:
180+ 50x = 20000

she has 180 dollars to start off with so you want to add that to the total cost. Then she makes 60 a day sbyt only actually saves 50 of it so +50x (thats the way i see it. The way they put it in the question is questionable. Dont know if she puts off the 50 or the 10)

The amount she started off with + how much she saves from working per day = total amount she needs

180+ 50x = 20000

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Rita makes sidewalk chalk two days a week each of those days she spent one one fourth hour making the chalk how much times does rita spend making sidewalk chalk in 3 weeks

Answers

1 hr 30 min
One 1/4 hour= 15 min
Twice a week= 30 min
1 week= 30 min
x3. Week x3
3 week= 90 min
90 min= 1 hr. 30 min

Answer: 7 2/4 hours a week

Step-by-step explanation:

1 1/4 x 2 = 10/4

10/4 x 30/4

30/4 = 7 2/4

The Drama Club is showing a video of their recent play. The first showing begins at 3:45 p.M. The second showing is scheduled at 6:25 p.M. With a 1 2 −hour break between the showings. How long is the video in hours and minutes? Pt. 2 The second showing started 20 minutes late. Will the second showing be over by 8:45 p.M.?

Answers

Answer:

the movie is 2 hours and 10 min long

no it will not be over by 8:45pm

Step-by-step explanation:

if the movie begins at 3:45 pm and the next begins at 6:25pm with a half hour break you need to take 30 min from 6:25 to see what time the movie ended which is 5:55pm then you figure the time between 3:45pm and 5:55pm which is 2hours and 10 min.

since thw movie is starting 20 min late from 6:25pm that is now a start time of 6:45pm if the movie is 2hours and 10 min it will not be over by 8:45pm since that is only 2 hours

What is the inequality of 0.3(0.3x+0.8)<-0.3

Answers

0.3(0.3x+0.8)<-0.3\ /:0.3\n\n0.3(0.3x+0.8):0.3<-0.3:0.3\n\n0.3x+0.8<-1\n\n0.3x<-1-0.8\n\n0.3x<-1.8\ /:0.3\n\nx<- (1.8)/(0.3) \n\nx<- (18)/(3) \n\nx<-6\ \ \ \ \Leftrightarrow\ \ \ x\in(-\infty;\ -6)

Which is the graph of y ≤ 1 – 3x?

Answers

The inequality sign is less than and equal to, the line will be a solid line and shaded below the graph. The required graph is graph A

In order to get the required graph of y ≤ 1 – 3x, we need to get the x and y-intercept of the equation

Given the equation y ≤ 1 – 3x?

The x-intercept occurs at y = 0

0 = 1 - 3x

-1 = -3x

x = 1/3

The x-intercept will be at (1/3, 0)

Similarly for the y-intercept

The y-intercept occurs at x = 0

y = 1 - 3(0)

y = 1

The y-intercept will be at (0, 1)

We need to find the graph with the intercept first. We can see that all the graph has the gotten intercept.

Since the inequality sign is less than and equal to, the line will be a solid line and shaded below the graph. The required graph is graph A

Learn more here: brainly.com/question/15816805

Answer:

Graph 1

Step-by-step explanation:

Given : Inequality y\leq 1-3x

To find : Which is the graph of the equation?

Solution :

Inequality y\leq 1-3x

We determine the x-intercept and y-intercept,

  • For x-intercept, put y=0

0\leq 1-3x                  

Add 3x both side,

3x\leq 1            

Divide both side by 3,

x\leq (1)/(3)        

x\leq 0.33            

Point is (0.33,0)

  • For y-intercept, put x=0

y\leq 1-3(0)              

y\leq 1                

Point is (0,1)

As there is equal and less than so there is a complete line not dotted line.

The graph is passing through the points (0.33,0) and (0,1) and drawn LHS of the graph.

Therefore, The correct option is graph 1.

Refer the attached figure below.                                              

Solve for y

y/162 - 7/9

Answers

9y=1134
the answer is y=126

Can you help me with any of these please (not lazy don't understand )

Answers

I believe the first one is h becuase there is a y on the left side.
for the second one just find the slope for the points and see which one doesn't fit in the groups (I would use tables)
and for the last one try writing equations for them.

but idk tho that's just what I would do.