MATHEMATICS HIGH SCHOOL

A colony of insects doubles every day. If the colony has 5 insects todayHow many will be present in 20 days?a.1310720
b. 2621440
c. 5242880
d. 10485760

Answers

Answer 1
Answer:

5242880 insects would be present in 20 days.

The correct answer is an option (c)

What is the formula of exponential growth?

"f(x)=ab^x,

where a is the initial value

b is the growth rate

x is time. "

For given question,

Suppose the function for the population growth is,

A(t)=A_0* b^t                    

A colony of insects doubles every day.

⇒ b = 2

The colony has 5 insects today.

⇒ A_0=5

So, the exponential growth function would be,

A(t)=5* 2^t                   ...........(1)

We need to find the number of insects after 20 days,

From equation (1),

\Rightarrow A(20)=5* 2^(20)\n\n\Rightarrow A(20)=5* 1048576\n\n\Rightarrow A(20)=5242880

Therefore, 5242880 insects would be present in 20 days.

The correct answer is an option (c)

Learn more about the exponential growth here,

brainly.com/question/11487261

#SPJ2        
Answer 2
Answer: The answer is C all I did was multiply 5*2 and repeat 20 times

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Answers

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Answers

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Answer:

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Answers

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Answer:

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