Calculate the number of grams of CH_3COOH in the vinegar.

Answers

Answer 1

Answer: when density in g/ml
9.86ml CH3COOH (X g/1ml) = g
1.049g/ml
9.86ml (1.049g/1ml) = 10.343 g
hope it helps

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Calculate the mass of copper if 2653.8 J of copper is cooled from 155 oC to 23 oC. The specific heat of copper is 0.385 J/g*oC.

Answers

Answer:

The answer to your question is m = 52.22 g

Explanation:

Data

mass of Cu = ?

Energy = 2653.8 J

temperature 1 = 155°C

temperature 2 = 23°C

Specific heat = 0.385 J/g°C

To calculate the mass of Copper, use the formula of specific heat and solve it for mass.

Formula

Q = mC(Temperature 2 - Temperature 1)

Solve for m

m = Q / C (Temperature 2 - Temperature 1)

Substitution

m = 2653.8 / 0.385(23 - 155)

Simplification

m = 2653.8 / 0.385(132)

m = 2653.8 / 50.82

Result

m = 52.22 g

Answer:

The mass of the copper is 53.22 grams

Explanation:

Step 1: Data given

Energy = 2653.8 J

Initial temperature = 155 °C

Final temperature = 23°C

Specific heat of copper = 0.385 J/ g°C

Step 2: Calculate mass of copper

Q = m*c*ΔT

⇒ with Q = the energy = 2653.8 J

⇒ with m = the mass of copper = TO BE DETERMINED

⇒ with c= The specific heat of copper = 0.385 J/g°C

⇒ΔT = The difference in temperature = T2 - T1 = 23 - 155 = -132°C

2653.8 J = m * 0.385 J/g°C * 132 °C

m = 2653.8 / (0.385*132)

mass of copper = 52.22 grams

The mass of the copper is 53.22 grams

How does the law of conservation of matter apply to chemical equations

Answers

Since the law of conservation of matter says that no matter can be created or destroyed, chemical equations must have the same amount of matter after the reaction as there was before, making them balanced.

According to VSEPR theory, what causes water molecules to have a bent shape? A. the unusual location of the free electrons. . B. repulsive forces between specific lone pairs of electrons. . C. attraction between the fixed orbitals of the unshared pairs of oxygen electrons. . D. ionic attraction and repulsion

Answers

According to VSEPR theory, what causes water molecules to have a bent shape?

Answer: Out of all the options presented above the one that best represents what causes water molecules to have a bent shape according to VSEPR theory is answer choice B) repulsive forces between specific lone pairs of electrons. the bond angle in a water molecule is bent.

I hope it helps, Regards.

The correct answer is $\boxed{{\text{option }}\left( {\text{B}} \right)}$ that is repulsive forces between specific lone pairs of electrons.

Further Explanation:

The total number of valence electrons of ${{\text{H}}_2}{\text{O}}$ is calculated as,

Total valence electrons (TVE) = [(1) (Valence electrons of O) + (2) (Valence electrons of H)]

$\begin{aligned}{\text{Total valence electrons}}\left( {{\text{TVE}}}\right)&=\left[{\left({\text{1}}\right)\left({\text{6}}\right)+\left({\text{2}}\right)\left({\text{1}}\right)}\right]\n&=8\n\end{aligned}$

In ${{\text{H}}_2}{\text{O}}$ , the total number of valence electrons is 8. Here, oxygen forms single bond with the hydrogen atom and therefore, 2 pair of electrons are used in the formation of two single bonds with hydrogen atom. Remaining 2 pair of electrons are used to complete the octet of oxygen atom. Therefore, ${{\mathbf{H}}_{\mathbf{2}}}{\mathbf{O}}$ contains two bond pairs and two lone pairs (refer to the image attached).

According to the VSEPR theory, central atom oxygen has two bond pair with two lone pair, therefore, ${{\text{H}}_2}{\text{O}}$ has an ${\text{A}}{{\text{B}}_2}{{\text{E}}_2}$ arrangement. Therefore, these four pairs of electrons spread out as tetrahedral arrangement to minimize lone pair-lone pair and bond pair-bond pair repulsion. Since lone pairs are not considered in the shape of the molecule and therefore, the final shape of water molecule is bent-shape.

Learn more:

1. Molecular shape around the central atom in the amino acid glycine: brainly.com/question/4341225

2. Balanced chemical equation: brainly.com/question/1405182

Answer details:

Grade: Senior School

Subject: Chemistry

Chapter: Covalent bonding and molecular structure

Keywords: hybridization, water, geometry, sp3, steric number, 3, p orbital, s orbital, Lewis structure, hybridization of water, central atom, carbon, hydrogen, oxygen, shape, double bond, h2o.

What product(s) form in the following neutralization reaction? H2SO4 (aq) + Ba(OH)2 (aq) → A) 2H_20 (1) +BaSO_]4 (aq) B) 2H20 (1) +BaSO_4(s) C) 2H20 (1) D) BaSO4