Answers
Explanation:
The reaction expression is given as:
2H₂ + O₂ → 2H₂O
The limiting reactant is the reactant in short short supply in the given reaction.
To find the limiting reactant we use the number of moles.
Mass of H₂ = 5g
Mass of O₂ = 10g
Number of moles =
Molar mass of H₂ = 2(1) = 2g/mol
Molar mass of O₂ = 2(16) = 32g/mol
Number of moles H₂ = = 0.4mole
Number of moles O₂ = = 0.3mole
From the balanced reaction equation:
2 mole of H₂ reacts with 1 mole of O₂
0.4 mole of H₂ reacts with 0.2 mole of O₂
But we are given 0.3 moles of O₂, so the limiting reactant is H₂ because oxygen gas is in excess
Final answer:
To find the limiting reactant between hydrogen (H₂) and oxygen (O₂) for water (H₂O) formation, convert given masses to moles, compare with the stoichiometry of the balanced equation, and identify that oxygen (O₂) is the limiting reactant as it has fewer moles available than required.
Explanation:
Finding the Limiting Reactant
To determine the limiting reactant in a chemical reaction between hydrogen (H₂) and oxygen (O₂) to form water (H₂O), we must first balance the chemical equation. The balanced reaction is:
2H₂(g) + O₂(g) → 2H₂O(l)Next, we will calculate the molar masses and use them to find the moles of each reactant:
- Molar mass of H₂ = 2.02 g/mol
- Molar mass of O₂ = 32.00 g/mol
Now, we convert the given masses to moles:
- Moles of H₂ = 5.00 g H₂ × (1 mol H₂ / 2.02 g) = 2.48 mol H₂
- Moles of O₂ = 10.00 g O₂ × (1 mol O₂ / 32.00 g) = 0.313 mol O₂
According to the stoichiometry of the balanced equation, we need 2 moles of H₂ for every 1 mole of O₂ to react completely. Therefore, the moles needed for the given moles of O₂ are:
Moles of H₂ needed = 0.313 mol O₂ × (2 mol H₂ / 1 mol O₂) = 0.626 mol H₂
Since we have 2.48 mol H₂ and only need 0.626 mol to react with all the available O₂, we can see that we have excess H₂ and not enough O₂. Hence, O₂ is the limiting reactant.
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Answer:
Explanation:
Hello there!
In this case, according to the given chemical reaction, it is possible for us to realize that the 46.2 kJ of energy are given per mole of reaction, which are related to 3 moles of hydrogen; Thus, we can calculate the energy per mole of hydrogen as shown below:
Now, to calculate the total energy, we convert the grams to moles of hydrogen as shown below:
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-do not dissolve in water
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Answers
Answer:
high melting points, dissolve easily in water, conduct electricity when melted.
Explanation:
I'm pretty sure
Answers
Answer:
:0
Explanation:
One second after the Big Bang, the universe was filled with neutrons, protons, electrons, anti-electrons, photons and neutrinos.Jun 17, 2017
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Answer:
Explanation:
Hello,
In this case, since the Broglie's wavelength for bodies is defined via:
Whereas h accounts for the Planck's constant, m the mass and v the velocity, which is:
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Answers
Answer:
They produce ions when dissolved in water.
Explanation:
Acids and bases have the characteristic in common to each other. Both of them have the property of reacting and dissolving in the water. Both acids and bases lead to the production of the ions when they are placed in a water solution. Acids produce Hydrogen ions when they are dissolved in water. Bases produce hydroxide ion when they are dissolved in water.
Answers
Answer: 0.1304M
Explanation: Please see the attachments below
Final answer:
The concentration of acetic acid in the solution is 0.1304 M.
Explanation:
To determine the concentration of acetic acid in solution, we can use the concept of stoichiometry and the balanced chemical equation for the reaction between acetic acid and sodium hydroxide. The balanced equation is:
CH3CO2H + NaOH -> CH3CO2Na + H2O
From the balanced equation, we can see that 1 mole of acetic acid reacts with 1 mole of sodium hydroxide. In order to calculate the moles of acetic acid, multiply the volume of NaOH used (16.3 mL) by the molarity of NaOH (0.20 M), then divide the result by 1000 to convert mL to L:
Moles of acetic acid = (16.3 mL NaOH x 0.20 M NaOH) / 1000 = 0.00326 moles
Now, to calculate the concentration of acetic acid in the solution, we divide the moles of acetic acid by the volume of the solution in litres:
Concentration of acetic acid = (0.00326 moles) / (25.0 mL x 1 L/1000 mL) = 0.1304 M
This means that the concentration of the acetic acid in the solution is 0.13M.
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