MATHEMATICS COLLEGE

Which of the following expression are equivalent to 2x+4 select three answers?A.6x
B.1/3(18x)
c.1/3(6x+12)
d.2/3(3x+6)
e.2(x+4)
f.4(1/2x+1)

Answers

Answer 1

Answer:

Answer:

A.6x

Step-by-step explanation:

hope i helped!! ...............

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Find the measure of the numbered angle
Please help me don’t know how to do it,
Evaluate the expression 28C14
. Chad's pay rate for babysitting is y = 9x, where x is the number of hours he babysits, and y is the number of dollars he earns. Horatio's pay rate is shown in the graph below. Horatio's Babysitting Pay Rate. Which of the following statements is true? * HORATIO'S BABYSITTING PAY RATE 100 90 80 70 60 Dollars Earned (8.60) 50 40 30 20 10 (4, 30) 0 1 2 3 4 5 6 7 8 9 10 Hours A. Chad makes $1.00 more per hour than Horatio. O B. Chad makes $1.50 more per hour than Horatio. C. Chad makes $1.00 less per hour than Horatio. D. Chad makes $1.50 less per hour than Horatio.
Jill brought a pound of strawberries for 4.00. What is the price per ounce of strawberries

Nannette has an 8-foot-long board. She needs to cut it into 9 equal length parts. How many feet long should each sectiob of the board be?

Answers

8/9 of a foot long each section or 10 2/3 inches each section

Nondigestible carbohydrates can be used in diet foods, but they may have Problem 7.2 effects on colonic hydrogen production in humans. We want to test to see if inulin, fructooligosaccharide, and lactulose are equivalent in their hydrogen production. Preliminary data suggest that the treatment means could be about 45, 32, and 60 respectively, with the error variance conservatively estimated at 35. How many subjects do we need to have power .95 for this situation when testing at the ????1 = .01 level?

Answers

Answer:

null hypothesis = µ1=µ2=µ3; µ1= popuation mean of inulin µ2 = population mean of fructicoligosaccharide =µ3=population mean of lactulose

alternative hypothesis =µ1≠µ2 ≠µ3

t1= µ-45/s1 / N-1

at the significance level 0.01

t at ᵅ/2 =0.005 and degree of freedom= 35-1=34 is 2.25

t1 = µ-32/s1/N-1

2.25= µ-45/s1/34

= s1/34= µ-45/2.25

=s1 =(µ-45/2.25)*34

t2= µ-32/s2/34

2.25 =µ-32/s2/34

s2/34= µ-32/2.25

s2=µ-32/2.25*34

T= 45-32/s1/sqrt34+s2/sqrt34

t at 0.005 and no of grees of freedom 68 =2.37

2.37=45-32/

or s1/sqrt34+s2/sqrt34 = 13/2.37

s1+s2 = 13/2.37 *5.83

s1+s2= 31.98 or 32

(µ1-45/2.25)*34+µ2-32/2.25*34=32

or µ1+µ2 = 2525

µ1=2525-µ2

µ1 and µ2 are not equal

thus null hypothesis is rejected

conclusion all the three components are not in equal amount in hydrogen production

Explanation : in this experiment we have to prove whether the means of insulin,fructicoligosaccharide and lactulose are equal. so even if we prove that two of them are not equal null hypothesis will be rejected. we use student-t test because we have to compare the means of two population.

Please help me solve x and z

Answers

Answer: Z = 107 as the opposite angles are equal. Then to find x, z is on the same line as (10x+3) so,

107+10x+3=180°

10x+3= 180-107

10x+3= 73°

now,

10x= 73-3 = 70

x= 70/10

x= 7

Hence z= 107 and x=7

pls mark brainliest

Answer:

$x=7\nz=107$

Step-by-step explanation:

First we can solve for x,

107 and 10x+3 is straight line which is 180 so make an equation:

$107+(10x+3)=180$

$10x +107+3=180$

$10x+110=180$

$10x=180-110$

$10x=70$

$x=70/10$

$x=7$

10(7) + 3 = 73

{CHECK: 107 + 10(7) + 3 = 180}

Now, let's find the value of z

As we have the value of x it will be easy to find z by forming an equation:

$z+73=180$

$z=180-73$

$z=107$

{CHECK: 107 + 73 = 180}

hope this helps :)

A,B and C are the vertices of a triangle,A has coordinates (4,6)
B has coordinates (2,-2)
C has coordinates (-2,-4)
D is the midpoint of AB.
E is the midpoint of AC.
prove that DE is parallel to BC.

Answers

SSS (side, side, side)

Answer:

SSS (side, side, side)

hope it helps:))!!!

A town interested in installing wind turbines to generate electricity measures the speed of the wind in the town over the course of a year. They find that most of the time, the wind speed is pretty slow, while only rarely does the wind blow very fast during a storm. What would be the best measure of the central wind speed they should report to the mayor? The mean, because the distribution of wind speeds is skewed. The median, because the distribution of wind speeds is symmetric. The mean, because the distribution of wind speeds is symmetric. The median, because the distribution of wind speeds is skewed. The proportion, because the distribution of wind speeds is skewed. The proportion, because the distribution of wind speeds is symmetric.

Answers

9514 1404 393

Answer:

The median, because the distribution of wind speeds is skewed.

Step-by-step explanation:

A few higher speeds will raise the mean. For a skewed distribution, the median may be a more appropriate measure of center.

Additional comment

From an engineering point of view, one might have to consider speeds only within some range, as the wind turbines may be shut down for speeds too low or too high. Likely the power generated is not proportional to speed, so a weighted average (of the square of speed) would probably be more useful. Unfortunately, this question does not get into such subtleties.

Need help with calculus question