Parallel lines have the same....A) Equation
B) y - intercept
C) X - intercept
D) slope

Answers

Answer 1
Answer: The answer is D. They have the same slope.

Related Questions

Lines m and n are parallel. The equation of line m is y=3x+3. What is the equation of line n?
The question is: 5 < b - 3
Solve for x: 3x − 24 = 81 57/3 105/3 57 105
To express the polynomial 4a^3 + a^2 - 6a^5 + 2a^3 - 4a + 1 in standard form, which terms should be combined?
Simplify the expression: 5(n − 6)

Suppose that an experiment has five possible outcomes, which are denoted {1,2,3,4,5}. Let A be the event {1,3,4} and let B be the event {2,4,5}. (Notice that we did not say that the five outcomes are equally likely: the probability distributions could be anything.) For each of the following relations, tell whether it could possibly hold. If it could, give a numerical example using a probability distribution of your own choice: if it could not, explain why not (what rule is violated)a. P(A) = P(B)
b. P(A) = 2P(B)
c. P(A) = 1 - P(B)
d. P(A) + P(B) > 1
e. P(A) - P(B) < 0
f. P(A) - P(B) > 1

Answers

Answer:

a. P(A) = P(B)

c. P(A) = 1 - P(B)

a and c are true . The rest are false.

Step-by-step explanation:

Two events A and B are said to be equally likely when one event is as likely to occur as the other. In other words each event should occur in equal number in repeated trials. For example when a fair coin is tossed the head is likely to appear as the tail, and the proportion of times each side is expected to appear is 1/2.

So when the events A= {1,3,4} B = {2,4,5} are equally likely then suppose their probability is 1/2.

a. P(A) = P(B)   True

1/2= 1/2

b. P(A) = 2P(B)  False

1/2 is not equal to 1

c. P(A) = 1 - P(B)  True

1/2= 1-1/2= 1/2

d. P(A) + P(B) > 1   False

1/2 + 1/2 is not greater than 1

e. P(A) - P(B) < 0   False

1/2-1/2= 0  is not less than 0

f. P(A) - P(B) > 1   False

1/2-1/2= 0 is not greater than 1

Final answer:

The relationships between the probabilities are evaluated and explained.

Explanation:

a. P(A) = P(B) could possibly hold if P(A) = 1/3 and P(B) = 1/3.

b. P(A) = 2P(B) could not hold, as probabilities cannot exceed 1.

c. P(A) = 1 - P(B) could possibly hold if P(A) = 2/3 and P(B) = 1/3.

d. P(A) + P(B) > 1 could possibly hold if P(A) = 1/3 and P(B) = 1/2.

e. P(A) - P(B) < 0 could not hold, as the difference between probabilities cannot be negative.

f. P(A) - P(B) > 1 could not hold, as the difference between probabilities cannot exceed 1.

Learn more about Probability here:

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Malik is buying a guinea pig. The guinea pig comes with a cage and food bowls for $ 125.00 . The expenses for feeding and caring for the guinea pig are $ 18.00 each month. How much will it cost Malik to buy and care for the guinea pig for one year?

Answers

Answer:

$341.00

Step-by-step explanation:

"$ 18.00 each month."

$18.00*$12.00=$216.00

$216.00+$125.00=$341.00

hope this helpes

be sure to give brainliest

Mrs. Smith is giving a homework pass to a student whose expression is equivalent to - i. Which expression will win the homework pass?A. i^36
B. i^37
C. i^38
D. i^39
Help pleaseee

Answers

Answer:

D. i^39

Step-by-step explanation:

If you simplify i^39, you get i^35, i^31, i^27, i^23, i^19, i^15, i^11, i^7, to i^3, which is equal to -i.

The best fit line is given by the equation y=0.5x+0.4, where y represents the distance in miles, and x represents the time for the trip in minutes.

Use the best fit line to estimate the distance for a trip that takes 20 minutes.

Enter your response in the box. Give the answer to the tenths place.

miles

Answers

Answer:

The anwser is 10.4

Step-by-step explanation:

0.5(20)+0.4

The amount of time a passenger waits at an airport check-in counter is random variable with mean 10 minutes and standard deviation of 2 minutes. Suppose a random sample of 50 customers is observed. Calculate the probability that the average waiting time waiting in line for this sample is (a) less than 10 minutes (b) between 5 and 10 minutes

Answers

Answer:

(a) less than 10 minutes

= 0.5

(b) between 5 and 10 minutes

= 0.5

Step-by-step explanation:

We solve the above question using z score formula. We given a random number of samples, z score formula :

z-score is z = (x-μ)/ Standard error where

x is the raw score

μ is the population mean

Standard error : σ/√n

σ is the population standard deviation

n = number of samples

(a) less than 10 minutes

x = 10 μ = 10, σ = 2 n = 50

z = 10 - 10/2/√50

z = 0 / 0.2828427125

z = 0

Using the z table to find the probability

P(z ≤ 0) = P(z < 0) = P(x = 10)

= 0.5

Therefore, the probability that the average waiting time waiting in line for this sample is less than 10 minutes = 0.5

(b) between 5 and 10 minutes

i) For 5 minutes

x = 5 μ = 10, σ = 2 n = 50

z = 5 - 10/2/√50

z = -5 / 0.2828427125

= -17.67767

P-value from Z-Table:

P(x<5) = 0

Using the z table to find the probability

P(z ≤ 0) = P(z = -17.67767) = P(x = 5)

= 0

ii) For 10 minutes

x = 10 μ = 10, σ = 2 n = 50

z = 10 - 10/2/√50

z = 0 / 0.2828427125

z = 0

Using the z table to find the probability

P(z ≤ 0) = P(z < 0) = P(x = 10)

= 0.5

Hence, the probability that the average waiting time waiting in line for this sample is between 5 and 10 minutes is

P(x = 10) - P(x = 5)

= 0.5 - 0

= 0.5

Find the number: 3/5of the number 33

Answers

Answer:

19.8 or 19 4/5

Step-by-step explanation:

Step 1: Set up the expression.

  • (3)/(5) * 33

Step 2: Simplify.

  • (3)/(5)*33 = (99)/(5)
  • (99)/(5) = 19(4)/(5) = 19.8

Therefore, the answer is 19.8 or 19 4/5.