Sharon and Dani make invitations for a party.Sharon makes 27 invitations. That is 3 times as many as Dani makes.write and solve an equation to find the number of invitations Dani makes

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Answer 1

Answer:

Answer:

81 Invitations, 27 times 3 = 81

Step-by-step explanation:

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Twelve different video games showing substance use were observed and the duration of times of game play (in seconds) are listed below. The design of the study justifies the assumption that the sample can be treated as a simple random sample. Use the sample data to construct a 98% confidence interval estimate of sigma, the standard deviation of the duration times of game play. Assume that this sample was obtained from a population with a normal distribution.4,757 4,509 4,221 4,486 4,935 4,426 4,905 4,822 4,383 4,9565,043 4,038
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Morningstar tracks the total return for a large number of mutual funds. The following tableshows the total return and the number of funds for four categories of mutual funds
(Morningstar Funds500, 2008).
Type of Fund
Domestic Equity
International Equity
Specialty Stock
Hybrid Number of Funds
9191
2621
1419
2900
Total Return (%)
4.65
18.15
11.36
6.75
a. Using the number of funds as weights, compute the weighted average total return for
the mutual funds covered by Morningstar.
b. Is there any difficulty associated with using the "number of funds" as the weights in
computing the weighted average total return for Morningstar in part (a)? Discuss. What
else might be used for weights?
c. Suppose you had invested $10,000 in mutual funds at the beginning of 2007 and
diversified the investment by placing $2000 in Domestic Equity funds, $4000 in International Equity funds, $3000 in Specialty Stock funds, and $1000 in Hybrid
funds. What is the expected return on the portfolio?

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a. The weighted average total return for the mutual funds covered by Morningstar is 7.81%.

b. A better weight would be the total amount of money invested in each category.

c. The expected return on the portfolio is 12.273%.

a. To compute the weighted average total return for the mutual funds covered by Morningstar, we need to multiply the total return for each category by the number of funds in that category, sum the products, and divide by the total number of funds:

Weighted average total return = [(4.65 x 9191) + (18.15 x 2621) + (11.36 x 1419) + (6.75 x 2900)] / (9191 + 2621 + 1419 + 2900)

Weighted average total return = 7.81%

Therefore, the weighted average total return for the mutual funds covered by Morningstar is 7.81%.

b. Using the "number of funds" as weights in computing the weighted average total return for Morningstar may not be appropriate if the funds in each category have different sizes or investment amounts. In this case, a better weight would be the total amount of money invested in each category. Another possible weight could be the market capitalization of the companies in which the funds are invested.

c. To find the expected return on the portfolio, we need to multiply the amount invested in each category by the expected return for that category, sum the products, and divide by the total amount invested:

Expected return = [(0.2 x 4.65) + (0.4 x 18.15) + (0.3 x 11.36) + (0.1 x 6.75)] / (2000 + 4000 + 3000 + 1000)

Expected return = 12.273%

Therefore, the expected return on the portfolio is 12.273%.

To learn more about weighted averages;

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Test the hypotheses below with the given data. let alpha = 0.05. sample 1: average = 138.4, sigma = 6.71, sample size = 48 sample 2: average = 142.5, sigma = 8.92, sample size = 39 this is an example of

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solution: this question solution is:-

Hypothesis testing with two populations.

Graph the following function and then find the specified limits. When necessary, state that the limit does not exist.f(x)equals=left brace Start 3 By 2 Matrix 1st Row 1st Column x minus 3 2nd Column if x less than 5 2nd Row 1st Column 2 2nd Column if 5 less than or equals x less than or equals 6 3rd Row 1st Column x plus 4 2nd Column if x greater than 6 EndMatrixx−3 if x<52 if 5≤x≤6x+4 if x>6;findModifyingBelow lim With x right arrow 5limx→5 f(x)andModifyingBelow lim With x right arrow 6limx→6 f(x)

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If I'm reading the question right, you have

$f(x)=\begin{cases}x-3&\text{for }x<5\n2&\text{for }5\le x\le6\nx+4&\text{for }x>6\end{cases}$

and you have to find

$\displaystyle\lim_(x\to5)f(x)\text{ and }\lim_(x\to6)f(x)$

The limits exist if the limits from either side exist. We have

$\displaystyle\lim_(x\to5^-)f(x)=\lim_(x\to5)(x-3)=2$

$\displaystyle\lim_(x\to5^+)f(x)=\lim_(x\to5)2=2$

$\implies\displaystyle\lim_(x\to5)f(x)=2$

and

$\displaystyle\lim_(x\to6^-)f(x)=\lim_(x\to6)2=2$

$\displaystyle\lim_(x\to6^+)f(x)=\lim_(x\to6)(x+4)=10$

$\implies\displaystyle\lim_(x\to6)f(x)\text{ does not exist}$

Final answer:

The function f(x) is a piecewise function. The limit as x approaches 5 equals 2 and the limit as x approaches 6 does not exist as the values from both sides are not the same.

Explanation:

The function f(x) given is a piecewise function which is defined differently on different intervals of x.

First let's graph these three conditions:

For x < 5, f(x) = x - 3. It is a straight line that crosses the Y-axis at -3.
For 5 ≤ x ≤ 6, f(x) = 2. It is a horizontal line along the height of 2 from x=5 to x=6.
For x > 6, f(x) = x + 4. It is a straight line that crosses the Y-axis at 4.

Next, we'll find the specified limits:

limx→5 f(x): As x approaches 5, we will look at values from both sides. From the left (x < 5), it would be 5 - 3 = 2. From the right (5 ≤ x ≤ 6), f(x) = 2. The value is the same from both sides, so the limit as x approaches 5 equals 2.
limx→6 f(x): As x approaches 6, from the left (5 ≤ x ≤ 6), f(x) = 2. From the right (x > 6), it would be 6 + 4 = 10. The values are not the same from both sides, so the limit as x approaches 6 does not exist.

Learn more about Mathematical Limits here:

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HELPP !!!!!! THEY ALL GO SOMEWHERE THERE SHOULDNT BE ANYLEFT

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A.) (3, 4) = "right 3 up 4" [ Option A, C ]

B.) (-3, 4) = "left 3 up 4" [ Option B, D ]

C.) (4, -3) = "right 4 down 3" [ Option E ]

Hope this helps!

A) you pick the saultion up 4 right 3 would be so you have the 4th on the right of the first the 3 Ads onto the 4 bye devided bye 3x4 so 4 right and up three is the first box I hoped abhelped

A sample of 16 items from population 1 has a sample variance 5.8 and a sample of 21 items from population 2 has a sample variance 2.4. Test the following hypotheses at the .05 level of significance. H0: Population 1 Variance < Population 2 Variance Ha: Population 1 Variance > Population 2 Variance a. What is the p-value