MATHEMATICS HIGH SCHOOL

Leo can run a mile in 7.45 minutes. At that rate, how long would it take for him to run a marathon (we let a marathon equal 26.2 miles)?

Answers

Answer 1
Answer:

multi subs AND THIS AND THAT AND THIS AND THAT
Answer 2
Answer:

Answer:

195.19 min

Step-by-step explanation:

7.45 x 26.2 = 195.19

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The graph of an inequality has an open circle at 3.9, and the ray moves to the right. What inequality is graphed?x > 3.9
x ≤ 3.9
x < 3.9
x ≥ 3.9

Answers

The answer would be x> 3.9

Answer:

x>3.9

Step-by-step explanation:

If I read 52 pages in 2 hrs and Tim reads 1/4 more in 2 and1/2 hr. who read faster?

Answers

They read at the same speed
If we split the time where you read into half hour intervals we would have
13 pages per 30 minutes
and since (1)/(4)* 52= 13 and the time added is 30 minutes we know that You and Tim read at the same speed. 
so Tim read 13 pages =1/4 of 52 pages in (2 and 1/2 hr) - (2hrs) = 1/2 hr
So Tim will read 26 pages in 1 hr and  that means Tim read 52 pages in 2 hrs, the same with You! The answer its that bouth read in the same time.

Verify: (sinx+cosx)^2=1+sin(2x)

Answers

(sinx + cosx)² = 1 + sin(2x)

Since (a + b)² = (a + b)(a+b):
(sinx + cosx)(sinx + cosx) = 1 + sin(2x)

Now, multiply each member with another:
sin²x + sinxcosx + sinxcosx + cos²x = 1 + sin(2x)
⇒   sin²x + cos²x + 2sinxcosx = 1 + sin(2x)

Since sin²x + cos²x = 1 (Pithagorean identity):
1 + 2sinxcosx = 1 + sin(2x)

Since 1 + 2sinxcosx = 1 + sin(2x) (Double-angle identity):
1 + sin(2x) = 1 + sin(2x)

How would I solve these? 

(-3xy)³ (-x³)

and

(-9b²a³)² (3³b)²

Answers

(-9b^2a^3)^2 \cdot (3^3b)^2 = (-9)^2\cdot(b^2)^2 \cdot (a^3)^2 \cdot (3^3)^2\cdot (b)^2 = \n \n= 81\cdot b^4\cdot a^6 \cdot 3^6\cdot b ^2 = 3^4 \cdot a^6 \cdot b^4\cdot 3^6\cdot b ^2 =\n \n= 3^(4+6) \cdota^(6) \cdot b ^(4+2) = 3^(10) \cdot a^(6) \cdot b ^6
(-3xy)^3(-x^3)=(-3)^3x^3y^3\cdot(-x^3)=-27x^3y^3\cdot(-x^3)=27x^6y^3\n\n\n(-9b^2a^3)^2\cdot(3^3b^2)^2=(-3^2a^3b^2)^2\cdot(3^3b^2)^2=3^(2\cdot2)a^(3\cdot2)b^(2\cdot2)\cdot3^(3\cdot2)b^(2\cdot2)\n\n=3^4a^6b^4\cdot3^6b^4=3^(4+6)a^6b^(4+4)=3^(10)a^6b^8

Find 2 consecutive integers that the sum is 149?

Answers

The two consecutive integers that the sum is 149 are 74 and 75.


What is an expression?

Expression in maths is defined as the collection of numbers variables and functions by using signs like addition, subtraction, multiplication, and division.

Numbers (constants), variables, operations, functions, brackets, punctuation, and grouping can all be represented by mathematical symbols, which can also be used to indicate the logical syntax's order of operations and other features.

Given that the number is 149. The two consecutive integers can be calculated as below,

Suppose the two consecutive integers are x and ( x + 1 ).

x + ( x + 1 ) = 149

2x + 1 = 149

2x = 148

x = 148 / 2

x = 74

The second integer would be,

x + 1 = 74 + 1 = 75

To know more about an expression follow

brainly.com/question/11766750

#SPJ2
Write an equation. To do this, make one integer equal to x, and the other equal to x+1. Set these equal to 149. Your equation should read x+(x+1)=149. Solve. To do this, add the two x's together. Your equation is now 2x+1=149. Get your x's alone. First, subtract 1 from both sides. Now the equation is 148=2x. Divide both sides by 2 to get x alone. You now have x=74. Plug this value back into the original equation to find your value for the other integer, and you have the two integers as 74 and 75. Hope this helps!

What number is 6.1% of 60

Answers

6.1\%\cdot60=0.061\cdot60=3.66
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