PLEASE HELP ME!!!!!Invasive species spread to new environments by all of the following ways except throughA. Cargo ships
B. Wood products
C. Pet trade
D. Quarantine
E. Ornamental plants

Answers

Answer 1

Answer: It is d because corona virus

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What is the right option?

In how many ways can a subcommittee of 6 students be chosen from a committee which consists of 10 senior members and 12 junior members if the team must consist of 4 senior members and 2 junior members?

Answers

Answer:

The number of ways is 13860 ways

Step-by-step explanation:

Given

Senior Members = 10

Junior Members = 12

Required

Number of ways of selecting 6 students students

The question lay emphasis on the keyword selection; this implies combination

From the question, we understand that

4 students are to be selected from senior members while 2 from junior members;

The number of ways is calculated as thus;

Ways = Ways of Selecting Senior Members * Ways of Selecting Junior Members

$Ways = ^(10)C_4 * ^(12)C2$

$Ways = (10!)/((10-4)!4!)) * (12!)/((12-2)!2!))$

$Ways = (10!)/((6)!4!)) * (12!)/((10)!2!))$

$Ways = (10 * 9 * 8 * 7 *6!)/((6! * 4*3*2*1)) * (12*11*10!)/((10!*2*1))$

$Ways = (10 * 9 * 8 * 7)/(4*3*2*1) * (12*11)/(2*1)$

$Ways = (5040)/(24) * (132)/(2)$

$Ways = 210 * 66$

$Ways = 13860$

Hence, the number of ways is 13860 ways

How to simplify 15v-9v=18

Answers

Answer:

v=3

Step-by-step explanation:

15v-9v=18

6v = 18

6 6

v = 3

How many #5 cans of potato salad are required to serve 210 people if each can has 3 pounds 8 ounces of potato salad and each serving is 5 ounces

Answers

210 times 5 then divided by 3.8
so rounding up, 277 cans

Can someone please answer

Answers

Answer:

slope - m= −0.2

Step-by-step explanation:

What is the value of sin(t) if Cos(t)=4/5 and t is in quadrant 1

Answers

Answer:

0.6 or 3/5

Step-by-step explanation:

If cos(t) = 4/5, then, taking the arccos of both sides, t ≈ 36.86989765. Taking the sin of that gives you 0.6, or 3/5 in fraction form.

3.5 is the answer for sure

Business Week conducted a survey of graduates from 30 top MBA programs. On the basis of the survey, assume that the mean annual salary for male and female graduates 10 years after graduation is $168,000 and $117,000, respectively. Assume the standard deviation for the male graduates is $40,000 and for the female graduates it is $25,000. 1. In which of the preceding two cases, part a or part b, do we have a higher probability of obtaining a smaple estimate within $10,000 of the population mean? why? 2. What is the probability that a simple random sample of 100 male graduates will provide a sample mean more than $4,000 below the population mean?

Answers

Answer:

1. Due to the lower standard deviation, it is more likely to obtain a sample of females within $10,000 of the population mean

2. 15.87% probability that a simple random sample of 100 male graduates will provide a sample mean more than $4,000 below the population mean

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

When the distribution is normal, we use the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = (X - \mu)/(\sigma)$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = (\sigma)/(√(n))$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

1. In which of the preceding two cases, part a or part b, do we have a higher probability of obtaining a smaple estimate within $10,000 of the population mean? why?

The lower the standard deviation, the less dispersed the values are, meaning it is more likely to find values within a certain threshold of the mean.

Due to the lower standard deviation, it is more likely to obtain a sample of females within $10,000 of the population mean.

2. What is the probability that a simple random sample of 100 male graduates will provide a sample mean more than $4,000 below the population mean?

We have that:

$\mu = 168000, \sigma = 40000, n = 100, s = (40000)/(√(100)) = 4000$

This probability is the pvalue of Z when X = 168000 - 4000 = 164000. So

$Z = (X - \mu)/(\sigma)$

By the Central Limit Theorem

$Z = (X - \mu)/(s)$

$Z = (164000 - 168000)/(4000)$

$Z = -1$

$Z = -1$ has a pvalue of 0.1587

15.87% probability that a simple random sample of 100 male graduates will provide a sample mean more than $4,000 below the population mean

Final answer:

1. We have a higher probability of obtaining a sample estimate within $10,000 of the population mean when the standard deviation is smaller. In this case, the standard deviation for female graduates is smaller, so the probability is higher. 2. The probability that a simple random sample of 100 male graduates will provide a sample mean more than $4,000 below the population mean can be calculated using the z-score formula and the z-table.

Explanation:

1. In the case where the standard deviation is smaller, we have a higher probability of obtaining a sample estimate within $10,000 of the population mean. This is because a smaller standard deviation indicates less variability in the data, making it more likely for the sample mean to be closer to the population mean. In this case, the standard deviation for female graduates is smaller, so the probability is higher.

2. To calculate the probability, we need to calculate the z-score and then use the z-table. The z-score formula is z = (x - μ) / (σ / sqrt(n)), where x is the sample mean, μ is the population mean, σ is the population standard deviation, and n is the sample size. Plugging in the given values, we find the z-score and use the z-table to find the probability.

Learn more about Probability here:

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