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Answer 1
Answer: All angles of a triangle have to equal 180 degrees. The top and bottom triangle are the same. So the first angle tells you 32 degrees. The second one has a little square which means 90 degrees. So 180 - 32 - 90 = 58.
So the angle A is 58. Since the top triangle and bottom triangle have the same angle measurement then angle C = 58 degrees.

Related Questions

How do find a missing term
4x+9y=27 written in slope intercept form
1/3 :4= x/6 Please solve!
Solve the equation using the quadratic formula : x^2-10x+25=18
∠E and ∠F are vertical angles with m∠E=8x+8 and m∠F=2x+38. What is the value of x?

How do I do these? can someone please help

Answers

-4/3x<12
multiply both sides by -3/4 to make it 1x (-4/3 times -3/4=-12/-12=1)
x<-36/4
x<-9



13c<-169
divide both sidse by 13
c<-13


What’s the answer to 3x/x+5+7/x+5

Answers

Ambiguous expression.  I think you meant:
                                 3x + 7
3x/(x+5)+7/(x+5) = --------------
                                  x+5

There's no "answer."  All you can do here is to combine the terms and simpify the resulting sum.

Solve the system 2x+3y=18 X-y=-1

Answers

Step-by-step explanation:

2x + 3y = 18

x - y = -1

therefore

x = y - 1

we use this identity in the first equation :

2(y - 1) + 3y = 18

2y - 2 + 3y = 18

5y - 2 = 18

5y = 20

y = 20/5 = 4

x = y - 1 = 4 - 1 = 3

Order numbers from least to greatest 2.8, -2 3/4, 3 1/8, -2.2

Answers

Answer:

-2.2, -2, 1/8, 3/4, 2.8, 3

Step-by-step explanation:

Answer:

-2 3/4, -2 2/5, 2.8, 3 1/8

Step-by-step explanation:

Strategy 1:

What you want to do in this question is convert everything into one unit. So either decimals, or fractions. I find it easier to do this with decimals so here is my steps to solving this.

Since -2 3/4, and 3 1/8 are already fractions we don't need to convert them.

Let's do 2.8 first.

0.8 as a fraction is 8/10, or 80/100 because one way to thing about it is 0.8 is just 0.8/1.0 and if you multiply top and bottom by ten, then you can get 0.8 = 8/10. lets simplify a bit more. 8/10 if you divide by 2 on top and bottom you get 4/5. So 2.8 = 2 4/5

We can do the same thing with -2.2.

All we have to do is do 0.2/1.0 times 10 on top and bottom and we get 2/10. Now we simplify. We can divide top and bottom by 2 without a remainder so if we do that we get 1/5 in simplified form. So -2.2 = -2 1/5

now 4/5, 1/5, 3/4 and 1/8 don't have the same base, so by using LCM (Least Common Multiple) we can figure out that the least common multiple between all of them is 40. All we have to do now is multiply top and bottom in a way that gets us 40 on both bases. (For 4/5 and 2/5 you have to multiply top and bottom by 8 to get 40 and for 3/4 you have to multiply top and bottom by 10 and for 1/8 you have to multiply the top and bottom to get 40.) Once we multiply it all out we get:

2 32/40, -2 30/40, 3 5/40, -2 8/40.

Now if you compare the negatives and the positives greatest to least you get:

Negatives: -2 8/40, -2 30/40

Positives: 2 32/40, 3 5/40

And if you put them together

-2 8/40, -2 30/40, 2 32/40, 3 5/40

Strategy 2:

If you're confident just estimate lol (When your'e at a higher level.)

Disclaimer: Doesn't work for all problems just the easy ones

Complete the following statements by writing the missing word (s).16. If two lines intersect, then their intersection is exactly ________________.

17. _____________ line can be drawn through two points.

18. If two planes intersect, then their intersection is ________________.

19. Through any three non-collinear points there exists exactly ______________.

Answers

16. one point, and only one

17. one, and only one

18. a line

19. one and only one plane
16 a point
17 one
18 a line
19 one plane

You have this information about ΔABC, ΔDEF, and ΔGHI:AB = DF

AB = GI

BC = HI

DE = HI

m∠B = m∠D = m∠I

Which triangles must be congruent?
ΔABC and ΔDEF only

ΔGHI and ΔABC only

none of the triangles
ΔABC, ΔDEF, and ΔGHI

Answers

ΔABC, ΔDEF, and ΔGHI

I think all triangles are congruent. 2 sides and 1 angle of each triangle is has the same measure. Making these triangles congruent in SAS theorem.

Answer: ΔABC, ΔDEF, and ΔGHI

Step-by-step explanation:

Given: In ΔABC, ΔDEF, and ΔGHI:

AB = DF               AB = GI

BC = HI                DE = HI

m∠B = m∠D = m∠I

In ΔABC and ΔGHI

AB = GI  [given]

BC = HI  [given]

m∠B =  m∠I  [given]

[ here m∠B and m∠I are the included angle of ΔABC and ΔGHI]

ΔABC ≅ ΔGHI [by SAS congruence postulate]

In ΔABC and ΔDEF

AB = DF [given]

BC = DE [ Since BC = HI  and DE = HI so by transitive property BC = DE]

m∠B =  m∠D  [given]

[ here m∠B and m∠D are the included angle of ΔABC and ΔDEF]

ΔABC ≅ ΔDEF [by SAS congruence postulate]

Now, since ΔABC ≅ ΔGHI and ΔABC ≅ ΔDEF

⇒  ΔGHI ≅ ΔDEF [transitive property]

Hence, all the given triangles ΔABC, ΔDEF, and ΔGHI are con gruent to each other.