Which of these do you prove with a geometric proof?experiments
opinions
postulates
theorems

Answers

Answer 1
Answer: postulates and theorems.

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IN a physics lab, a student discovers that the magnitude of the magnetic field at a certain distance from a long wire is 4.0μT. If the wire carries a current of 5.0 A, what is the distance of the magnetic field from the wire?

Answers

Answer:

0.25 m

Explanation:

The intensity of the magnetic field around a current-carrying wire is given by:

B=(\mu_0 I)/(2 \pi r)

where

where

\mu_0 = 4\pi \cdot 10^(-7)Tm/A is the permeabilty of free space

I is the current

r is the distance from the wire

In this problem, we know:

B=4 \mu T=4 \cdot 10^(-6) T is the magnetic field

I=5.0 A is the current in the wire

Re-arranging the equation, we can find the distance of the field from the wire:

r=(\mu_0 I)/(2 \pi B)=((4\pi \cdot 10^(-7))(5.0 A))/(2\pi(4\cdot 10^(-6) T))=0.25 m

a car with a mass of 2000 kilograms is moving around a circular curve at a uniform velocity of 25 meters per second. The curve has a radius of 80 meters. What is the centripetal force on the car

Answers

In the given problem, we say various information's that are going to help us reach the ultimate answer to the question. Let us first write the information's that have been presented in front of us.
Mass of the car = 2000 kg
Velocity of the car = 25 m/s^2
Radius of the circle = 80 m
Now we already know the equation for calculating the centripetal force and that is
Centripetal Force = [mass * (velocity)^2]/Radius
                            = [2000 * (25)^2]/80
                            = (2000 * 625)/80
                            = 1250000/80
                            = 15625
So the centripetal force on the car is 15625 Newtons
  

your answer is 15,625 N

i just took the test

A line graph usually reveals a relationship between which factors

Answers

Answer:

variables on the horizontal and vertical axis (slope, outliers, +/- correlation, etc)

Explanation:

What is the minimum coeffecient of static friction μmin required between the ladder and the ground so that the ladder does not slip?

Answers

Answer:

\mu = (1)/(2tan\theta)

Explanation:

let the ladder is of mass "m" and standing at an angle with the ground

So here by horizontal force balance we will have

\mu N_1 = N_2

by vertical force balance we have

N_1 = mg

now by torque balance about contact point on ground we will have

mg((L)/(2)cos\theta) = N_2(L sin\theta)

so we will have

N_2 = (mg)/(2tan\theta)

now from first equation we have

\mu (mg) = (mg)/(2tan\theta)

\mu = (1)/(2tan\theta)

Two or more atoms join together to form a ?

Answers

two atoms of the same element can join together to form a molecule

atoms of two or more elements joined together form compounds.

Magnet A has twice the magnetic field strength of Magnet B and at a certain distance pulls on magnet B with a force of 100 N. The amount of force that magnet A exerts on magnet B is A. at or about 50 N. B. exactly 100 N. C. more information is needed.

Answers

Answer:

50 N is the correct answer.