PHYSICS HIGH SCHOOL

A pond is a small body of water that is too shallow for sunlight to permeate, and a lake is a large body of water that is deep enough for sunlight to permeate

Answers

Answer 1

Answer: False, the technical distinction between a pond and a lake has not been universally standardized.

Answer 2

Answer:

FALSE

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Related Questions

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The Lamborghini Diablo sports car can accelerate from 0.0 km/hr to 99.2 km/hr in 4.0 seconds. What is the acceleration of this car? Give your answer in units of kilometers per hour/sec.

Answers

The Lamborghini Diablo sports car can accelerate from 0.0 km/hr to 99.2 km/hr in 4.0 seconds. What is the acceleration of this car? Give your answer in units of kilometers per hour/sec. To find the acceleration of the car we have to
1. First determine the suitable formula for this word problem. Which is a. A=vf-vi/t

Given are: Vf=99.2 km/h Vi= 0.0 km/h T= 4.0sec

Solution:
A= 99.2 km/h – 0.0km/h / 4.0 sec
A = 99.2 km/h / 4 sec
A = 2.8 km/h/sec

Answer:

24.8 km per second

Explanation:

PLZ HELP!!!75
What is the identity of the atom shown?
A) fluorine
B) neon
C) nitrogen
D) potassium

Answers

9 is the # of protons with is also the # you use to identify the element. It would be A, fluorine.

A fluorine is the answer.

The amount of pressure in a gas is measured in pascals. TRUE or FALSE.

Answers

True Pascals Is Used To measure Amount Of Pressure In A Gas

(Any unit of force) divided by (any unit of area) is a unit of pressure.

1 pascal = 1 newton / 1 square meter

So a pascal is an acceptable unit of pressure, and the statement
is true. It's very popular worldwide for this purpose, but it's by no
means the only one used everywhere. We also still see measurements
in units of pounds per square inch, Torr, millibars, atmospheres, etc.

suppose that you look into a photometer's eyepiece and the fluorescent disks appear to be equal in intensity. If the distance between the photometer to lamp 1 is 400mm, the distance between the photometer to lamp 2 is 200 mm, and the intensity of lamp 2 is known to be 15 candelas, what is the intensity to lamp 1?

Answers

Use the Inverse square law, Intensity (I) of a light is inversely proportional to the square of the distance(d).

I=1/(d*d)

Let Intensity for lamp 1 is L1 distance be D1 so on, L2 D2 for Intensity for lamp 2 and its distance.

L1/L2=(D2*D2)/(D1*D1)

L1/15=(200*200)/(400*400)
L1=15*0.25
L1=3.75 candela

The purpose of a fuse or circuit breaker is _____.to speed up the current
to slow down the current
to stop current that is flowing too fast
to stop current that is flowing too slow