All fossil fuels contains hydrocarbons in it. Amongst the given options hydrogen is the correct answer. Except that it contains carbon in it. Hydrocarbons are those class of compounds which contains hydrogen and carbon as element in it.
They are considered to be good fuels because they naturally bring out complete combustion as they contain hydrogen and carbon in its compound form.
B. 44 amu
C. 88 amu
D. 176 amu
E. 352 amu
The correct answer is 9.6h.
As you know, a radioactive isotope's nuclear half-life tells you exactly how much time must pass in order for an initial sample of this isotope to be halved.
Using the formula , A = Ao.
where , A- final mass after decay
Ao - initial mass
n - the number of half-lives that pass in the given period of time
Now, putting all the values, we get
1.3 × mg = 0.050 mg ×
Take the natural log of both sides of the equation to get,
㏑ = ㏑
㏑ = n. ln
n = 1.6
Since n represents the number of half-lives that pass in a given period of time, you can say that
t= 1.6 × 6 h
t = 9.6h
Hence, it will take 9.6 h until the radioactive isotope decays.
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Using the formula for radioactive decay and the provided half-life of technetium-99m, it can be calculated that it takes approximately 28.5 hours for 0.050 mg of technetium-99m to decay to a quantity of 1.3 x 10^-2 mg.
The decay of a radioactive isotope is an exponential process based on the half-life, which is, in turn, constant for any given isotope. The general formula for the remaining quantity of a radioactive isotope after a given time is given by: N = N0 (0.5) ^(t/t1/2), where (N0) is the initial amount, (N) is the remaining amount, (t) is time, and (t1/2) is the half-life of the isotope. In this case, we are given the initial quantity (N0 = 0.050 mg), the remaining quantity (N = 1.3 x 10^-2 mg), and the half-life (t1/2 = 6.0 hours).
We can solve for time (t) in the equation: N = N0 (0.5) ^(t/t1/2). Plugging in the values, we get 1.3 x 10^-2 = 0.050 x (0.5)^(t/6), and solving for t, we find that it takes approximately 28.5 hours for the technetium-99m to decay to 1.3 x 10^-2 mg.
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Plantations
Economies
Colonies
Cash Crops
Answer: cash crops
Explanation:
trust
Answer: Cash Crops
Explanation: These crops were used in the south to make loads of money before the civil war in southern plantations so they were known as cash crops
Answer:
The colors are produced by heating metal salts, such as calcium chloride or sodium nitrate, that emit characteristic colors. List of colors and elements in Fireworks: Aluminum – Aluminum is used to produce silver and white flames and sparks.
Colors in fireworks are produced by heating certain chemicals until they emit light, creating an emission spectrum. Different chemicals create different colors; for example, sodium compunds create yellow, while lithium creates crimson.
Chemicals are used to produce colors in fireworks by being heated until they are excited and emit light. This produces an emission spectrum which varies based on the element being heated. Sodium and its compounds, for example, produce a bright yellow color. This effect is seen when an electrical discharge is passed through sodium vapor. Lithium, on the other hand, creates a bright, crimson color.
Other alkali metals and their salts also add color to a flame. Even certain alkaline earth metals such as calcium, strontium, and barium give color to a flame giving shades of red and green. In certain specific engines, green and yellow flames are produced using different types of fuel and oxidant mixtures.
Thus, the specific chemicals used and how they're mixed and ignited play a critical role in the color of the resulting fireworks display.
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