PHYSICS COLLEGE

Which of the following is not a risk associated with using legal drugs without medical supervision

Answers

Answer 1

Answer:

paying too much on the black market instead of getting a prescription

Explanation:

i just took the quiz

Answer 2

Answer:

Paying too much on the black market instead of getting a prescription

Explanation:

The rest of the options are risks associated with using legal drugs without medical supervision.

Related Questions

How far above the bottom of the tank could a second hole be cut so that the stream emerging from it could have the same range as for the first hole
Which of these 23rd chromosomecombinations is likeliest to result in aperson with male and female traits?ΧΟXXXXXYXY
A friend tells you that a lunar eclipse will take place the following week, and invites you to join him to observe the eclipse through a high-powered telescope he owns. You are curious what the eclipse might look like from different perspectives in space. If the moon has a diameter of 2,159.14 miles, what is the maximum distance that it could be observed by the naked eye with enough detail that you could distinguish it from other celestial bodies (assuming that you have 20/20 vision)
Sophia wanted to estimate the product 73 x 12 so she made an estimate of 70x 10. Would her estimate be greater or near the actual estimate?
If you want to play a tune on wine glasses, you’ll need to adjust the oscillation frequencies by adding water to the glasses. This changes the mass that oscillates (more water means more mass) but not the restoring force, which is determined by the stiffness of the glass itself. If you need to raise the frequency of a par- ticular glass, should you add water or remove water?

Charge q1 is placed a distance r0 from charge q2 . What happens to the magnitude of the force on q1 due to q2 if the distance between them is reduced to r0/4 ?What is the electrostatic force between and electron and a proton separated by 0.1 mm?

Answers

Answer:

The electrostatic force between and electron and a proton is $F=2.30* 10^(-20)\ N$

Explanation:

It is given that, charge $q_1$ is placed at a distance $r_o$ from charge $q_2$ . The force acting between charges is given by :

$F=(kq_1q_2)/(r_o^2)$

We need to find the force if the distance between them is reduced to $r_o/4$ . It is given by :

$F'=(kq_1q_2)/((r_o/4)^2)$

$F'=16* (kq_1q_2)/(r_o^2)$

$F'=16* F$

So, if the the distance between them is reduced to $r_o/4$ , the new force becomes 16 times of the previous force.

The electrostatic force between and electron and a proton separated by 0.1 mm or $10^(-4)\ m$ is :

$F=(kq_1q_2)/(r_o^2)$

$F=(9* 10^9* (1.6* 10^(-19))^2)/((10^(-4))^2)$

$F=2.30* 10^(-20)\ N$

So, the electrostatic force between and electron and a proton is $F=2.30* 10^(-20)\ N$ . Hence, this is the required solution.

A missile is moving 1350 m/s at a 25.0 angle

Answers

i will answer both versions assuming what you want to know is the distance it travels up from and over the ground. and how long until it reaches space. 540 meters per second up and over. to reach space which is 100km above sea level, it would take about 5400 minutes

Where is the density of the material greater, at point B or point C?
Explain why.

Answers

Answer: The density is greater at point C

Explanation: At that point

The convention current slowly cools off

A solid 0.6950 kg ball rolls without slipping down a track toward a vertical loop of radius ????=0.8950 m . What minimum translational speed ????min must the ball have when it is a height H=1.377 m above the bottom of the loop in order to complete the loop without falling off the track? Assume that the radius of the ball itself is much smaller than the loop radius ???? . Use ????=9.810 m/s2 for the acceleration due to gravity.

Answers

Answer:

The minimum transnational speed is 4.10 m/s.

Explanation:

Given that,

Mass of solid ball = 0.6950 kg

Radius = 0.8950 m

Height = 1.377 m

We need to calculate the minimum velocity of the ball at bottom of the loop to complete the track

Using formula velocity at lower point

$v_(min)=√(5gR)$

Put the value into the formula

$v_(min)=√(5*9.8*0.8950)$

$v_(min)=6.62\ m/s$

We need to calculate the velocity

Using conservation of energy

P.E at height +K.E at height = K.E at the bottom

$mgH+(1)/(2)mv^2=(1)/(2)m(√(5gR))^2$

$v^2=(√(5gR))^2-2gH$

$v^2=(6.62)^2-2*9.8*1.377$

$v^2=16.8352$

$v=√(16.8352)$

$v=4.10\ m/s$

Hence, The minimum transnational speed is 4.10 m/s.

Final answer:

The minimum translational speed the solid ball must have when it is at a height H=1.377 m above the bottom of the loop to successfully complete the loop without falling off the track is approximately 7.672 m/s. This was derived using principles of energy conservation.

Explanation:

The minimum translational speed must be sufficient enough to maintain contact with the track even at the highest point of the loop. Using the principle of energy conservation, the total energy at the height H, assuming potential energy to be zero here, should be equal to the total energy at the highest point of the loop. Here, the total energy at height H will consist of both kinetic and potential energy while at the top of the loop it consists of potential energy only. Setting these equations equal to each other: 0.5 * m * v² + m * g * H = m * g * 2R Solving the above equation for v:v = √2g (2R-H). Substituting known values henceforth gives us √2*9.81*(2*0.895-1.377) = 7.672 m/s. Hence, the ball must have a minimum translational speed of approximately 7.672 m/s at height H to complete the loop without falling.

Learn more about Minimum Translational Speed here:

brainly.com/question/13030773

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Two cars, a Porsche Boxster convertible and a Toyota Scion xB, are traveling at constant speeds in the same direction. Suppose, instead, that the Boxster is initially 170 m behind the Scion. The speed of the Boxster is 24.4 m/s and the speed of the Scion is 18.6 m/s. How much time does it take for the Boxster to catch the Scion

Answers

Answer:

It will take 29.31 seconds for the Boxster to catch the Scion

Explanation:

Given the data in the question;

lets say Toyota Scion xB is car A and Porsche Boxster convertible is B and Toyota Scion xB is car A

the distance travelled by car A is

x = $V_(A)$ × t

where $V_(A)$ is the speed of the car and t is time

the distance travelled by car B before reaching car A will be;

x + x₀ = $V_(B)$ × t

Now lets replace x by $V_(A)$ × t

( $V_(A)$ × t) + x₀ = $V_(B)$ × t

x₀ = ( $V_(B)$ × t) - ( $V_(A)$ × t)

x₀ = t ( $V_(B)$ - $V_(A)$ )

t = x₀ / ( $V_(B)$ - $V_(A)$ )

so we substitute

t = 170 m / (24.4 - 18.6)

t = 170 / 5.8

t = 29.31 s

Therefore; it will take 29.31 s for the Boxster to catch the Scion

Seven seconds after a brilliant flash of lightning, thunder shakes the house. How far was the lightning strike from the house? Seven seconds after a brilliant flash of lightning, thunder shakes the house. How far was the lightning strike from the house? Much farther away than two kilometers Much closer than one kilometer About two kilometers away About one kilometer away It is impossible to predict.

Answers

Answer:

About two kilometers away

$\rm distance=2.401\ km$

Explanation:

Given:

The time gap between the light and sound to travel to the house, $t=7\ s$

Since the clouds are formed in the troposphere region of the atmosphere which extends from 8 kilometers to 12 kilometers above the earth-surface and the velocity of light is 300000 kilometers per second so it is visible almost instantly, hence we neglect the time taken by the light to travel to the house from the clouds.

∴Distance between the lightning-strike and the house:

$\rm distance=v* t$

we have the speed of sound as: $v=343\ m.s^(-1)$

So,

$\rm distance=343* 7$

$\rm distance=2401\ m$

$\rm distance=2.401\ km$

Other Questions

A rock is pulled back in a slingshot as shown in the diagram below. The elastic on the slingshot is displaced 0.2 meters from its initial position. The rock is pulled back with a force of 10 newtons.When the rock is released, what is its kinetic energy?

Talia is on a road trip with some friends. In the first 2 hours, they travel 100 miles. Then they hit traffic and go only 30 miles in the next hour. The last hour of their trip, they drive 75 miles.Calculate the average speed of Talia’s car during the trip. Give your answer to the nearest whole number.

A large, massive object collides with a stationary, smaller object on an ice rink. If the large object transfers all of its momentum to the smaller object, which statement below describes the velocity of the smaller object after the collision? A. It will move faster than the large object was moving initially. B. It won't move. C. It will move at the same speed that the large object was moving initially. D. It will move slower than the large object was moving initially.

A 60.0-kg boy is surfing and catches a wave which gives him an initial speed of 1.60 m/s. He then drops through a height of 1.57 m, and ends with a speed of 8.50 m/s. How much nonconservative work was done on the boy