Displacement vectors of 5 km north, 3 km east, 2 km south, and 3 km west combine to a total displacement of___. A. 3 km north.. B. 13 km west.. C. 0 km.. D. 2 km south..
Answers
Displacement (D) is the shortest distance from the initial to the final position.
In this example distance is 5 km north - 2 km south = 3 km north (look at the image).
Answer: Forces and Motion Unit Test (Connexus)
1. A. 3 km north
2.B. The airplane
3. C. at a particular instant
4. D. all of the above
5. C. the front seat of the car
6. C. inertia
7. C. one-third its weight on Earth's surface
8.D. gravity
9.D. all of the above
10. C. Pascal's principle
11.D. The weight of the balloon is less than the weight of the air displaced by the balloon
12.C. fluid displaced by the object
13. displacement
14.vector addition
15. positive
16 projectile
17. force,mass
18. increases
19.equally
These are the answers I put for the typed out Essay's
20. Speed is the distance traveled by an object where as, velocity is distance traveled by an object per unit time in a particular direction. Speed is a scaler quantity where as velocity is a vector quantity.
21. Acceleration is the rate of change, which means the change in velocity (vf-vi) with time(t) Where vf if the final velocity and vi is the initial velocity
22. Acceleration can be described as changes in speed, direction or both. The ball is moving at a constant speed, but its direction is changing continuously Because it's direction is changing, the ball is experiencing continuous acceleration.
23. For graph A, I can say that velocity is constant until it reaches time of 8 seconds and a constant velocity is again exhibited starting at time 12 seconds
24. For Graph B, the velocity is changing as time pass by since the slope is changing, At time of 2 seconds, graph A has greater velocity since it has a steeper slope.
25. 300 meters
26. Graph A shows greater velocity because Graph A has a steeper slope than Graph B.
27. 38 kg * 2.2 m/s=83.6 kg-m/s
28. The pressure inside the tube is greater than the pressure outside the tube because primarily of the smaller area of the tube. This increases up the pressure and let the fluid rise up.
29. The fertilizer is pushed up the tube.
Explanation: I hope this helps :)
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Bob weighs 80 pounds. He ran up the steps which rose 14 feet. Fred weighs 110 pounds. He ran up the same steps as Bob. If both boys reached the top of the 14-foot stairs at the same time, which boy had the greatest horsepower?
Answers
Answer:
73.8 N
Explanation:
The total volume is,
V =
=
= 0.1396 m
The average density is,
=
= 7.169 g/cm³
The linear mass density is,
μ = pπr²
= (7.169 x 10⁹) (π (0.3 x 10⁻³)²)
= 2.026 x 10⁻³ Kg/m
The fundamental mode of length is,
L = λ/2
λ=2L
= 2 x 0.65
= 1.3 m
The speed of the wave is,
v = λf
= 1.3 m x 147 Hz
= 1.91 m/s
The tension is,
v = √T/ц
T = ц v²
= 2.026 x 10⁻³)(1.91 m/s)²
= 73.769N
73.8N
Answers
Answers
Answer:
Elements
Explanation:
Carbon and Hydrogen are pure substances or elements. All the atoms of carbon have same number of protons. It cannot be broken into new elements.
Contrary to elements, there are compounds which are formed by the chemical bonds between two or more elements like in water. In water, Hydrogen and oxygen elements combine. All the atoms of water do not have the same number of protons. Then, there are mixtures where elements are not chemically bound. For example, air.
Answers
Given,
Mass, m=1500kg
Velocity, v=20m/s
KE= 1/2mv^2
KE=1/2 x 1,500 x 20^2
KE=300000 J
KE=300 kJ
260 m
35.8 m
848 m
Answers
Answer:
35.8 m
Explanation:
An appropriate formula is ...
The initial velocity is 0, and the acceleration due to gravity is 9.8 m/s², so the distance, d, is ...
Answers
The angular velocity of the earth is
The satellite tangential velocity is the distance from the earth times the angular velocity, which is
For meters per second, we divide by the number of seconds in an hour, which is 3600:
Final answer:
The tangential velocity of a satellite, with the same angular velocity as the Earth and 5x10^7 m distance from Earth's center, is calculated to be approximately 3650 m/s.
Explanation:
The tangential velocity of a satellite is given by the formula v = rω, where 'v' is the tangential velocity, 'r' is the radius (distance from the center of the Earth to the satellite), and 'ω' is the angular velocity. The referenced satellite's angular velocity is the same as that of the Earth, which is approximately 7.292 x 10^-5 rad/s. Given r = 5x10^7 m (the satellite's distance from Earth), we input these values into the formula:
v = (5x10^7 m)(7.292 x 10^-5 rad/s)
Upon calculation, we find that the satellite's tangential velocity is approximately 3650 m/s.
Learn more about Tangential Velocity here:
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