The second term of an arithmetic sequence is -39. The rule a, = a -1 + 12 can be used to find the next term of thesequence. What is the explicit rule for the arithmetic sequence?
a, = -51+12(n-1)
O a = -39+12(n-1)
O a, = 12+(-39)(n-1)
O a = 12+(-51)(n-1)

Answers

Answer 1
Answer:

Answer:

A. an = -51+12(n-1)

Step-by-step explanation:

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Answer 2
Answer:

The solution is, the explicit rule for the arithmetic sequence is

a n = -51 + ( n - 1 ) · 12 .

What is Arithmetic progression?

An arithmetic progression or arithmetic sequence is a sequence of numbers such that the difference between the consecutive terms is constant.

The nth term of AP : a_n = a + (n – 1) × d

here, we have,

given that,

a 2 = -39

a 2 = a 1 + 12

- 39 = a 1 + 12

a 1 = - 39 - 12

a 1 = - 51 ( first term )

The common difference is : d = 12

The explicit rule for the arithmetic sequence:

a n = a1 + ( n - 1 ) d

a n = -51 + ( n - 1 ) · 12

Hence, The solution is, the explicit rule for the arithmetic sequence is

a n = -51 + ( n - 1 ) · 12 .

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Which sequences are arithmetic? Select three options.–8.6, –5.0, –1.4, 2.2, 5.8, …
2, –2.2, 2.42, –2.662, 2.9282, …
5, 1, –3, –7, –11, …
–3, 3, 9, 15, 21, …
–6.2, –3.1, –1.55, –0.775, –0.3875, …

Answers

From the given options

options I, III and IV  are Arithmetic sequences.

Given :

we are given with sequences. we need to check which one is arithmetic sequence.

A sequence is arithmetic when the consecutive terms have common difference.

Lets check one by one

-8.6, -5.0, -1.4, 2.2, 5.8,......\n-5-(-8.6)=3.6\n-1.4-(-5)=3.6\n2.2+1.4=3.6\n

Its arithmetic because common difference is same 3.6

2, –2.2, 2.42, –2.662, 2.9282, …

-2.2-2=-4.2

2.42+2.2=6.62

Its not arithmetic

5, 1, –3, –7, –11, …

1-5=-4

-3-1=-4

-7+3=-4

-11+7=-3

Common difference is -4. So it Arithmetic

–3, 3, 9, 15, 21, …

3+3=6

9-3=6

15-9=6

Its Arithmetic

–6.2, –3.1, –1.55, –0.775, –0.3875, …

-3.1+6.2=3.1

-1.55+3.1=1.55

Its not Arithmetic

So, options I, III and IV  are Arithmetic sequences.

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Answer:

it should be 2nd option, 3rd, and 5th.

Step-by-step explanation:

Suppose we toss a coin 4 times. how many different sequences of outcomes are possible if order matters? (for example, hhtt is one outcome and htht is counted as a different outcome)

Answers

Solution: Each coin toss has 2 possible outcomes "Head" and "Tail". So if we flip a coin four times, the number of possible outcomes are:

2^(4) = 16 outcomes.

Let H denotes the Head and T denotes the Tail, then the 16 possible outcomes are enumerated below:

HHHH, HHHT, HHTH, HHTT, HTHH, HTHT, HTTH, HTTT,

THHH, THHT,  THTH, THTT,  TTHH,  TTHT, TTTH, TTTT


a class has a pizza party. there are 14 students that will have pizza. Each pizza has 8 slices. the teacher wants to buy the least amount of pizzas so that there are the same number of slices for each student. how many pizzas should be purchased?

Answers

The teacher could get a whole pie and five individual slices but if not then...... The teacher can get one whole pie and cut each slice into 2 but there will be a remainder of 1 slice which the teacher can have......hope this helps

Clarence is visiting his friends in Germany. Which currency will he use to pay for souvenirs?

Answers

He will use Euros because Euros are the official currency used in countries of the European Union, and Germany is a country of the European Union and uses Euros.

Answer:

Euros

Step-by-step explanation:

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If there is an 80% chance of rain and a 30% chance of wind and rain, what is the probability that it is windy, given that it is rainy? Round your answer to the nearest percent.

Answers

We suppose the total chance is 100%. So the chance of wind and rain accounts for 30%. Then it is given rainy. So the total chance will change to 80% and the chance of wind and rain remains constant. Then you can get the answer should be 30%/80%=37.5%≈38%.

Answer:38

Step-by-step explanation:

Solve: 3x + 1 = 3


With working out

Answers

3x + 1 = 3 \n  \n3x + 1-1 = 3 -1\n \n  3x = 2 \n \n (3x)/(3) = (2)/(3)  \n \n  x = (2)/(3)



3x+1 =3 \n  \n 3x  =3 -1 \n  \n 3x =2 \n  \n  \n  (3x)/(3)  =  (2)/(3)  \n  \n x  =  (2)/(3)   \n  \n \framebox[1.1\width]{Good Luck!} \par