If the class started at 11:30 A.M. and ended at 12:25 P.M., how long did the class last?

Answers

Answer 1
Answer:

Answer:

55 minutes

Step-by-step explanation:


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Solve the following equation: 28 ÷ 7 + 2 × 3 = ?      A. 24B. 18C. 10D. 12
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Give the values of a, b, and c needed to write the equation's general form. 1/4x^2 + 5 = 0

Substitution method-
r = -3s
r= 10 - 4s

Answers

r=-3s\nr=10-4s\n\n-3s=10-4s\ \ \ \ |add\ 4s\n-3s+4s=10\ns=10\n\nr=-3\cdot10=-30

Please I need help!

Answers

Answer:

16.7

Step-by-step explanation:

Following SOHCAHTOA, we see that Sine = Opposite/Hypotenuse is appropriate for this question. Since the sine of 33 is approximately 0.54, we see that the Opposite(9) / Hypotenuse(x) should be 0.54.

9 / x = 0.54

9 = 0.54x

9/0.54 = x

16.7 = x

16.7 is the correct time

This is hard for me, can someone please help? Loren solved the equation 10 = StartFraction 19 Over 9 EndFraction (149) + b for b as part of her work to find the equation of a trend line that passes through the points (1, 130) and (10, 149). What error did Loren make? She should have solved 10 = StartFraction 9 Over 19 EndFraction (149) + b for b. She should have solved 1 = StartFraction 19 Over 9 EndFraction (130) + b for b. She should have solved 149 = StartFraction 19 Over 9 EndFraction (10) + b for b. She should have solved 130 = StartFraction 9 Over 19 EndFraction (1) + b for b.

Answers

The solution is, the equations of line passes through two points:(1,130), (10.149) is:

149=19/9 (10) +b

130=19/9(1)+b

What is a straight line?

A straight line is an endless one-dimensional figure that has no width. It is a combination of endless points joined both sides of a point and has no curve.

here, we have,

for Loren to find a line passes through two points:(1,130), (10.149)

1) find slope: m=y2-y1/x2-x1 =149-130/10-1=19/9

m=19/9

to find b in the equation y=mx+b for point (1,130)

y=130, x=1, m=19/9

130=19/9(1)+b

for point (10,149)

149=19/9 (10) +b

you have two options

Hence, The solution is, the equations of line passes through two points:(1,130), (10.149) is:

149=19/9 (10) +b

130=19/9(1)+b

To learn more on Equation 0f Straight-Line click:

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Answer:

149=19/9 (10) +b

130=19/9(1)+b

Step-by-step explanation:

for Loren to find a line passes through two points:(1,130), (10.149)

1) find slope: m=y2-y1/x2-x1 =149-130/10-1=19/9

m=19/9

to find b in the equation y=mx+b for point (1,130)

y=130, x=1, m=19/9

130=19/9(1)+b

for point (10,149)

149=19/9 (10) +b

you have two options

Equation of perpendicular line:

Equation of parallel line:

Answers

1)Parallel means they have to have the same slope. Since our equation is y=2/3x+1, a line parallel to that would be(using out points) -5=2/3(-4)+b.

To find the y-intercept, solve for "b".

b=-7/3

Our equation would then be y=2/3x-7/3

2)Perpendicular lines have opposite-reciprocal slopes. our previous equation was y=2/3x+1, so our new equation would be -5=-3/2(-4)+b. Now lets solve for b.

b=-11

So our perpendicular equation would be y=-3/2x-11

Hope that was helpful. :)

Answer:

1)Parallel means they have to have the same slope. Since our equation is y=2/3x+1, a line parallel to that would be(using out points) -5=2/3(-4)+b.

To find the y-intercept, solve for "b".

b=-7/3

Our equation would then be y=2/3x-7/3

2)Perpendicular lines have opposite-reciprocal slopes. our previous equation was y=2/3x+1, so our new equation would be -5=-3/2(-4)+b. Now lets solve for b.

b=-11

So our perpendicular equation would be y=-3/2x-11

Step-by-step explanation:

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Greatest common factor of 28 and 42

Answers

Answer:

14

Step-by-step explanation:

To calculate the greatest common factor (GCF) of 28 and 42, we need to factor each number (factors of 28 = 1, 2, 4, 7, 14, 28; factors of 42 = 1, 2, 3, 6, 7, 14, 21, 42) and choose the greatest factor that exactly divides both 28 and 42, i.e., 14.

Help me please im failing math

Answers

Answer:

g(x) = x² - 5

Step-by-step explanation:

The vertex form of a parabola is:

→   y = (x - a)² + b

where (a, b) is the vertex of the parabola.

From the graph, we can identify that the vertex has been shifted down 5 units, and it has not been shifted horizontally. Therefore, we can assign the following a and b values:

  • a = 0
  • b = -5

Now, we can plug these into the vertexformequation to get the equation of the function g(x):

y = (x - 0)² + (-5)

This simplifies to:

y = x² - 5