When a car travels around a curve in the road what helps to keep the car driving in a curved path?
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Centripetal force acts on an object moving in a circular path and the force is directed towards the center of the circular path.
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A sample of gas at 300 K has a volume of 2.0 liters. At what temperature will the volume decrease to 1.0 liter if the pressure is kept constant?
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I will assume that you are 1.8 m tall, so the distance the bagel falls before it hits you on the head is
300.5 m - 1.8 m = 298.7 m
One of the important equations relating distance and acceleration is
s = v₀ +½at², where
s = distance,
v₀ = initial velocity,
a = acceleration, and
t = time.
I also assume that the person at the top of the tower didn't throw the bagel down at you, so v₀ = 0.
a is the acceleration due to gravity, which is 9.8099 m·s⁻² in Paris.
s = v₀ + ½ at²
298.7 m = 0 + ½ × 9.8099 m·s⁻² × t²
298.7 = 4.9050 t² s⁻²
t² =
t =
The time taken for the croissant to hit you on the head assuming you are 1.5 m tall is 7.73 s
Considering the question given above, your height was not stated.
Let your height be 1.5 m
Thus, the height of the Eiffel Tower to your head will be:
Height (h) = (Total height of tower) – (Your assumed height)
Total height of tower = 300.5 m
Your assumed height = 1.5 m
Height (h) = 300.5 – 1.5
Height (h) = 299 m
Finally, we shall determine the time taken for the croissant to hit you on the head.
Height (h) = 299 m
Acceleration due to gravity (g) = 10 m/s²
Time (t) =?
H = ½gt²
299 = ½ × 10 × t²
299 = 5 × t²
Divide both side by 5
Take the square root of both side
t = 7.73 s
Therefore, the time taken for the croissant to hit you on the head assuming you are 1.5 m tall is 7.73 s
Learn more: brainly.com/question/19168584
b. The nucleus has a negative charge
c. The atom has a dense nucleus
d. Alpha particles can pass through a thin sheet of gold foil
e. All of the above are correct regarding the gold foil experiment
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It was not a conclusion because it is neutral. It is not positive nor negative.
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Final answer:
The combined mass of oxygen and mercury obtained from the thermal decomposition of 20g of mercury(II) oxide would also be 20g. The exact division between oxygen and mercury would depend on the stoichiometry of the reaction.
Explanation:
The subject here is the thermal decomposition of mercury(II) oxide (HgO). When this compound is heated, it decomposes into mercury and oxygen. The mass principle in chemistry, also known as the Conservation of Mass, states that the combined mass of the products (oxygen and mercury in this case) should be equal to the mass of the reactant (mercury oxide). Therefore, if you heat 20g of mercury(II) oxide, you would obtain a combined mass of 20g of oxygen and mercury. The exact mass of oxygen and mercury would depend on the atomic mass and stoichiometry of the decomposition reaction. For example, if the reaction were 2HgO --> 2Hg + O2, you would get twice as much mercury mass as oxygen, due to the nature of the balanced equation.
Learn more about Thermal Decomposition here:
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Answer:
54.2 g of Ca(OH)₂
Explanation:
Let's determine the moles of solute, we should need
Molarity . volume (L) = moles
Let's convert 600 mL to L
600 mL/ 1000 = 0.6L
1.22 mol/L . 0.6L = 0.732 moles
Finally we must convert the moles to mass ( moles . molar mass)
0.732 mol . 74.08 g/mol = 54.2 g
Answer: 54.2 g Ca(OH)2
Explanation: Molarity is moles of solute / L solution
First convert mL to L
600 mL x 1L / 1000 mL = 0.6 L
Find moles of Ca(OH)2
n= M x L
= 1.22 M x 0.6 L
= 0.732 moles Ca(OH)2
Convert moles to mass using its molar mass of Ca( OH)2 = 74 g
0.732 moles Ca(OH)2 X 74 g Ca(OH)2 / 1 mole Ca(OH)2
= 54.2 g Ca(OH)2