What is 12-3x=-6x
Show the work please
Answers
Answer:
x=-3
Step-by-step explanation:
12-3x=-6x
12=-3x-6x
12= -9x
----------
-9. -9
12/9= -3
How I did it :
12 - 3x = -6x
Add 3 x to both sides:
12 = -3x
Then divide both sides by -3:
-4 = x
And just switch it around
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Answer:
6). Option (B)
7). Option (C)
Step-by-step explanation:
6) Property of a triangle :
"Sum of all interior angles is 180°"
(x + 2)° + (2x + 2)° + (2x - 1)° = 180°
5x + 3 = 180°
5x = 177°
x =
(x + 2)° = 37.4°
(2x - 1)° = 69.8°
(2x + 2)° = 72.8°
Option (B) is the answer.
7). (4x + 2)° + (2x + 1)° + (x - 1)° = 180°
7x + 2 = 180°
7x = 178°
x =
(4x + 2)° = 103.7
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Option (C) will be the answer.
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Answer:
12.23+4r-42°-9x
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is always a square.
343 = 7³
If the area is 343 m², then the rectangle with the smallest perimeter
is the square with sides of
√343 = (7)^ ¹·⁵ = 7 √7 meters
Final answer:
To find the dimensions of a rectangle with the smallest possible perimeter given an area of 343 m², we must determine the dimensions that will minimize the sum of the lengths of the four sides. The dimensions of the rectangle are 7 m by 49 m.
Explanation:
To find the dimensions of a rectangle with the smallest possible perimeter given an area of 343 m², we must determine the dimensions that will minimize the sum of the lengths of the four sides. Since the perimeter is the sum of the lengths of the opposite sides of a rectangle, we can rewrite the perimeter formula as P = 2l + 2w, where l represents the length and w represents the width.
Now, let's solve for the dimensions:
1. Start with the formula for the area of a rectangle: A = lw.
2. Substitute the given area: 343 = lw.
3. Rewrite the perimeter formula: P = 2l + 2w.
4. Express one variable in terms of the other using the area formula: l = 343/w.
5. Substitute the expression for l in the perimeter formula: P = 2(343/w) + 2w.
6. Simplify the equation: P = (686/w) + 2w.
7. To find the minimum perimeter, differentiate the equation with respect to w and set it equal to zero: 0 = (686/w²) + 2.
8. Solve the equation for w: (686/w²) + 2 = 0. Subtract 2 from both sides: 686/w² = -2. Multiply both sides by w²: 686 = -2w².
9. Divide both sides by -2: -343 = w². Take the square root of both sides (ignoring the positive value since the width cannot be negative): w = -√343 = -7.
10. Substitute the value of w back into the area formula: 343 = l(-7). Solve for l: 343 = -7l. Divide both sides by -7: l = 343/-7 = -49.
Since both dimensions cannot be negative, we ignore the negative values and take the absolute values of w and l: w = 7 and l = 49.
Therefore, the dimensions of the rectangle with an area of 343 m² and the smallest possible perimeter are 7 m by 49 m.
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