An auto weighing 2,500 pounds is on a street inclined at 10 with the horizontal. Find the force necessary to prevent the car from rolling down the hill. Round your answer to the nearest whole number. Do not use a space or decimal in your answer or it will be marked wrong.

Answers

Answer 1
Answer:

Answer:

13892 lb-ft/sec^2

Step-by-step explanation:

Given that An auto weighing 2,500 pounds is on a street inclined at 10 with the horizontal.

Here acceleration due to gravity is the pulling factor against which the car should be stopped from rolling down the hill.

Weight of the car =2500 pounds

Vertical component of gravity = 32cos (90-10)=32sin 10 = 32(0.1736)

Force required = mass x acceleration

=2500x0.1736x32

=13892 lb ft/sec^2

Answer 2
Answer: Make sure your calculator is set to DEGREES and not RADIANS when performing your sinθ calculation. sin(10) = -0.54402 sin(10°) = 0.17365 You could also try using trig tables if you're unsure how to do this. So: 2500sin(10°) = 434 lb

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What number can be written as 40 + 5

Answers

a number that can written as 40 + 5 will be 45



The number that can be written as 40 +5 = 45.So the number is 45.

For the system of equations shown below2x = −y + 6
−4x + 3y = 8
What is the solution to the system of equations?

Answers

2x=-y+6
-4x+3y=8
Rewriting the equations;
y+2x=6
3y-4x=8

Multiplying equation I by 3;
3y+6x=18
3y-4x=8
Subtracting equation II from equation I;
10x=10
x=1

Replacing for x in the first equation;
2x=-y+6
2(1)=-y+6
2=-y+6
2-6=-y
-4=-y
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Michi put $7.50 worth of gas in her car. two co-workers who were riding to work with her offered to share the cost of the gas. one paid 1/2 of the total amount and the other paid 1/3 of the total amount. how much of the total amount was left

Answers

1.25.
7.50 x 1/2 = 3.75
+
7.50 x 1/3 = 2.50
= 6.25
7.50 - 6.25 = 1.25

Find the distance between point P(2, -1) and Q(10,-7)

Answers

The distance between the two points is 10.

How do you factor 8y^3+316

Answers

8y^3+316
divide both sides by 4 (smallest divisable number) just say you tried to factor 2 and 3 and they weren't whole numbers and then you tried 4 and gave you the answer :)
4(2y^3+79)

Find the coordinates of the intersection of the diagonalsof parallelogram XYZW with vertices X(2, 2), Y(3, 6), Z(10, 6), and W(9,2). Hint: what do we know about
the diagonals of a parallelogram?

Answers

The coordinates of the intersection of the diagonals  of parallelogram XYZW is at (6, 4).

Parallelogram

A parallelogram is a quadrilateral in which opposite sides are parallel and equal. The diagonals of a parallelogram bisect each other.

Given parallelogram XYZW with vertices X(2, 2), Y(3, 6), Z(10, 6), and W(9,2).

The equation of diagonal XZ is:

  • y-2=(6-2)/(10-2) (x-2)\n\ny=0.5x+1

The equation of diagonal YW is:

  • y-6=(2-6)/(9-3) (x-3)\n\ny=-(2)/(3) x+8

The point of intersection is at:

0.5x + 1 = (-2/3)x + 8

x = 6. Hence y = 4

The coordinates of the intersection of the diagonals  of parallelogram XYZW is at (6, 4).

Find out more on Parallelogram at: brainly.com/question/970600

Answer:

We know the basic facts about parallelogram is The basic formula for calculating the area of a parallelogram is the length of one side times the height of the parallelogram to that side.

Step-by-step explanation: