Divya wants to rent a car to drive for the weekend. The rental company has a special that allows her to rent it for $200 for the weekend, plus $0.07 per mile. Divya only has $230. Write an inequality, solve, and determine her limitations when renting.
Answers
Answer:
A maximum of 428 miles is the distance what Divya can travel.
Step-by-step explanation:
Given that:
Rent to be paid for the car in the weekend = $200
Charges to be paid per mile = $0.07
Total money available with Divya = $230
To find:
The inequality as per her limitations and solution to the problem.
Solution:
Let the number of miles for which Divya can drive = miles
Charges for one mile = $0.07
Charges for miles = $0.07
Total charges for renting and miles = Rental charges + Operational charges
Total charges for renting and miles = $200 + $0.07
These are charges must be lesser than equal to the amount of money available with Divya.
Therefore, we can write:
Subtracting 200 from both the sides:
Dividing both sides with 0.07:
Therefore, a maximum of 428 miles is the distance what Divya can travel.
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It starts down on the left and goes up on the right and intersects the x-axis at x = -2, 2, and 3.
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The graph starts from the bottom left and it keeps going to the top right.
equation cross x-axis in point x=-2, x=2, x=3
so we can choise from 1 and 3 answers:
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coefficient before x³>0 so it go up
so it ís answer 1
Answer:
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Answers
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given
4x - 10 = 3x ( subtract 3x from both sides )
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x - 10 = 0 ( add 10 to both sides )
x - 10 + 10 = 0 + 10 , that is
x = 10
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