You toss a coin and roll a number cube. Find P(tail and a six).

Answers

Answer 1
Answer: there are 6 heads and 6 tails as and outcome so
H-T, H-T, H-T, H-T, H-T, H,T

Heads - 1
Heads - 2
Heads - 3
Heads - 4
Heads - 5
Heads - 6
Tails - 1
Tails - 2
Tails - 3
Tails - 4
Tails - 5
Tails - 6
We have to find the probability of tail and 6 so there is only one tail and a  6
P(tail and a six) = 1/12 = 0.08
hope it helps



Answer 2
Answer:

There will be 12 possible outcomes. So, the probability of (tail and a sic) would be equal to = 1/12

1/12 is your answer..........


Related Questions

Steve read a total of 9 books over 3 months. If Steve has read 15 books so far, how manymonths has he been with his book club? Assume the relationship is directly proportional.
Inverse operations 15x+8=6
Each Friday, the school prints 400 copies of the school newsletter. The equation c = 400w models the relationship between the number of weeks and the total number of copies of the newsletters printed. What is true of the graph of this scenario
Sam took his family to the zoo. An adult's ticket is two times the cost of a child's ticket. The total cost for two adults' tickets and three children's tickets was $28. How much do the tickets cost?
What's A(-2,-4),B(2,4)

A quiz has 50 multiple choice questions. Each question has 3 possible answers, one of which is correct. A correct answer is worth 2 points, but a point is taken off for each incorrect answer. A student answers all 25 questions by guessing at random. In each case present the problem with an appropriate box model. Find the expected value and the standard error for the sum of 25 draws. Interpret this sum in terms of the scores.

Answers

She or he would get a 75%

When Gail goes on a hike, she always packs a ratio of 20 protein bars to 15 water bottles in her backpack.Complete the statement about the ratio of protein bars to water bottles.


CLEARCHECK
For a short hike, Gail should pack
protein bars if she packs 3 water bottles.

Answers

The answer is 4 don’t listen to him

Greatest common factor of 28 and 42

Answers

Answer:

14

Step-by-step explanation:

Factors of 28: 1, 2, 4, 7, 14, 28

Factors of 42: 1, 2, 3, 6, 7, 14, 21, 42

So, the GCF is 14

What is 4 1/6 minus 2 5/6

Answers

4 (1)/(6) -2 (5)/(6) =3+1 (1)/(6) -2 (5)/(6) =3-2+ (7)/(6) - (5)/(6) =1 (2)/(6) =1 (1)/(3)
1 2/6 or 1 1/3 would b ur answer (ther both th same!!)

Solve x2 + 5x + 6 = 0

Answers

Answer:

Use the quadratic formula

   =−±2−4√2

x=−b±b2−4ac2ax=\frac{-{\color{#e8710a}{b}} \pm \sqrt{{\color{#e8710a}{b}}^{2}-4{\color{#c92786}{a}}{\color{#129eaf}{c}}}}{2{\color{#c92786}{a}}}x=2a−b±b2−4ac

   ​​

   Once in standard form, identify a, b, and c from the original equation and plug them into the quadratic formula.

   2+5+6=0

   x2+5x+6=0x^{2}+5x+6=0x2+5x+6=0

   =1

   a=1a={\color{#c92786}{1}}a=1

   =5

   b=5b={\color{#e8710a}{5}}b=5

   =6

   c=6c={\color{#129eaf}{6}}c=6

=−5±52−4⋅1⋅6√2⋅1

2

Simplify

3

Separate the equations

4

Solve

Solution

=−2=−3

Step-by-step explanation:

Answer:

x= - 2 or x = - 3

Step-by-step explanation:

x^(2) +5x+6=0\nFactorise\n(x^(2) +3x)(+2x+6)=0\nx(x+3)+2(x+3)=0\n(x+2)(x+3)=0\nx+2 = 0 or  x+3=0\nx=-2 or x=-3

An optical inspection system is used to distinguish among different part types. The probability of a correct classification of any part is 0.94. Suppose that three parts are inspected and that the classifications are independent. Let the random variable X denote the number of parts that are correctly classified.

Answers

Answer:

µ = 2.82

Variance(X) =  0.169

Step-by-step explanation:

The complete question is:

An optical inspection system is to distinguish among different part types. The probability of a correct classification of any part is 0.94. Suppose that three parts are inspected and that the classifications are independent. Let the random variable X denote the number of parts that are correctly classified. Determine:

(a) the mean

(b) variance of X .

Round your answers to three decimal places

Solution:

Part A:

First we have to find the mean.

We have,

n = 3

p = 0.94

µ = n*p

Put the values in the formula:

µ = 3*0.94

µ = 2.82

Part B:

To find the Variance of X:

Var(X) = np(1 - p)

= 2.82(1 - 0.94)

= 2.82(0.06)

= 0.1692

By rounding off:

= 0.169