Terry the plumber charges a base fee of $40 for each visit to someone's home plus $25 each hour forlabor. When Kathy received her bill after he came to fix a leak in her sink, the total charge was $152.50.
How many hours did Terry work on Kathy's sink?

Answers

Answer 1
Answer:

Answer:

4.5 hours

Step-by-step explanation:


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What is the angle supplementary to the angle measuring 165°12′?A. 75°12′ B. 180′ C. 14°48′ D. 60′
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An object with a mass of 6.3 kg has a mass of 7.1newtons applied to it, what is the resulting acceleration of the object

Answers

Since, a = F (net) / m (net)
Therefore a = 7.1 / 6.3 = 1.13 m/sec^2

5 students participated in a push-up competition.The amount of push-ups each student completed is listed: 12, 7, 10, 11,5
What was the mean number of push-ups?

Answers

Answer: 9

Step-by-step explanation:

Formula : Mean = \frac{\text{Sum of observations}}{\text{Number of observaions}}

Given: 5 students participated in a push-up competition.

The amount of push-ups each student completed is listed: 12, 7, 10, 11,5.

Mean = (12+7+10+77+5)/(5)

=(45)/(5)=9

Hence, the mean number of push-ups = 9

What is the exact value of sec(-405degress)?? ...?

Answers

sec= 1/(cos), you can add or subtract 360 degrees from any angle measurement without changing the value of any of the trig functions i.e. 405 degrees= 405-360=45. cos of 45 is sqrt(2)/2 so sec405= 2/sqrroot2

store uses a selling price based markup of 40% and item cost to store a 300 what selling price with the store set for the item A 335 B 400 C 435 D 500

Answers

Hi There! :)

Store uses a selling price based markup of 40% and item cost to store a 300 what selling price with the store set for the item A 335 B 400 C 435 D 500

400! :)

There are 46 students in an elementary statistics class. On the basis of years of experience, the instructor knows that the time needed to grade a randomly chosen first examination paper is a random variable with an expected value of 5 min and a standard deviation of 4 min. (Round your answers to four decimal places.)(a) If grading times are independent and the instructor begins grading at 6:50 P.M. and grades continuously, what is the (approximate) probability that he is through grading before the 11:00 P.M. TV news begins?(b) If the sports report begins at 11:10, what is the probability that he misses part of the report if he waits until grading is done before turning on the TV?

Answers

Answer:

a) P ( T < 250 mins ) = 0.7695

b) P ( T > 260 mins ) = 0.1344

Step-by-step explanation:

- The RV from a sample has the following parameters that are mean = 5 mins, and standard deviation s = 4 mins.

- The entire population has n = 46 students.

- We will first compute the population mean u and population standard deviation σ as follows:

                            u = n*mean

                            u = 46*5 = 230 mins

                            σ = sqt ( n ) * s

                            σ = sqt ( 46 ) * 4

                            σ = 27.129 mins

- Approximating that the time taken T to grade the population of entire class follows a normal distribution with parameters u and σ as follows:

                            T~ N ( 230 , 27.129 )

Find:

- If grading times are independent and the instructor begins grading at 6:50 P.M. and grades continuously, what is the (approximate) probability that he is through grading before the 11:00 P.M. TV news begins?

- The total time till 6:50 PM to 11:00 PM is ( 4 hr and 10 mins ) = 250 mins.

- We will compute the Z-value as follows:

                        Z = ( 250 - 230 ) / 27.129

                        Z = 0.7372

- Then use the Z-Tables and determine the probability:

                        P ( T < 250 mins ) = P ( Z < 0.7372 )

                        P ( T < 250 mins ) = 0.7695

Find:

-  If the sports report begins at 11:10, what is the probability that he misses part of the report if he waits until grading is done before turning on the TV?

- For the teacher to miss the sports report he must take more time than 6:50 PM to 11:10 P.M.

- The total time till 6:50 PM to 11:10 PM is ( 4 hr and 20 mins ) = 260 mins.

- We will compute the Z-value as follows:

                        Z = ( 260 - 230 ) / 27.129

                        Z = 1.10582

- Then use the Z-Tables and determine the probability:

                        P ( T > 260 mins ) = P ( Z > 1.10582 )

                        P ( T > 260 mins ) = 0.1344

Jen ran 9 miles in 117 minutes , if her speed remained the same throughout the run , what was her pace?

Answers

Jen's pace is approximately 13 minutes per mile.

To calculate Jen's pace, we need to determine the time it took her to run 1 mile.

Jen ran 9 miles in 117 minutes, so we divide the total time by the number of miles:

Pace = Total time / Number of miles

Pace = 117 minutes / 9 miles

To simplify the pace, we can convert 117 minutes into hours by dividing it by 60:

Pace = (117 minutes / 60) hours / 9 miles

Pace ≈ 1.95 hours / 9 miles

Now, to find the pace in minutes per mile, we can convert 1.95 hours to minutes by multiplying it by 60:

Pace ≈ (1.95 hours × 60) minutes / 9 miles

Pace ≈ 117 minutes / 9 miles

Therefore, Jen's pace is approximately 13 minutes per mile.

Learn more about time here

brainly.com/question/8644408

#SPJ2

117 ÷ 9 = 13

Hope this helps!