(Lots of points)PLEASE HELP ME Due today at 8:59 in Texas

Answers

Answer 1

Answer:

Answer:

6.) So 8 of 24 hours is 1/3. So the percent of his time used was 33.33333 . . % (etc)

7.) The easiest way to figure out a percentage is dividing it. So if it was 30 hit out of 75 people, then divide 30 by 75. So 40% of them got hit.

Hope that helps

Logarithm

A log function is a way to find how much a number must be raised in order to get the desired number.

$a^c=b$

can be written as

$\rm{log_ab=c$

where a is the base to which the power is to be raised,

b is the desired number that we want when power is to be raised,

c is the power that must be raised to a to get b.

For example, let's assume we need to raise the power for 10 to make it 1000 in this case log will help us to know that the power must be raised by 3.

$\rm{log\ 1000 = 3$

Given to us

log a = 3,

log b = 4,

log c = -1,

Logarithm Values

log a = 3

$10^3 = a\n1000 = a\na=1000$

lob b = 4,

$10^4=b\n10000=b\nb=10,000$

log c = -1,

$10^(-1) = c\n\n(1)/(10) = c\n\nc = 0.1$

Simplifying

$\rm{log(b^7)/(a^5c^6)\n$

$=\rm{log(10,000^7)/(1,000^5* 0.1^6)\n$

$=\rm{log 10^(19)$

Hence, the value of $\rm{log\ 10^(19)$ is 19.

Answer:

Step-by-step explanation:

Given:

$(b^7)/(a^5c^6)$

log a = 3,

log b = 4,

log c = -1

Required:

Numerical value of the log expression

SOLUTION:

To solve this, we need to recall the rules to apply in each step:

$(b^7)/(a^5c^6)$

Step 1: Apply log of quotients => i.e. $log (a)/(b) = log(a) - log(b)$

$log(b^7) - (log(a^5c^6))$

Step 2: Apply log of products. i.e. log ab = log a + log b.

$log(b^7) - (log(a^5) + log(c^6))$

Step 3: Apply log of exponents. i.e. $log(a^n) = nlog(a)$ .

$7log(b) - (5log(a) + 6log(c))$

Step 4: Substitute log a = 3, log b = 4, log c = -1, into the equation.

$7(4) - (5(3) + 6(-1))$ .

$28 - (15 - 6)$ .

$28 - 9$ .

$= 19$ .

How many ways are there to add four positive odd numbers to get a sum of 22?

Answers

there are 18 ways to add four positive numbers to get 22

Nielsen Media Research wants to estimate the mean amount of time, in minutes, that full-time college students spend texting each weekday.Find the sample size necessary to estimate that mean with a 15 minute margin of error. Assume that a 96% confidence level is desired and that the standard deviation is estimated to be 112.2 minutes.

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Answer:

n=237

Step-by-step explanation:

Previous concepts

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Assuming the X follows a normal distribution

$X \sim N(\mu, \sigma=112.2)$

We know that the margin of error for a confidence interval is given by:

$Me=z_(\alpha/2)(\sigma)/(√(n))$ (1)

The next step would be find the value of $\z_(\alpha/2)$ , $\alpha=1-0.96=0.04$ and $\alpha/2=0.02$

Using the normal standard table, excel or a calculator we see that:

$z_(\alpha/2)=2.054$

If we solve for n from formula (1) we got:

$√(n)=(z_(\alpha/2) \sigma)/(Me)$

$n=((z_(\alpha/2) \sigma)/(Me))^2$

And we have everything to replace into the formula:

$n=((2.054(112.2))/(15))^2 =236.05$

And if we round up the answer we see that the value of n to ensure the margin of error required $\pm=15 min$ is n=237.

We have 30 miles of fencing which can be used to enclose a rectangular piece of grazing land along a straight portion of a river. No fence is required along the river. The grazing land will be subdivided into two sections by means of a fence parallel to the sides and perpendicular to the river. Write a function that expresses the total area in terms of the width x of the side of the grazing area perpendicular to the straight river.

Answers

Answer:

The area of the gazing land is $\frac{30x-x^2}2$ square miles.

Step-by-step explanation:

Given that, 30 miles of fencing can be used to enclose a rectangular piece of grazing land along a straight piece of river.

Let the length of the rectangular piece of gazing which is along the river be y and the width of the rectangular piece of gazing be x.

Along the river side, no fence is required.

Therefore total length of fence is = 2(x+y)-x

=2y+x

∴2y+x=30

⇒2y=30-x

$\Rightarrow y=(30-x)/(2)$

The area of the rectangular piece of gazing is = Length×width

=xy

$=x.\frac{30-x}2$

$=\frac{30x-x^2}2$ square miles.

The United States Bureau of Labor Statistics (BLS) conducts the Quarterly Census of Employment and Wages (QCEW) and reports a variety of information on each county in America. In the third quarter of 2016, the QCEW reported the total taxable earnings, in millions, of all wage earners in all 3222 counties in America. Suppose that James is an economist who collects a simple random sample of the total taxable earnings of workers in 56 American counties during the third quarter of 2016. According to the QCEW, the true population mean and standard deviation of taxable earnings, in millions of dollars, by county are ?=28.29 and ?=33.493, respectively.
Let X be the total taxable earnings, in millions, of all wage earners in a county. The mean total taxable earnings of all wage earners in a county across all the counties in James' sample is x??.
Use the central limit theorem (CLT) to determine the probability P that the mean taxable wages in James' sample of 56 counties will be less than $33 million. Report your answer to four decimal places.
P(x??<33)=
Use the CLT again to determine the probability that the mean taxable wages in James' sample of 56 counties will be greater than $30 million. Report your answer to four decimal places.
P(x??>30)=