PHYSICS COLLEGE

An ideal step-down transformer is needed to reduce a primary voltage of 120 V to 6.0 V. What must be the ratio of the number of turns in the secondary to the number of turns in the primary

Answers

Answer 1

Answer:

$N_s : N_p = 20 : 1$

Explanation:

From the question we are told that

The primary voltage is $V_p = 120 \ V$

The secondary voltage is $V_s = 6 \ V$

Generally from the transformer equation we have that

$(V_p)/(V_s) = (N_p)/(N_s)$

$(120)/(6) = (N_p)/(N_s)$

=> $(N_p)/(N_s) = 20$

Therefore the ratio of the number of turns in the secondary to the number of turns in the primary is

$N_s : N_p = 20 : 1$

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A proton and an alpha particle (helium nucleus consisting of two protons and two neutrons) are accelerated from rest across the same potential difference. Assume the proton mass and the neutron mass are roughly the same and neglect any relativistic effect. Compared to the final speed of the proton, the final speed of the alpha particle is?1. less by a factor of 22. less by a factor of √ 23. less by a factor of 44. greater by a factor of 25. the same

Answers

Answer:

option B

Explanation:

we know,

change in energy is equal to

$W = (1)/(2)m(v^2 - u^2)$

$W = (1)/(2)m(v^2 - 0^2)$

$W = (1)/(2)m v^2$

$q = (1)/(2)m v^2$

proton mass and the neutron mass are roughly the same

so,

$q \alpha m v^2$

now,

$(q_p)/(q_(\alpha)) = (m_p v_p^2)/(m_(\alpha)v_(\alpha)^2)$

$(q_p)/(q_(\alpha)) = (m_p v_p^2)/(2 m_pv_(\alpha)^2)$

we know,

mass of alpha particle is four times mass of the mass of proton.

mα = 4 m_p

$(e)/(2e) = ( v_p^2)/(4 v_(\alpha)^2)$

$( v_p^2)/(v_(\alpha)^2) = 2$

$v_(\alpha)^2 =( v_p^2)/(2)$

$v_(\alpha)=( v_p)/(√(2))$

less by a factor of √2

Hence, the correct answer is option B

Which of the following is not a risk associated with using legal drugs without medical supervision

Answers

Answer:

paying too much on the black market instead of getting a prescription

Explanation:

i just took the quiz

Answer:

Paying too much on the black market instead of getting a prescription

Explanation:

The rest of the options are risks associated with using legal drugs without medical supervision.

The position of a particle as a function of time is given by x = (2.0 m/s)t + (-3.0 m/s2)t2. (a) plot x-versus-t for time from t = 0 to t = 1.0 s. (do this on paper. your instructor may ask you to turn in this plot.) this answer has not been graded yet. (b) find the average velocity of the particle from t = 0.45 s to t = 0.55 s. m/s (c) find the average velocity from t = 0.49 s to t = 0.51 s.

Answers

Part a)

Equation of position with time is given as

$x = (2.0 m/s)t + (-3.0 m/s2)t^2$

since this equation is a quadratic equation

so it will be a parabolic graph between t = 0 to t = 1

part b)

at t = 0.45 s

$x = 2* 0.45 - 3 * 0.45^2$

$x_1 = 0.2925 m$

at t = 0.55 s

$x = 2* 0.55 - 3*0.55^2$

$x_2 = 0.1925$

now the displacement is given as

$d = x_2 - x_1$

$d = 0.1925 - 0.2925 = -0.1 m$

so the average velocity is given by

$v = (d)/(t)$

$v = \frac{-0.1}{0.1) = -1 m/s$

part c)

at t = 0.49 s

$x = 2* 0.49 - 3 * 0.49^2$

$x_1 = 0.2597 m$

at t = 0.51 s

$x = 2* 0.51 - 3*0.51^2$

$x_2 = 0.2397 m$

now the displacement is given as

$d = x_2 - x_1$

$d = 0.2397 - 0.2597 = -0.02 m$

so the average velocity is given by

$v = (d)/(t)$

$v = \frac{-0.02}{0.02) = -1 m/s$

By using a 2-meter stick (like the one in lab) marked in millimeters and a stopwatch that measures to 1/100h of a second, you decide to measure the speed of a motorized toy car that travels at a constant velocity. You measure out a 162.0cm interval with the 2-meter stick and time how long it takes the car to travel that distance using the stopwatch. Repeating the ex 2.95 s Calculate the average speed of the toy car What are the absolute and relative uncertainties of the distance and time measurements? Which measurement is more uncertain? Use the weakest link rule to determine the relative and absolute uncertainty in your speed estimation. Explain why it is necessary to calculate relative uncertainties. Why is absolute uncertainty not enougn ent 5 times you get the following time data: 3.11 s 3.15 s 2.84 s 2.97 s

Answers

Answer:

Explanation:

The average speed of a body is defined as the ratio between total distance and total time

v = dx / dt

v = 162.0 / 2.95

v = 54.9 m / s

The absolute errors (uncertainties) of the distance and time measurements as measured with instruments are the errors of the instruments

Δx = 0.1 cm

Δt = 0.01 s

Relative errors (uncertainties) are the absolute errors between the measured value

Er = Δx /x

Er = 0.1 / 162.0

Er = 6.2 10⁻⁴ length

Er = 0.01 / 2.95

Er = 3.4 10⁻³ time

The most uncertain measure is the time to have a greater relative error

Let's calculate the relative speed error

Δv / v = dv / dx dx + dv / dt dt

dv / dx = 1 / t

dv / dt = x (-1 / t²)

Er = Δv / v = 1 / t Δx + x / t² Δt

Er = 0.1 / 2.95 + 162.0/2.95² 0.01

Er = 0.034 + 0.19

Er = 0.22

We can observe that the relative error of time is much higher than the relative error of distance, so to reduce the speed error, time must be measured with much more precision

Absolut mistake

Er = Δv / v

Δv = Er v

Δv = 0.22 54.9

Δv = 12 cm / s

v± Δv = (5 ±1 ) 10 cm/s

When calculating the relative uncertainty, it is known which magnitude should be more precisely medical to reduce the total error of a derived magnitude

Enter your answer in the provided box. In water conservation, chemists spread a thin film of certain inert materials over the surface of water to cut down on the rate of evaporation of water in reservoirs. This technique was pioneered by Benjamin Franklin three centuries ago. Franklin found that 0.10 mL of oil could spread over the surface of water of about 32.0 m2 in area. Assuming that oil forms a monolayer (that is, a layer that is only one molecule thick) estimate the length of each oil molecule in nanometers. Assume that oil molecules are roughly cubic. (1 nm = 1 × 10−9 m)

Answers

Answer:

≅3.2 nm

Explanation:

Using the converter units as know for this case that:

1 ml is 1 cubic centimeter ⇒ 0.1 ml is 0.1 cubic centimeters

32.0 m² so :

32.0 m² *100 *100 cm² ⇒ 0.1 / ( 32.0 * 100 *100 ) = 100,000,000 * 0.1 / (32.0 * 100 * 100 ) nm

v = 100/32.0 nm = 3.125 nm thick.

v ≅3.2 nm

As oil is one molecule thick and the molecules are cubic, length of each oil is 3.2 nm

What would the position of arrows on a target need to be to illustrate measurements that are neither accurate nor precise

Answers

Answer:

The position of the arrows will not be on the target i.e. outside the bull's eye, neither will they be close to one another (widely scattered).

Explanation:

Accuracy refers to the closeness of a measurement to an actual or accepted value while precision refers to the closeness of measurements to one another.

Using archery as an illustration of precision and accuracy, measurements (arrows) that are neither accurate not precise are those arrows that will be far away or outside the bull's eye region (target) of the board and also far apart from one another.

In a nutshell, the arrows will be distant from the bull's eye or target (not accurate) and also distant from one another (not precise).

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Suppose that we are designing a cardiac pacemaker circuit. The circuit is required to deliver pulses of 1ms duration to the heart, which can be modeled as a 500 ohm resistance. The peak amplitude of the pulses is required to be 5 V. However, the battery delivers only 2.5 V. Therefore, we decide to charge two equal value capacitors in parallel from the 2.5V battery and then switch the capacitors in series with the heart during the 1ms pulse. What is the minimum value of the capacitances required so the output pulse amplitude remains between 4.9 V and 5.0 V throughout its 1ms duration