Do any body know the summary for The Christmas carol act 2 scene 2?

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Answer 1

Answer:

Answer:

Act 2 of the Christmas Carol begins with Scrooge getting a visit from the ghost of Christmas present. This spirit is a jolly man filled with happiness and laughter. ... Scrooge sees Bob Cratchit's crippled son, Tiny Tim, who shows so much kindness towards everyone that it warms Scrooge's heart.

Step-by-step explanation:

your welcome

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What’s the answer for this question

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Answer:

128

Step-by-step explanation:

you do 16 x 16 (256) and then divide it by 2

Solve each equation by factoring.
1) a^2- 9a + 14 = 0

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it’s c [7,2] for sure! :)

Two equations are given below:a – 3b = 4
a = b – 2

What is the solution to the set of equations in the form (a, b)? (5 points)

(–2, –2)
(–3, –1)
(–9, –7)
(–5, –3)

Answers

a - 3b = 4
a = b -2

(b - 2) - 3b = 4
b - 2 - 3b = 4
-2b = 4 + 2
-2b = 6
b = 6/-2
b = -3

a = b - 2
a = -3 -2
a = -5

to check: a = -5 ; b = -3 ⇒ (-5,-3)
a - 3b = 4
-5 - 3(-3) = 4
-5 + 9 = 4
4 = 4

Which inequality represents this sentence?Seven times six is less than or equal to nine times five.

7 • 6 ≥ 9 • 5

7 • 6 < 9 • 5

7 • 6 > 9 • 5

7 • 6 ≤ 9 • 5

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(7)(6)≥(9)(5)42≱45False

What is (4-5a)^2 - a (2a -3)

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23a²+-37a+16 is the answer

3a^2+13 should be correct

Why can't you factor 2cosx^2+sinx-1=0 ?

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$2cos^2x+sinx-1=0\n\n2(1-sin^2x)+sinx-1=0\n\n2-2sin^2x+sinx-1=0\n\n-2sin^2x+sinx+1=0\n\n-2sin^2x+2sinx-sinx+1=0\n\n-2sinx(sinx-1)-1(sinx-1)=0\n\n(sinx-1)(-2sinx-1)=0\iff sinx-1=0\ or\ -2sinx-1=0\n\nsinx=1\ or\ -2sinx=1\n\nsinx=1\ or\ sinx=-(1)/(2)\n\nx=(\pi)/(2)+2k\pi\ or\ x=-(\pi)/(6)+2k\pi\ or\ x=(7\pi)/(6)+2k\pi\ where\ k\in\mathbb{Z}$

$2cosx^2+sinx-1=2(1-sin^2x)+snx-1=\n\n=2(1-sinx)(1+sinx)-(1-sinx)=(1-sinx)[2(1+sinx)-1]=\n\n=(1-sinx)(2+2sinx-1)=(1-sinx)(1+2sinx)\n\n2cosx^2+sinx-1=0\ \ \ \Leftrightarrow\ \ \ (1-sinx)(1+2sinx)=0\n\n1-sinx=0\ \ \ \ \ or\ \ \ \ \ 1+2sinx=0\n\n1)\ \ \ 1-sinx=0\ \ \ \Rightarrow\ \ \ sinx=1\ \ \ \Rightarrow\ \ \ x= ( \pi )/(2) +2k \pi ,\ \ \ k\in I\n\n$

$2)\ \ \ 1+2sinx=0\ \ \ \ \ \ \Rightarrow\ \ \ sinx=- (1)/(2)\n\n \Rightarrow\ \ \ x_1=( \pi + ( \pi )/(6) )+2k \pi ,\ \ \ \ \ \ x_2=( - ( \pi )/(6) )+2k \pi,\ \ \ \ \ \ k\in I\n\n.\ \ \ \ \ \ x_1=(7 \pi )/(6) +2k \pi ,\ \ \ \ \ \ \ \ \ \ \ \ x_2=-( \pi )/(6) +2k \pi,\ \ \ \ \ \ \ \ \ k\in I\n\nAns.\ x=-( \pi )/(6) +2k \pi\ \ \ or\ \ \ x= ( \pi )/(2) +2k \pi\ \ \ or\ \ \ x=(7 \pi )/(6) +2k \pi,\ \ \ k\in I$

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Magda sold her car for $1,900. This was $300 less than twice the original purchase price. What was the original price of Magda's car? Let p represent the original price of the car.A .2p - 300 = 1,900; p = 1,100 B .300p = 1,900 + 2; p = 634 C .300 - 2p = 1,900; p = 800 D .2p = 1,900 - 300; p = 800