A contractor building an airport needs to know how far a water tower is away fromend of the runway. Using her diagram below can you determine how far away the
water tower is?
A contractor building an airport needs to know how far - 1

Answers

Answer 1
Answer:

Answer:

B.

Step-by-step explanation:

tan(82)= X/100

100•[tan(82)]= [X/100] •100 Multiply each side by 100 to get the X by itself on the right side

X= to 711.537


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the Kelly family bought a new pet rabbit. They want to build an enclosure outside so it has lots of room to roam. They have 30 feet of leftover lumber to use. Find the length and width of the enclosure if the length is to be 4fteet longer than twice the width.

Answers

assume that since this is a simple math problem and they only mentioned legnth and witdth,
assume a perfect rectangle

so assuming they use all the lumber
30=perimiter
perimiter=legnth around=legnth+legnth+with+width

30=2legnth+2width
undistribute
30=2(legnth+width)
divide by 2
15=legnth+width
legnth is 4 more than 2width
legnth=4+2width
subsitute
15=legnth+width
15=4+2width+width
subtract 4
11=2width+width
divide by 3
11/3=width

legnth=4+2width
legnth=4+2 times (11/3)
lefnth=4+22/3
4=12/3
legnth=12/3+22/3
legnth=34/3 feet=11 and 1/3 foot

width=11/3=3 and 2/3


legnth=11 and 1/3 foot
width=3 and 2/3 foot

Helpppppppppp aasapppp

Answers

Answer:

2

Step-by-step explanation:

Convert mixed fraction to improper fraction

-2(2)/(3)=-(8)/(3)\n\n\n-1(1)/(3)=-(4)/(3)

-2(2)/(3) ÷ -1(1)/(3) =(-8)/(3) ÷ -(4)/(3)

                  =-(8)/(3)*-(3)/(4)\n\n\n=2 *1 \n\n= 2

Answer:

2

Step-by-step explanation:

Simplify the following:

(-(2 + 2/3))/(-(1 + 1/3))

(-(2 + 2/3))/(-(1 + 1/3)) = (-1)/(-1)×(2 + 2/3)/(1 + 1/3) = (2 + 2/3)/(1 + 1/3):

(2 + 2/3)/(1 + 1/3)

Put 1 + 1/3 over the common denominator 3. 1 + 1/3 = 3/3 + 1/3:

(2 + 2/3)/(3/3 + 1/3)

3/3 + 1/3 = (3 + 1)/3:

(2 + 2/3)/((3 + 1)/3)

3 + 1 = 4:

(2 + 2/3)/(4/3)

Put 2 + 2/3 over the common denominator 3. 2 + 2/3 = (3×2)/3 + 2/3:

((3×2)/3 + 2/3)/(4/3)

3×2 = 6:

(6/3 + 2/3)/(4/3)

6/3 + 2/3 = (6 + 2)/3:

((6 + 2)/3)/(4/3)

6 + 2 = 8:

(8/3)/(4/3)

Multiply the numerator by the reciprocal of the denominator, (8/3)/(4/3) = 8/3×3/4:

(8×3)/(3×4)

(8×3)/(3×4) = 3/3×8/4 = 8/4:

8/4

The gcd of 8 and 4 is 4, so 8/4 = (4×2)/(4×1) = 4/4×2 = 2:

Answer: 2

Going top to bottom label them as A, B, C, and D

Answers

i hope this helps you

5.- Andrés se comió 1/5 de los bombones de una caja y Ana 1/2 de la misma. ¿Qué fracción de bombones se comieron entre las dos?. Si quedaron 12 bombones, ¿cuántos bombones tenía la caja? (Solución)

Answers

Answer:

La fracción de bombones que se comieron entre los dos es (7)/(10)

La caja tenía 40 bombones.

Step-by-step explanation:

Sabes que Andrés se comió 1/5 de los bombones de una caja y Ana 1/2 de la misma. Para conocer la fracción de bombones que se comieron entre ambos, debes sumar las fracciones que comieron cada uno:

(1)/(5) +(1)/(2)

Para hacer suma de fracciones con distinto denominador, lo primero que hay que hacer es determinar un denominador común. Para eso debes calcular el mínimo común múltiplo (mcm) entre los denominadores.

En este caso, el mcm entre 5 y 2 es 10.

Ahora tienes que multiplicar cada numerador por el número que hayas multiplicado el denominador. Para ello, dividís el m.c.m entre el denominador inicial y el resultado se multiplica por el numerador de esa fracción:

  • 10÷5= 2 ⇒ 2*1= 2 Por lo tanto, 2 es el numerador de la primera fracción.
  • 10÷2= 5 ⇒ 5*1= 5 Por lo tanto, 5 es el numerador de la segunda fracción.

Entonces:

(1)/(5) +(1)/(2)=(2)/(10) +(5)/(10)

Ahora  simplemente sumas los denominadores:

(1)/(5) +(1)/(2)=(2)/(10) +(5)/(10)=(7)/(10)

La fracción de bombones que se comieron entre los dos es (7)/(10)

Sabes que quedaron 12 bombones en la caja. Representando 1 la cantidad total de bombones, y si se comieron 7/10 de la caja, entonces quedaron:

1-(7)/(10)

Restando de manera similar al procedimiento usado para la suma se obtiene:

1-(7)/(10)=(3)/(10)

Finalmente podes aplicar la siguiente regla de tres: si 3/10 representa los 12  bombones que quedaron en la caja, entonces en 1 (que representa la cantidad total de bombones) cuantos bombones hay?

cantidad total de bombones=(1*12)/((3)/(10) )

cantidad total de bombones=40

La caja tenía 40 bombones.

Could somebody Please help me

Answers

Correct answer is B :)
So first you work out the total Surface area (L x W of every quadrilateral, and [L x W]÷2 for triangles)
and then for the lateral surface area, you minus the area of the vertical sides, which are the 2 triangles :)

What is the equation of the line passing through the points (–5, –2) and (3, 14) in slope-intercept form?

Answers

Answer:

2x-y+2= 0

Step-by-step explanation:

(-5,-2)=(x1, y1)

(3, 14) =(x2, y2)

now,

slope(m)= y2-y1 / x2-x1

=14+2 / 3+5

= 16 /8

=2 units

passing point = (-5,-2) = x1,y1

now,

eqn of the line can be represented as,

y -y1 = m (x-x1)

y +2 = 2 (x +5)

y+2 = 2x +10

y = 2x+10-8

0 = 2x+2-y

2x-y+2 =0 is the required eqn

Answer:

licker 90000000000000000