PHYSICS HIGH SCHOOL

a plane is traveling at a velocity of 50 m/s. it accelerates at a constant rate of 0.5 m/s until it's velocity reaches 65 m/s. what distance did the plane cover while it was accelerating?

Answers

Answer 1

Answer:

Answer:

Displacement = 1725m

Explanation:

$t = (u-v)/(a)$

$t = (65-50)/(0.5) = 30s$

$s = ut+(1)/(2)at^(2) \ns = 50*30 + (1)/(2) *0.5*30^(2) = 1725m$

Answer 2

Answer:

Final answer:

Using the equations of motion, we find that the plane covers a distance of 850 meters while it is accelerating from a velocity of 50 m/s to 65 m/s at the rate of 0.5 m/s².

Explanation:

You're asking about a motion problem in physics that requires using the equations of motion to solve. In this case, the formula we would use is v² = u² + 2as, where 'v' is the final velocity, 'u' is the initial velocity, 'a' is acceleration, and 's' is the distance covered.

Given:
Initial velocity (u) = 50 m/s
Final velocity (v) = 65 m/s
Acceleration (a) = 0.5 m/s²

We are asked to find the distance covered (s). Rearranging the formula to find 's', we get: s = (v² - u²) / 2a

Substituting the given values, the distance covered (s) = (65² - 50²) / (2*0.5) = 850 meters. So, the plane covers a distance of 850 meters while it is accelerating.

Learn more about Equations of Motion here:

brainly.com/question/35709307

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Answers

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Explanation:

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Answers

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What must be your average speed in order to travel 350 km in 5.15 h? *66.0 km/h
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69.0 km/h

Answers

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=
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