MATHEMATICS MIDDLE SCHOOL

Draw a bar model that shows how the number of hours in March compares with the number of hours in February of this year.

Answers

Answer 1

Answer:

Answer:

Firstly we calculate the number of hours of both months.

This year is not a Leap year. So, the number of days of February is 28

and the number of days of March is 31

So, Number of hours February has 28 × 24 = 672 hours

and, Number of hours March has 31 × 24 = 744 hours

The bar graph is the best visual representation when we have categorical data. It is drawn by using a rectangular bar where the length of the bar represents height or frequency.

Answer 2

Answer: Okay so first we need to find how many days are in March and February. March has 31 days and because this year was a leap year February has 29 days.

The next step is to convert days to hours.
March: 31x24=744
February: 29x24=696

Now its time to graph

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If x and y are real numbers such that x > 1 and y < −1,then which of the following inequalities must be true?
A. x/y> 1
B. |s|^2 > |y|
C. x/3− 5 > y/3 − 5
D. x^2 + 1 > y^2 + 1
E. x^(−2) > y^(−2)

Answers

$x > 1\ \wedge\ y < -1\n\nA.\ (x)/(y) > 1-FALSE;example:x=2;\ y=-2\ then\nL=(2)/(-2)=-1;R=1;\ L < R\n\nB.\ |x|^2 > |y|-FALSE;example:x=2;\ y=-6\ then\nL=|2|^2=2^2=4;R=|-6|=6;\ L < R\n\nC.\ (x)/(3)-5 > (y)/(3)-5-TRUE;(x)/(3)-5 > (y)/(3)-5\to(x)/(3) > (y)/(3)\to x > y$

$D.\ x^2+1 > y^2+1-FALSE;example:x=2;\ y=-3\ then\nL=2^2+1=4+1=5;R=(-3)^2+1=9+1=10;L < R\n\nE.\ x^(-2) > y^(-2)-FALSE;example:x=3;\ y=-2\ then\nL=3^(-2)=(1)/(9);R=(-2)^(-2)=(1)/(4);\ L < R$

Julie takes her dog on long walks.It takes them 1/4 of an hour to walk 2/3 of a mile.How far will they have walked after 1.5 hours?

Answers

A quarter of an hour is 15 minutes. An hour and a half is 90 minutes. To get from 15 to 90 you multiply 15 by 6. You then multiply 2/3 by 6. 12/3, which is then simplified to 4 miles. The answer is 4 miles.

Draw a number line from –10 to 10. Put tick marks at each integer. Graph a point with the given coordinate. point F, coordinate –7

Which is true about point F on the number line?
A.

Point F is 7 units to the right of 0.

B.

Point F is 1 unit to the right of –6.

C.

Point F is 1 unit to the left of –6.

D.

Point F is 7 units to the left of 7.

Answers

lets try to draw a line here, now, I can draw the tick marks but you can imagine them that there are above the numbers

__________F________________________________________________
-10 -9 -8 -7 -6 -5 -4 -3 -2 -1 0 1 2 3 4 5 6 7 8 9 1 0

the answer is C

A group of students wish to go bowling. There is a flat rate of $5 per student for shoe rental. It then costs $2.50 pergame up to 2 games total and then the cost is $2.00 per game after the first 2. If 6 students went, each rented shoes
and each rolled 3 games;
1. create a step function equation to calculate the cost per student per game
2. graph your step function
3. determine the total cost for this bowling outing

Answers

Answer:

$c(g)=\left\{\begin{array}{lcl}(5)/(\lceil g\rceil)+2.5&\text{for}&0<g \le 2\n\n(6)/(\lceil g\rceil)+2&\text{for}&g>2\end{array}\right.$
see below
$72

Step-by-step explanation:

1. Since the function is supposed to give cost per game, it will be the stated cost per game (2.50 or 2.00) in addition to the quotient of the fixed cost and the number of games. For more than 2 games, the "fixed cost" is essentially the $5 shoe cost plus the premium on the first two games, an additional dollar.

For graphing purposes, we choose to use the "ceiling" function, so that any fractional game is charged at the price for the next higher integer number of games.

The "cost per game" function can be written as ...

$c(g)=\left\{\begin{array}{lcl}(5)/(\lceil g\rceil)+2.5&\text{for}&0<g \le 2\n\n(6)/(\lceil g\rceil)+2&\text{for}&g>2\end{array}\right.$

2. The graph is shown in the attachment.

3. The cost per game for 3 games is c(3) = 6/3+2 = 4, so the cost for 3 games for 1 student is 3·4 = 12. The cost for 6 students is then 6·12 = 72 dollars.

Which are the center and radius of the circle with equation (x + 5)2 + (y - 4)2 = 9?

Answers

Answer:

Center (-5,4) radius 3

Step-by-step explanation:

The standard equation of a circle is

(x-h)^2+(y-k)^2=r^2

where the center is (h,k) and r is the radius

so h=-5 in this case and k is 4

r^2=9 so r=3

amber invested 25000 at 2% for 3 years compound simiannually.Find future value at the end of 3 years?

Answers

Use the compound interest formula:

A = P(1+r/n)^(nt). Here, P = $25000, r = 0.02, t = 3 and n = 2.

Then:

A = $25000(1 + 0.02/2)^(3*2)

= $25000(1.01)^6

= $26538.00 (future value at the end of 3 years)

First you use the compound interest formula which is: A = P(1+r/n)^(nt).

Plug in the number in this case being P = $25000, r = 0.02, t = 3 and n = 2.

A = $25000(1 + 0.02/2)^(3*2)

= $25000(1.01)^6

= $26538.00 (future value at the end of 3 years)

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The system of equations shown below is graphed on a coordinate grid:3y + x = 4 2y − x = 6 Which statement is true about the coordinates of the point that is the solution to the system of equations? A. It is (−2, 2) and lies on both lines. B. It is (−5, 3) and lies on both lines. C. It is (−5, 3) and does not lie on either line. D. It is (−2, 2) and does not lie on either line.

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