What force is needed to give a 0.25-kg arrow an acceleration of 196 m/s2? A. 0.25 N B. 49 N C. 196 N D. 748 N

Answers

Answer 1

Answer: The answer is B. 49 N

Force is equal to the mass of that object multiplied by itsacceleration:

F = m × a
The unit of force is N = kg * m/s².

It is given:
m = 0.25 kg
a = 196 m/s²

F = m × a = 0.25 kg × 196 m/s² = 49 N

Answer 2

Answer:

B.49 N is the ANSWER! I took the test on k12 and it was right

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A car moving with a velocity of 20 meters/second has1.8 * 105 joules of kinetic energy. What is the mass of the car?

Answers

Kinetic energy is the product of mass and the square of the velocity of the moving object. In this case, we substitute the given data, that is 1.8 x10^5 joules = m * (20 m/s2)^2. Extracting the mass, the mass of the car therefore is equal to 450 kg

Explanation :

Given that,

Velocity of the car, v = 20 m/s

Kinetic energy of the car, $E_k=1.8* 10^5\ J$

Kinetic energy is given by :

$E_k=(1)/(2)mv^2$

$m=(2E_k)/(v^2)$

So, $m=(2* 1.8* 10^5\ J )/((20\ m/s)^2)$

m = 900 kg

Hence, the mass of the car is 900 kg

Speakers A and B are vibrating in phase. They are directly facing each other, are 6.69 m apart, and are each playing a 75.0-Hz tone. The speed of sound is 343 m/s. What is the distance from speaker A to the first point on the line between the speakers where constructive interference occurs?

Answers

Answer:

3.117 m

Explanation:

Given that:

the distance of separation between speaker A and speaker B (L) = 6.69 m

Frequency (F) = 750 -Hz tone

Velocity of speed of sound = 343 m/s

The distance from Speaker A to the first point (L₁) on the line can be calculated by using the formula:

$L_1=(L-A)/(2)$

where A = $(Velocity ofthe sound (V))/(Frequency (F))$

we have:

$L_1=(L-(V)/(F) )/(2)$

$L_1=(6.69-(343)/(750) )/(2)$

$L_1=(6.69-0.457 )/(2)$

$L_1=(6.233 )/(2)$

$L_1= 3.1165 m$

$L_1=3.117 m$

∴ the distance from speaker A to the first point on the line between the speakers where constructive interference occurs = 3.117 m

What's the first thing you should do after retrieving a boat onto a trailer?

Answers

The first thing you should do after retrieving a boat onto a trailer is to secure the boat to the trailer. This is important to ensure the boat remains stable and safe during transportation.

Here are the steps to secure the boat to the trailer:

1. Position the boat properly: Align the boat on the trailer so that it is centered and evenly distributed. Make sure the boat is positioned in such a way that the weight is balanced and evenly distributed across the trailer.

2. Attach the bow strap: The bow strap is a strong, adjustable strap that is used to secure the front (bow) of the boat to the trailer. Connect one end of the bow strap to the trailer and the other end to a secure point on the boat's bow. Make sure the strap is tight and secure, but not overly tightened to the point of damaging the boat.

3. Connect the stern tie-downs: Stern tie-downs are straps or ropes used to secure the rear (stern) of the boat to the trailer. Attach one end of each stern tie-down to the trailer and the other end to a secure point on the boat's stern. Make sure the stern tie-downs are tight and secure, but again, avoid over-tightening.

4. Check the connections: After attaching the bow strap and stern tie-downs, double-check all the connections to ensure they are properly secured. Give each strap a gentle tug to make sure it is tight and won't come loose during transport.

5. Secure loose items: Before hitting the road, secure any loose items in the boat, such as life jackets, paddles, or fishing gear. These items should be properly stowed and secured to prevent them from shifting or falling out during transportation.

Know more about trailer:

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Answer:

Set the parking brake of the towing vehicle, and put it in park (or first gear if you have a manual transmission).

Move the vessel onto the trailer far enough to attach the winch line to the bow eye of the vessel. ...

Shut off the engine, and raise the engine or outdrive.

Pull the vessel out of the water.

Explanation:

What Is Solar Radiation?

Answers

Solar Radiation is just light, or heat, from the sun (solar)

While sitting in your car by the side of a country road, you see your friend, who happens to have an identical car with an identical horn, approaching you. You blow your horn, which has a frequency of 260 Hz; your friend begins to blow his horn as well, and you hear a beat frequency of 6.0Hz .How fast is your friend approaching you?

Express your answer to two significant figures and include the appropriate units.

Answers

Answer:

$v_s =7.74\ m/s$

Explanation:

given,

Speed of sound = 343 m/s

frequency of horn = 260 Hz

the friend is approaching, the frequency is increased by the Doppler Effect. The frequency is 266 Hz

using formula

$f' = (v)/(v-v_s)f_0$

$266= (343)/(343 - v_s)(260)$

$1.023= (343)/(343 - v_s)$

$343 - v_s = 335.26$

$v_s =7.74\ m/s$

the speed of friends approaching is equal to $v_s =7.74\ m/s$

In a closed system, glider A with a mass of 0.40 kg and a speed of 2.00 m/s collides with glider B at rest with a mass of 1.20 kg. The two interlock and move off. What speed are they moving at?

Answers

The speed are they moving at will be 0.5 m/sec.Law of conservation of momentum is applied.

What is the law of conservation of momentum?

According to the law of conservation of momentum, the momentum of the body before the collision is always equal to the momentum of the body after the collision.

The given data in the problem is;

(m₁) is the mass of 1st gilder= 0.40 kg

(u₁) is the initial velocity = 2 m/s

(m₂) is the mass of 2nd gilder = 1.20 kg

(u₂) is the initial velocity of 2nd gilder = 0 m/s

(v) is the velocity after collision =.?

According to the law of conservation of momentum;

Momentum before collision =Momentum after collision

$\rm m_1u_1 + m_2u_2 = v(m_1 + m_2)\n\n(0.40* 0.25) + (1.2 * 0) = v * (0.40+1.20) \n\n 125 + 0 = v * (1250) * 125 \n\n \rm v= (0.8)/(1.6) \n\n \rm v= 0.5 \ m/sec$

Hence, the speed are they moving at will be 0.5 m/sec

To learn more about the law of conservation of momentum refer;

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Conservation of momentum.
m1*u1 + m2*u2 =m1*v1 + m2*v2
here u2=0 body at rest, v1=v2=v both interlock and move together
0..4*2+1.2*0 = 0.4*v+1.2*v
v= 0.8/1.6 = 0.5 m/sec

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