How do you do a question like this? 80% as a fraction in simplest form.

Answers

Answer 1

Answer: Take away 0.20 of the amount.

Related Questions

Suppose monthly rental prices for a one-bedroom apartment in a large city has a distribution that is skewed to the right with a population mean of $880 and a standard deviation of $50. (a) Suppose a one-bedroom rental listing in this large city is selected at random. What can be said about the probability that the listed rent price will be at least $930? (b) Suppose a random sample 30 one-bedroom rental listing in this large city will be selected, the rent price will be recorded for each listing, and the sample mean rent price will be computed. What can be said about the probability that the sample mean rent price will be greater than $900?
An air conditioning system can circulate 320 cubic feet of air per minute. How many cubic yards of air can it circulate per minute?
What is the total interest paid on an $185,000 loan at 6.25% APR over 15 years (monthly payments)?
Which equation is the inverse of 2(x – 2)2 = 8(7 + y)?D.y=+or-sqrt28+4x so the answer is D.
Marie is reading a 271-page book. She has already read 119 pages. She uses the equation 119+8h=271 to find out how long it will take her to finish the book if she reads at about 8 pages per hour.Solve for h.

Thirty 7th graders were surveyed and asked their favorite sport. The results showed that 15 liked football, 7 liked baseball, 5 like basketball, and 3 like soccer. What generalization can not be made?Soccer is the least favorite sport.
Half of the students like football.
The students would prefer to play sports over going to school.
None of the students like tennis.

Answers

Answer:

C. The students would prefer to play sports over going to school

Step-by-step explanation:

Hope this helps :)

can u brainlist

In a survey of 269 college students, it is found that69 like brussels sprouts,
90 like broccoli,
59 like cauliflower,
28 like both Brussels sprouts and broccoli,
20 like both Brussels sprouts and cauliflower,
24 like both broccoli and cauliflower, and
10 of the students like all three vegetables.

a) How many of the 269 college students do not like any of these three vegetables?

b) How many like broccoli only?

c) How many like broccoli AND cauliflower but not Brussels sprouts?

d) How many like neither Brussels sprouts nor cauliflower?

Answers

Answer: a) 83, b) 28, c) 14, d) 28.

Step-by-step explanation:

Since we have given that

n(B) = 69

n(Br)=90

n(C)=59

n(B∩Br)=28

n(B∩C)=20

n(Br∩C)=24

n(B∩Br∩C)=10

a) How many of the 269 college students do not like any of these three vegetables?

n(B∪Br∪C)=n(B)+n(Br)+n(C)-n(B∩Br)-n(B∩C)-n(Br∩C)+n(B∩Br∩C)

n(B∪Br∪C)= $69+90+59-28-20-24+10=156$

So, n(B∪Br∪C)'=269-n(B∪Br∪C)=269-156=83

b) How many like broccoli only?

n(only Br)=n(Br) -(n(B∩Br)+n(Br∩C)+n(B∩Br∩C))

n(only Br)= $90-(28+24+10)=28$

c) How many like broccoli AND cauliflower but not Brussels sprouts?

n(Br∩C-B)=n(Br∩C)-n(B∩Br∩C)

n(Br∩C-B)= $24-10=14$

d) How many like neither Brussels sprouts nor cauliflower?

n(B'∪C')=n(only Br)= 28

Hence, a) 83, b) 28, c) 14, d) 28.

Suppose you read online that children first count to 10 successfully when they are 32 months old, on average. You perform a hypothesis test evaluating whether the average age at which gifted children first count to 10 is different than the general average of 32 months. What is the p-value of the hypothesis test? Choose the closest answer.

Answers

Answer:

$p_v =2*P(t_((35))<-1.822)=0.0885$

Step-by-step explanation:

Assuming this info from R

hist(gifted$count)

## Min. 1st Qu. Median Mean 3rd Qu. Max.

## 21.00 28.00 31.00 30.69 34.25 39.00

## Sd

## [1] 4.314887

Data given and notation

$\bar X=30.69$ represent the mean

$s=4.3149$ represent the sample standard deviation

$n=36$ sample size

$\mu_o =32$ represent the value that we want to test

$\alpha$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean is different than 32, the system of hypothesis would be:

Null hypothesis: $\mu = 32$

Alternative hypothesis: $\mu \neq 32$

If we analyze the size for the sample is > 30 but we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=(\bar X-\mu_o)/((s)/(√(n)))$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=(30.69-32)/((4.3149)/(√(36)))=-1.822$

P-value

The first step is calculate the degrees of freedom, on this case:

$df=n-1=36-1=35$

Since is a two sided test the p value would be:

$p_v =2*P(t_((35))<-1.822)=0.0885$

Kent Co. manufactures a product that sells for $60.00. Fixed costs are $285,000 and variable costs are $35.00 per unit. Kent can buy a new production machine that will increase fixed costs by $15,900 per year, but will decrease variable costs by $4.50 per unit. What effect would the purchase of the new machine have on Kent's break-even point in units?

Answers

0riginal break even point:

285000/ 60/35 = $166,250

New break even point = new fixed costs / ( selling price - variable cost/ selling price)

New break even point = 285,000 + 15,900. / ( 60-( 35-4.50)/60

300,900 / 60-30.50/60 = $612,000

The new break even point increases.

Final answer:

With the new machine, Kent Co.'s break-even point in units would decrease, from 11,400 to 10,200 units. Despite increasing fixed costs, the new machine drives down variable costs, effectively lowering the total number of units needed to cover costs.

Explanation:

The concept under consideration here is the break-even point calculation in unit terms. The break-even point (units) is calculated by dividing the total fixed costs by the contribution margin per unit, which is sales price per unit minus variable cost per unit.

Currently, Kent Co.'s break-even point can be found using its original costs:

Fixed costs: $285,000
Sales price per unit: $60
Variable cost per unit: $35
Contribution margin per unit: $60 - $35 = $25
Break-even point (units): $285,000 / $25 = 11,400 units

If Kent were to purchase the new machine, its costs would alter as follows:

New fixed costs: $285,000 + $15,900 = $300,900
New variable cost per unit: $35 - $4.50 = $30.50
New contribution margin per unit: $60 - $30.50 = $29.50
New break-even point (units): $300,900 / $29.50 = 10,200 units

Thus, purchasing the new machine would in fact lower Kent Co.'s break-even point to 10,200 units, thereby improving its cost efficiency.

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What is r in the problem d=2r

Answers

Answer:

radius

Step-by-step explanation:

Answer:

I'm not sure what you mean by "make the subject."

I can only guess that you'd like to solve this equation for r, which might be what you're looking for.

By "solve this equation for r," what I mean is to rewrite it in the form "r = [some expression]."

This is also known as "isolating." By performing operations on both sides of the equation the task is achieved.

Step-by-step explanation:

In your example we could begin by dividing both sides by 2, as demonstrated below.

d = 2r

d / 2 = (2r) / 2

d / 2 = r or reversing the equality

r = d / 2.

That didn't require many operations, but the idea is the same for more complicated equations.

Hope this helps.

Consider the following functions. f(x) = x − 3, g(x) = x2 Find (f + g)(x). Find the domain of (f + g)(x). (Enter your answer using interval notation.) Find (f − g)(x). Find the domain of (f − g)(x). (Enter your answer using interval notation.) Find (fg)(x). Find the domain of (fg)(x). (Enter your answer using interval notation.) Find f g (x). Find the domain of f g (x). (Enter your answer using interval notation.)

Answers

Answer:

$(f+g)(x)=x-3+x^2$ ; Domain = (-∞, ∞)

$(f-g)(x)=x-3-x^2$ ; Domain = (-∞, ∞)

$(fg)(x)=x^3-3x^2$ ; Domain = (-∞, ∞)

$((f)/(g))(x)=(x-3)/(x^2)$ ; Domain = (-∞,0)∪(0, ∞)

Step-by-step explanation:

The given functions are

$f(x)=x-3$

$g(x)=x^2$

$(f+g)(x)=f(x)+g(x)$

Substitute the values of the given functions.

$(f+g)(x)=(x-3)+x^2$

$(f+g)(x)=x-3+x^2$

The function $(f+g)(x)=x-3+x^2$ is a polynomial which is defined for all real values x.

Domain of (f+g)(x) = (-∞, ∞)

$(f-g)(x)=f(x)-g(x)$

Substitute the values of the given functions.

$(f-g)(x)=(x-3)-x^2$

$(f-g)(x)=x-3-x^2$

The function $(f-g)(x)=x-3-x^2$ is a polynomial which is defined for all real values x.

Domain of (f-g)(x) = (-∞, ∞)

$(fg)(x)=f(x)g(x)$

Substitute the values of the given functions.

$(fg)(x)=(x-3)x^2$

$(fg)(x)=x^3-3x^2$

The function $(fg)(x)=x^3-3x^2$ is a polynomial which is defined for all real values x.

Domain of (fg)(x) = (-∞, ∞)

$((f)/(g))(x)=(f(x))/(g(x))$

Substitute the values of the given functions.

$((f)/(g))(x)=(x-3)/(x^2)$

The function $((f)/(g))(x)=(x-3)/(x^2)$ is a rational function which is defined for all real values x except 0.

Domain of (f/g)(x) = (-∞,0)∪(0, ∞)

$(f + g)(x) = x^2 + x - 3$ , domain: all real numbers.

$(f - g)(x) = -x^2 + x - 3$ , domain: all real numbers.

$(fg)(x) = x^3 - 3x^2$ , domain: all real numbers.

$f(g(x)) = x^2 - 3$ , domain: all real numbers.

To find (f + g)(x), we need to add the functions f(x) and g(x).

The function f(x) = x - 3 and the function $g(x) = x^2.$

So, $(f + g)(x) = f(x) + g(x) = (x - 3) + (x^2).$

Expanding this equation, we get $(f + g)(x) = x^2 + x - 3.$

To find the domain of (f + g)(x), we need to consider the domain of the individual functions f(x) and g(x).

Since both f(x) = x - 3 and $g(x) = x^2$ are defined for all real numbers, the domain of (f + g)(x) is also all real numbers.

To find (f - g)(x), we need to subtract the function g(x) from f(x).

So, $(f - g)(x) = f(x) - g(x) = (x - 3) - (x^2).$

Expanding this equation, we get $(f - g)(x) = -x^2 + x - 3.$

The domain of (f - g)(x) is also all real numbers, since both f(x) and g(x) are defined for all real numbers.

To find (fg)(x), we need to multiply the functions f(x) and g(x).

So, $(fg)(x) = f(x) * g(x) = (x - 3) * (x^2).$

Expanding this equation, we get $(fg)(x) = x^3 - 3x^2.$

The domain of (fg)(x) is all real numbers, since both f(x) and g(x) are defined for all real numbers.

To find f(g(x)), we need to substitute g(x) into the function f(x).

So, $f(g(x)) = f(x^2) = x^2 - 3.$

The domain of f(g(x)) is also all real numbers, as $g(x) = x^2$ is defined for all real numbers, and f(x) = x - 3 is defined for all real numbers.

In summary:

- $(f + g)(x) = x^2 + x - 3$ , domain: all real numbers.

- $(f - g)(x) = -x^2 + x - 3$ , domain: all real numbers.

- $(fg)(x) = x^3 - 3x^2$ , domain: all real numbers.

- $f(g(x)) = x^2 - 3$ , domain: all real numbers.

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