MATHEMATICS HIGH SCHOOL

the ratio of the circumferences of two circles is 2:3. If the large circle has a radius of 39 cm, what is the radiusof the small circle?

Answers

Answer 1

Answer:

Answer:

$r_(1) = 26$ .

Step-by-step explanation:

Given : the ratio of the circumferences of two circles is 2:3. If the large circle has a radius of 39 cm,

To find : what is the radius of the small circle.

Solution : We have given that ratio of the circumferences of two circles is 2:3.

Let $r_(2)$ is radius of larger circle and $r_(1)$ is radius of small circle .

Then circumference = $(2\pi\ r_(1) )/(2\pi\ r_(2))$ = $(2)/(3)$ .

Solving the above equation

$(r_(1))/(r_(2) )$ = $(2)/(3)$ .

We have given radius of larger circle = 39 then

$(r_(1))/(39)$ = $(2)/(3)$ .

On multiplying both sides by 39.

$r_(1) = 39 *(2)/(3)$ .

$r_(1) = 13 * 2$ .

$r_(1) = 26$ .

Therefore, $r_(1) = 26$ .

Answer 2

Answer:

C1/C2 = 2/3

2pi r1 / 2pi r2 = r1/r2 = 2/3

r1/39 = 2/3

r1 = 39*2/3 = 26

So, your answer is 26cm

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The amount 180.00 is what percent greater than 135.00

Gary has 10 coins in his pocket. 2 quarters 5 dimes 3 nickels without looking, Gary pulls 1 coin from his pocket and puts it on a table. Then, he pulls one more coin from his pocket. What is the probability that the first coin is a dime and the second coin is a nickle?

Answers

Probability that the first coin is a dime: 1/2

Probability that the second coin is a nickel: 1/3

The information given represents lengths of sides of a right triangle with c the hypotenuse. Find the correct missing length to the nearest hundredth. A calculator may be helpful.a = 20, b = 28, c = ?

A.34.41

B.35.45

C.35.88

D.34.72

Answers

The correct answer for the question that is being presented above is this one: "A.34.41." The information given represents lengths of sides of a right triangle with c the hypotenuse.

h^2 = a^2 + b^2
c^2 = 20^2 + 28^2
c^2 = 400 + 784
c^2 = 1184
c = 34.41

Which expression has a value of 1/6

Answers

Answer:

There are several expressions that have a value of 1/6. Here are a few examples:

- 2/12

- 3/18

- 4/24

- 5/30

- 10/60

These expressions all equal 1/6 when simplified.

Determine if the following lines are parallel, perpendicular, or neither. y=x-8 x+y=-5

Answers

Answer:

To determine if two lines are parallel or perpendicular, we need to examine their slopes.

First, let's rearrange the second equation, x+y=-5, to slope-intercept form (y = mx + b):

y = -x - 5

In this form, we can see that the slope of the second line is -1.

The first equation, y=x-8, is already in slope-intercept form, y = mx + b, where the slope is 1.

Comparing the slopes, we can see that the slopes of the two lines are different. The slope of the first line is 1, and the slope of the second line is -1.

Since the slopes are not equal, the lines are not parallel.

Now, let's determine if the lines are perpendicular:

Two lines are perpendicular if the product of their slopes is -1.

The slope of the first line is 1, and the slope of the second line is -1.

Since 1 * -1 = -1, the product of the slopes is -1.

Therefore, the lines y = x - 8 and x + y = -5 are perpendicular.

Step-by-step explanation:

Answer: Perpendicular

Step-by-step explanation:

Our task is to identify if these lines are parallel or not. The lines are :

$\rm{y=x-8}$
$\rm{x+y=-5}$

A good move would be to write these two equations in the same format. The easiest one is slope-intercept. Equation 1 is already in this form, but the second one isn't.

To write the second equation in slope-intercept, all we need to do is subtract x from both sides, and we get:

$\rm{y=-5-x}$

Now, switch the terms:

$\rm{y=-x-5}$

The slope of the first line is 1, and the slope of the second line is -1.

They can't be parallel, since their slopes are not the same. For them to be perpendicular, their slopes should be negative reciprocals of each other.

Is -1 the negative inverse of 1? Yes.

∴ The lines are perpendicular.

Alexis has a piece of red paper that is 4 centimeters wide. Its length is twice its width. She glues a piece of blue paper on top of the red piece measuring 3 centimeters by 7 centimeters. How many square centimeters of red paper will be visible on top?

Answers

It is given:Alexis has a piece of red paper that is 4 centimeters wide. Its length is twice its width .If length is 4cm then width = 4x2= 8cm.

Area of red paper= length x width = 4x8=32 square cm.

Alexis glues a piece of blue paper on top of the red piece measuring 3 centimeters by 7 centimeters.

Area of blue paper= 3x7=21 square cm.

Area of red paper that will be visible on top =32-21= 11 square cm.

(4x8) - (3x7) will give you what is showing of the red paper

The model shows the expression 20 + 16.Which expression is equivalent to this sum?
O4(5) + 4
4+5+4
O4(5+4)
5(4+4)

Answers

The third one. O4 (5+4)

Explanation:
4 (5+4)
4 times 5 is 20 which added to 4 times 4 which is 16 is the same thing asked before. 20+16. So the answer is the third one

Answer:

4 (5 + 4)

Step-by-step explanation:

20 + 16

= 4 (5 + 4)

= 4(5) + 4(4)

= 20 + 16

therefore, the answer is 4 (5 + 4)

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