Please simplify

5×3−8÷2×3

Answers

Answer 1
Answer: The answer would be 3! You can find this using PEMDAs, aka order of operations. Hope this helps!!
Answer 2
Answer:

Answer:

Use PEMDAS

Step-by-step explanation:

answer is 7/6 i think

i am not 100% sure


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Ou have learned that given a sample of size n from a normal distribution, the CL=95% confidence interval for the mean can be calculated by Sample mean +/- z((1-CL)/2)*Sample std/sqrt(n). Where z((1-cl)/2)=z(.025) is the z score.a. help(qnorm) function. Use qnorm(1-.025) to find z(.025).b. Create a vector x by generating n=50 numbers from N(mean=30,sd=2) distribution. Calculate the confidence interval from this data using the CI formula. Check whether the interval covers the true mean=30 or not.c. Repeat the above experiments for 200 times to obtain 200 such intervals. Calculate the percentage of intervals that cover the true mean=30. This is the empirical coverage probability. In theory, it should be very close to your CL.d. Write a function using CL as an input argument, and the percentage calculated from question c as an output. Use this function to create a 5 by 2 matrix with one column showing the theoretical CL and the other showing the empirical coverage probability, for CL=.8, .85, .9, .95,.99.
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Equation4(5x–9)=−2(x+7)
# x = 1
Explanation
Write the equation.
Add 2x to each side.
30
:: Multiply on each side.
:: 22x = 22
:: 22x-36= -14
Add 36 to each side.
Reason
Given
Distributive Property
Addition Property of Equality
Addition Property of Equality
Division Property of Equality
:: 20x - 36 = -2x - 14
:: Divide each side by 22.

Answers

After dividing each side by 22, you'll find that x = 1. Great job!

What is the range of the following data values? 47, 28, 92, 34, 83

Answers

First, put all of the numbers in a list ranking from high to low (or low to high) and subtract the highest and lowest values.

92 - 28 = 64
The range is 64

Hope this helps!!

Answer:

64

Step-by-step explanation:

Expand and simplify
4a^2(b^2-c)+2ab(ab-c)-ac(a+2b)

Answers

4a^2(b^2-c)+2ab(ab-c)-ac(a+2b)\n-----------------------\nuse\ distributive\ property:a(b-c)=ab+ac\n-----------------------\n=4a^2b^2-4a^2c+2a^2b^2-2abc-a^2c-2abc\n=(4a^2b^2+2a^2b^2)+(-4a^2c-a^2c)+(-2abc-2abc)\n\n=\boxed{6a^2b^2-5a^2c-4abc}
4a²(b² - c) + 2ab(ab - c) - ac(a + 2b)
4a²(b²) - 4a²(c) + 2ab(ab) - 2ab(c) - ac(a) - ac(2b)
4a²b² - 4a²c + 2a²b² - 2abc - a²c - 2abc
4a²b² + 2a²b² - 4a²c - a²c - 2abc - 2abc
6a²b² - 5a²c - 4abc

Find all sets of four consecutive integers whose sum is between 95 and 105

Answers

Hello,
Let n-2,n-1,n,n+1 the four consecutive integers.

s=n-2+n-1+n+n+1=4n-2
==> 95<=4n-2<=105
==> 97<=4n<=107
==>24.25<=n<=26.75

n= 25 ou n=26
if n=25, s=23+24+25+26=98
if n=26, s=24+25+26+27=102

2 solutions: {23,24,25,26} and {24,25,26,27}


Use the diagram to find the value of x

Answers

um can i see the diagram plz :)

2+5*___=33
Figure out the blank.

You can use exponents

Answers

Answer:

6.2

Step-by-step explanation:

2+5*x=33

5*x=33-2

5*x=31

X=31/5

X=6.2

6.2 should be the answer