A triangle has squares on its three sides as shown below what is the value of x

Answers

Answer 1

Answer:

Answer:

5 cm

Step-by-step explanation:

Related Questions

2. Yumi takes hour to complete 50 math problems. Eric is able to complete 48math problems in hour. Which student can complete math problems at agreater rate of problems per hour?
HELPIf m∠ABC = 72°, what is m∠DAB?
Given f(x)=x^2+3 and g(x)=x+5/x. Find (g o f)(4)
Y = - 7/6x + 1 Use the slope-intercept form to find the slope and y-intercept.
How do I find the slope

What is the slope of the line represented by the values in the table?x. y
10. 14
2. -2
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answers:

-2
$(1)/( - 2)$
$(1)/(2)$
2

Answers

Answer:the answer is 2

Step-by-step explanation:I did the quiz

Pam has 90 m of fencing to enclose an area in a petting zoo with two dividers to separate three types of young animals. The three pens are to have the same area. Express the area function for the three pens in terms of x. Determine the domain and range for the area function

Answers

Answer:

The area function is

$A=(135)/(2)x-(9)/(2)x^2$ .

The domain and range of A is $(0,15m)$ and $(0, 253.125 m^2]$ .

Step-by-step explanation:

The given length of fencing is $90 m$ .

Let the length and width of each pen be $x$ and $y$ respectively as shown in the figure.

As there are 3 pens, so, the total area,

$A= 3 xy \;\cdots (i)$

From the figure the total length of fencing is $6x+4y$ .

Here, for a significant area for the animals, $x>0$ as well as $y>0$ as $x$ and $y$ are the sides of ben.

From the given value:

$6x+4y=90\;\cdots (ii)$

$\Rightarrow y=\frac {45}{2}-(3x)/(2)$

Now, from equation (i)

$A=3x\left(\frac {45}{2}-(3x)/(2)\right)$

$\Rightarrow A=(135)/(2)x-(9)/(2)x^2\;\cdots (iii)$

This is the required area function in the terms of variable $x$ .

For the domain of area function, from equation (ii)

$x=15-(2y)/(3)$

$\Rightarrow x<15 m$ [as y>0]

So, the domain of area function is $(0,15m)$ .

For the range of area function:

As $x \rightarrow 0$ or $y\rightarrow 0$ , then $A\rightarrow 0$ [from equation (i)]

$\Rightarrow A>0$

Now, differentiate the area function with respect to $x$ .

$\frac {dA}{dx}=(135)/(2)-9x$

Equate $\frac {dA}{dx}$ to zero to get the extremum point.

$\frac {dA}{dx}=0$

$\Rightarrow (135)/(2)-9x=0$

$\Rightarrow x=(15)/(2)$

Check this point by double differentiation

$\frac {d^2A}{dx^2}=-9$

As, $\frac {d^2A}{dx^2}<0$ , so, point $x=(15)/(2)$ is corresponding to maxima.

Put this value back to equation (iii) to get the maximum value of area function. We have

$A=(135)/(2)* \frac {15}{2}-(9)/(2)* \left(\frac {15}{2}\right)^2$

$\Rightarrow A=253.125 m^2$

Hence, the range of area function is $(0, 253.125 m^2]$ .

Final answer:

The area of each pen can be expressed as A(x) = x * (90 - 2x) / 3. The domain of this function is 0 < x < 45, and the range is 0 < A(x) < 300

Explanation:

In this problem, since Pam has to divide the petting zoo into three parts, we can consider the width of each pet pen to be x and the total length of the three pens to be (90 - 2x)/3, given that the total fence is 90m and we have two fences that are x meters long separating the pens. So, the area, A of each pen can be expressed as a function of x: A(x) = x * (90 - 2x) / 3. The domain of this function, or the possible values of x, would be all the values that make the area positive, which are 0 < x < 45. For the range of the function, we analyze the quadratic function which will have a maximum value at x = 15, as the area will be largest when the space is divided evenly, so the maximum area is A(15)= 15 * (60) / 3 = 300. Therefore, the range of the function is 0 < A(x) < 300.

Learn more about Area and Functions here:

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Please help. are they Parallel, perpendicular or neither

Answers

Answer:

Neither

Step-by-step explanation:

Parallel lines don't intersect

Answer:

Neither parallel or perpendicular.

Step-by-step explanation:

For AB A(-1,-4) and B(2, 11)

x1,y1 x2,y2

Gradient = (y2 - y1)/(x2 - x1)

= (11 - (-4))/(2 - (-1))

= 15/3 = 5.

For CD C(1 , 1) and D(4 , 10)

x1, y1 x2, y2

Gradient = (y2 - y1)/(x2 - x1)

= (10 - 1)/(4 - 1)

= 9/3 = 3

from the above they are neither parallel or perpendicular.

Identify the independent and dependent variables. The number of campers decreased, so fewer counselors are needed.

A.
The independent variable is number of counselors and the dependant variable is number of campers.

B.
The independent variable is number of campers and the dependant variable is number of counselors.

Answers

The numbers of campus decreased can't be controlled by other people so it's independent.

Therefore, your answer is B. The independent variable is number of campers and the dependent variable is number of counselors.

Express the product in simplest form 8/2x+8 * x^2-16/4

Answers

From formula a^2-b^2 = (a-b)(a+b) :
x^2 - 16 = (x-4)(x+4)

In 2x+8 factor out "2", you'll reach 2(x+4). So:

$(8)/(2x+8) \cdot (x^2-16)/(4)=(8(x-4)(x+4))/(2(x+4) \cdot 4)= (8(x+4)(x-4))/(8(x+4))= \boxed{x-4}$

(In finish you delete 8(x+4) from nominator and denominator)

You arrive at an intersection with traffic lights that are not working because of a power outage

Answers

Traffic rules are set by each individual state.

In most states, an intersection where traffic lights are out of order
is treated as if it were a 4-way STOP.

But you can't depend on this answer. You MUST determine what
the law is in the state where you're driving. And if you drive out of
state, it may change for you.

Treat the outage of the traffic lights like a stop sign.

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