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Answer 1
Answer: I believe the correct answer is 18
Answer 2
Answer: the answer to your problem is 5 ☺️

Related Questions

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In determining automobile-mileage ratings, it was found that the mpg (X) for a certain model is normally distributed, with a mean of 33 mpg and a standard deviation of 1.7 mpg. Find the following:__________. a. P(X<30) b. P(28c. P(X>35) d. P(X>31) e. the mileage rating that the upper 5% of cars achieve.
-5(7+2y)+15(x+2y); x=7 and y=-7
In a sample of 41 water specimens taken from a construction site, 23 contained detectable levels of lead. A 95% confidence interval for the proportion of water specimens that contain detectable levels of lead is 0.409 Required:Construct a confidence interval for the proportion of water specimens that contain detectable levels of lead.
8x + 4y= 12 2x+ y= 3

Which of the following expressions are equivalent to - -a/b

Answers

Answer:

B) -(a)/(-b)

Step-by-step explanation:

1. First, we have to know that two negatives equal positive.

2. Given the information above, -(-a)/(b) can simplify to (a)/(b).

3. Let's go through each answer choice and see which one also simplifies to (a)/(b).

A:

  • (a)/(-b)
  • -(a)/(b)

B:

  • -(a)/(-b)  
  • (a)/(b)

Therefore, the answer is B) -(a)/(-b).

In a survey of 1016 ?adults, a polling agency? asked, "When you? retire, do you think you will have enough money to live comfortably or not. Of the 1016 ?surveyed, 535 stated that they were worried about having enough money to live comfortably in retirement. Construct a 99?% confidence interval for the proportion of adults who are worried about having enough money to live comfortably in retirement.A. There is a 99?% probability that the true proportion of worried adults is between ___ and ___.

B. 99?% of the population lies in the interval between ___ and ___.

C. There is 99?% confidence that the proportion of worried adults is between ___ and ___.

Answers

Answer:

C. There is 99% confidence that the proportion of worried adults is between 0.487 and 0.567

Step-by-step explanation:

1) Data given and notation  

n=1016 represent the random sample taken    

X=535 represent the people stated that they were worried about having enough money to live comfortably in retirement

\hat p=(535)/(1016)=0.527 estimated proportion of people stated that they were worried about having enough money to live comfortably in retirement

\alpha=0.01 represent the significance level

Confidence =0.99 or 99%

z would represent the statistic

p= population proportion of people stated that they were worried about having enough money to live comfortably in retirement

2) Confidence interval

The confidence interval would be given by this formula

\hat p \pm z_(\alpha/2) \sqrt{(\hat p(1-\hat p))/(n)}

For the 99% confidence interval the value of \alpha=1-0.99=0.01 and \alpha/2=0.005, with that value we can find the quantile required for the interval in the normal standard distribution.

z_(\alpha/2)=2.58

And replacing into the confidence interval formula we got:

0.527 - 2.58 \sqrt{(0.527(1-0.527))/(1016)}=0.487

0.527 + 2.58 \sqrt{(0.527(1-0.527))/(1016)}=0.567

And the 99% confidence interval would be given (0.487;0.567).

There is 99% confidence that the proportion of worried adults is between 0.487 and 0.567

Final answer:

To build a 99% confidence interval, we first calculate our sample proportion by dividing the number of such instances by the total sample size. Next, we determine the standard error of the proportion, then our margin of error by multiplying the standard error by the Z value of the selected confidence level. Lastly, we determine the confidence interval by adding and subtracting the margin of error from the sample proportion.

Explanation:

To construct a 99% confidence interval for the proportion of adults worried about having enough money to live comfortably in retirement, we will utilize statistical methods and proportions. First, we must calculate the sample proportion. The sample proportion (p) is equal to 535 (the number who are worried) divided by 1016 (the total number of adults surveyed).

Then, we find the standard error of the proportion which we get by multiplying the square root of ((p*(1-p))/n) where n is the number of adults sampled. The margin of error is found using the Z value corresponding to the desired confidence level, in this case, 99%. Multiply the standard error by this Z value. Lastly, we construct the confidence interval by taking the sample proportion (p) ± the margin of error.

The result will give you the 99% confidence interval - meaning we are 99% confident that the true proportion of adults who are worried about having enough money to live comfortably in retirement lies within this interval.

Learn more about Confidence Interval here:

brainly.com/question/34700241

#SPJ3

Which of the following represents the value of x, the missing exponents needed to make the equation a true statement? Explain your reasoning.(Please answer! I need this ASAP)

Answers

Answer:  x = 21

======================================================

Explanation:

The exponent rules are

  • a^b * a^c = a^(b+c) .... lets call this rule 1
  • (a^b)/(a^c) = a^(b-c) .... lets call this rule 2
  • (a^b)^c = a^(b*c) ......... lets call this rule 3

The expression on the right hand side simplifies to c^(-1). We add the exponents to get this. So we're using rule 1 mentioned above.

We'll keep this in mind for later.

------------------

On the left hand side (c^5)^4 becomes c^(20) because we multiply the exponents (rule 3)

Then (c^20)/(c^x) becomes c^(20-x). We subtract exponents here (rule 2).

------------------

After using those exponent rules, the original equation turns into

c^(20-x) = c^(-1)

The bases are both c, so the exponents must be equal

20-x = -1

-x = -1-20

-x = -21

x = 21

Convert 3 over 7 into a percent.

Answers

Step-by-step explanation: To write a fraction as a percent, first remember that a percent is a ratio of a number to 100.

So to write 3/7 as a percent, we need to find a fraction

equivalent to 3/7 that has a 100 in the denominator.

We can do this by setting up a proportion.

So we have (3)/(7) = (n)/(100).

Now, we can use cross-products to find the missing value.

So we have (3)(100) which is 300 is equal to (7)(n) or 7n.

So we have the equation 300 = 7n.

Next, dividing both sides of the equation by 7, we have 42.8571 = n.

So 3/7 is equal to 42.8571/100 or 42.8571%.

Suppose the value of x varies from x = a to x = b . There are at least two ways of thinking about what percent x changed by. We'll explore two of them here. For each of the following questions, write an expression in terms of a and b to answer the question. Method 1 b is how many times as large as a ? times as large Therefore, b is what percent of a ? % Hence, if x varies from x = a to x = b , x changes by what percent?

Answers

The change in the value of x, as a percentage, is given by:

(b - a)/(a) * 100\%

The percentage change is given by the change multiplied by 100% and divided by the initial value.

In this question, x varies from x = a to x = b, which means that the initial value is a, and the change is b - a. Then, the percentage chance in the value of x is given by:

(b - a)/(a) * 100\%

A similar problem is given at brainly.com/question/24729807

Answer:

Step-by-step explanation:

i. b is how many times as large as a?

b/a

ii. Therefore, b is what percent of a?

b/a*100

iii. Hence, if x varies from x=a to x = b, x changes by what percent?

(100b)/a-100

Find the missing number of the unit rate


12/4=?/1

Answers

Answer: 3/1

Step-by-step explanation:

Your supposed to divide by 4 on the top and bottom.

12 4= 3

4 4 = 1

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