A physics student throws a ball thrown horizontally from the top of a building with a speed of 8 m/s. The student measures the height of the building to be 15m.
Answers
Answer:
Following are the solution to the given question:
Explanation:
Please find the complete question in the attached file.
Distance:
Using the concept of motion, the answers to the question posed on the motion of a dropped ball are :
- Verticalcomponentofacceleration=-9.8m/s²
- Horizontalcomponentofacceleration=0
- InitialverticalVelocity=0
- Timetaken=1.75seconds
- Landingdistancefrombuilding=14meters
The vertical component of acceleration is denoted as :
The gravitational force acting on the ball in the downward direction has an acceleration of - 9.8 m/s². Hence,
Gravitational force only acts downwards along the vertical, hence, horizontal component of acceleration will be Zero.
then the vertical component of x, will be 0
= 0
Theinitialverticalvelocity; :
:
Thetimetaken:
S = 0.5gt² ; S=distance=15meters;g=-9.81
15 = 0.5(9.8)t²
15 = 4.9t²
t² = (15 ÷ 4.9)
t² = 3.061
t = √3.061
t=1.75seconds
LandingDistancefrombuilding:
Horizontal speed × time taken
Therefore, the ball landed 14 meters away from the building.
Learn more : brainly.com/question/13981527
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Answer: a) Balancing chemical equations
Explanation:
We are given that this student is struggling to have the "equations balanced to cancel out." This means that answer option A gives the specific problem they are facing, a) Balancing chemical equations. While they may be struggling to cancel things out, they say "I can't seem to have the equations balanced." This leads us to the specific answer.
Final answer:
The application of Hess's law involves balancing reactions and using stoichiometry to add or subtract equations, thus obtaining a desired reaction. The law states that the enthalpy change for a total process is the sum of enthalpy changes for individual steps. One can think of complex reactions as occurring in individual steps, helping to balance or cancel out equations.
Explanation:
In your question, you're grappling with the utilization of Hess's law and balancing or canceling out equations. To solve such problems with Hess's law, it's crucial first to understand what this law implies. Hess's law states that if a chemical process can be written as the sum of multiple steps, the enthalpy change of the total process equals the sum of the enthalpy changes for individual steps. This law works because enthalpy is a state function, which means that enthalpy changes depend mainly on the initial and final state, not the path through which the process passed.
For example, take the reaction of carbon with oxygen to form carbon dioxide. You can write this reaction as a direct process: C(s) + O₂(g) = CO₂(g). But you can also divide it into two steps: 1. Carbon and oxygen form carbon monoxide (C(s) + 02 (8) -> CO(g)), and 2. Carbon monoxide reacts with oxygen to form carbon dioxide (CO(g) + 1-0₂ (8) -> CO₂(g)). The reaction, when written as a sum of these steps, will give you the overall reaction, helping to balance or cancel out the equations.
The challenging aspect of Hess's law is the manipulation of equations to achieve cancellation and balance. Remember, stoichiometry rules allow us to change the quantities of reactants and products (but not their identity) when we have balanced equations. It's akin to mathematical equations, where one can multiply an entire equation by a constant to obtain an equivalent equation.
Learn more about Hess's Law here:
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Answers
Answer:
Crystal.
Explanation:
b. False