MATHEMATICS COLLEGE

PLEASE HELP!!! PLATO ALGEBRA 2

Answers

Answer 1

Answer:

Answer:

(gof) (4) = 9

Hence, option A is true.

Step-by-step explanation:

f(x)=-x³

g(x)=|1/8x -1|

(gof) (4) = g{f(4)}

First wee need to determine f(4)

f(4)=-(4)³

= -64

(gof) (4) = g{f(4)} = g(-64)

= $\left|(1)/(8)\left(-64\right)-1\right|$

$=\left|-(1)/(8)\cdot \:64-1\right|$

$=\left|-8-1\right|$

$=\left|-9\right|$

$\mathrm{Apply\:absolute\:rule}:\quad \left|-a\right|=a$

$=9$

Thus,

(gof) (4) = 9

Hence, option A is true.

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An experimenter is studying the effects of temperture, pressure, and type of catalyst on yield from a certain chemical reaction. Three different temperatures, four different pressures, and five different catalysts are under consideration.(a) If any particular experiental run involves the use of single temperature, pressure, and catalyst, how many experimental runs are possible?
(b) How many experimental runs are there that involve use of the lowest temperature and two lowest pressure?

Answers

Answer:

Step-by-step explanation:

Given that an experimenter is studying the effects of temperture, pressure, and type of catalyst on yield from a certain chemical reaction. Three different temperatures, four different pressures, and five different catalysts are under consideration.

a) Experimental runs possible if use of single temperature, pressure and catalyst is there = no of temperatures x no of pressures x no of catalysts

= $3*4*5 = 60$

b) Here pressure and temperature have no choice as lowest is selected.

no of methods = no of catalysts x 1 x1

= 5

Select all the correct answers.Which expressions are equivalent to the given expression.
y^-8y^3x^0x^-2

Answers

Answer:

$x^(-2)y^(-5)$

Step-by-step explanation:

The options are not given; however, the question can still be solved

Given

$y^(-8)y^3x^0x^-2$

Required

Simplify

Start by rewriting the expression

$y^(-8) * y^3 * x^0 * x^(-2)$

Apply the following laws of indices: $a^x * a^y = a^(x+y)$

This gives:

$y^(-8+3) * x^(0-2)$

Evaluate the exponents

$y^(-5) * x^(-2)$

$x^(-2)y^(-5)$

Hence, $x^(-2)y^(-5)$ is equivalent to $y^(-8)y^3x^0x^-2$

The expression which is equivalent to the exponential equation is $x^(-2)y^(-5)$ .

Given data:

The exponential form is an easier way of writing repeated multiplication involving base and exponents. It has a base and a power

The exponential form of a number is a way of representing a number using exponents, where the base is typically a number greater than 1.

The exponential expression is represented as $y^(-8)y^(3)x^(0)x^(-2)$ .

From the laws of exponents:

$m^(a)*m^(b)= m^(a+b)$

$(m^(a))/(m^(b))= m^(a-b)$

So, the expression is simplified as:

$y^(-8)y^(3)x^(0)x^(-2)=x^(-2)y^(-5)$

Hence, the equivalent expression is $x^(-2)y^(-5)$ .

To learn more about exponents, refer:

brainly.com/question/28966438

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ILL GIVE YOU BRAINLIEST IF YOU GET IT RIGHT AND EXPLAIN A circular walkway surrounds a fountain.The fountain alone has a diameter of 16 feet.The walkway adds an additional 4 feet to each side. What is the area of the walkway minus the area of the fountain. Use 3.14 for Pi.

Answers

Answer:

Step-by-step explanation:

$A_(circle)=\pi r^2\n\nA=\pi r_(walkway)^2-\pi r_(fountain)^2\n\nA=\pi(20^2-16^2)=244\pi$

use a calculator fo find the value

Answer:

a = 452.16 ft² area of walkway

a = -351.68 ft² area of the walkway minus the area of the fountain

Step-by-step explanation:

Area fountain

a = π16²

a = 256π

Area fountain and walkway

a = π(16 + 4)²

a = π20²

a = 400π

Area Walkway

a =400π - 256π

a = 144π

a = 144 * 3.14

a = 452.16 ft²

------------------------------

I think the Area of the Walkway is what the question should be asking for, but it asked for

"the area of the walkway minus the area of the fountain"

a = 144π - 256π

a = -112π

a = -112 * 3.14

a = -351.68

Graph the line that passes through the given point and has the given slope m. (3,10); m=-(5)/(2)

Answers

Step-by-step explanation:

given a slope and a point that the line passes through you have 2 options

Option 1: Solve for the equation of the line so you can just use that to graph the line. In this scenario it would be y=(-5/2)x - (20/13)

Option 2: plot the given point and, based on the slope, plot the next point that it crosses. In this case the next point would be (5, 7). Then you can just draw a line using these 2 points.

A 40 N force is applied to an object with a mass of 0.1 kg on a frictionless surface. What is the acceleration of the object?

Answers

The acceleration of the object is 400 m/s²

What is the acceleration of the object?

To find the acceleration of an object when a 40 N force is applied to it with a mass of 0.1 kg on a frictionless surface, we can use Newton's second law of motion, which states that the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass.

The formula for Newton's second law of motion is:

F = ma

where:

F is the net force,

m is the mass of the object,

a is the acceleration.

In this case, the net force is 40 N and the mass of the object is 0.1 kg.

Substituting these values into the formula, we get:

40 N = (0.1 kg) a

Solving for a, we get:

a = 400 m/s²

Therefore, the acceleration of the object is 400 m/s²

Read more about acceleration of object at: brainly.com/question/605631

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Answer:

400

Step-by-step explanation:

40 divided by .1

Whats 1/10 of 6,000

Answers

Answer:

600

Step-by-step explanation:

(1 / 10) * 6000

That's it!

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